Laravel 5.8 get tables belonging to a user - php

Question

I am listing all tables in the DBthat are prefixed with the user->id + _ (eg: 2_my_table) like so:
$account = Auth()->user();
$tables = DB::select("SHOW TABLES LIKE '" . $account->id . "_%'");
This works and returns an array like this:
array:1 [▼
0 => {#577 ▼
+"Tables_in_mydb (2_%)": "2_country_list"
}
]
Why does it add the (2_%) search pattern to the Tables_in_mydb property?
This causes issues later when try and describe the tables like this:
if (count($tables)) {
foreach ($tables as $table) {
$table->columns = DB::select('describe '.$table->Tables_in_mydb);
$table->rows = DB::select('SELECT COUNT(*) AS count FROM '.$table->Tables_in_mydb);
}
}

Answer 1

Fixed like this. But still do not understand the original issue.
$tables = collect(DB::select('show tables'))->filter(function ($val) use (&$account) {
foreach ($val as $key => $tbl) {
$tbl_prefix = $account->id . "_";
$tbl_prefix_length = strlen($tbl_prefix);
if (substr($tbl, 0, $tbl_prefix_length) == $tbl_prefix) {
return $tbl;
}
}
});

Answer 2

You might have to go about it the long way.
By using get_object_vars, you can get the object values into an array. Then use array_values to get just the values:
$table_name_arr = array_values(get_object_vars($table));
This will provide with an array (0 => '2_country_list'), which you can easily get with $table_name_arr[0]
For a one-liner, use
$table_name = array_values(get_object_vars($table))[0];