Using PHP Foreach with 3 Arrays - php

Question

I'm getting data from a site as you can see in the code below. Is it possible to use 3 arrays in a single foreach loop?
I've tried too many code snippets, but I haven't found the solution.
This is my normal code:
<?php
$i = 0;
$url = file_get_contents("xxx");
$display = '#{"__typename":"GraphImage","id":"(.*?)","edge_media_to_caption":{"edges":\[{"node":{"text":"(.*?)"}}]},"shortcode":"(.*?)","edge_media_to_comment":{"count":(.*?)},"comments_disabled":(.*?),"taken_at_timestamp":(.*?),"dimensions":{"height":(.*?),"width":(.*?)},"display_url":"(.*?)","edge_liked_by":{"count":(.*?)},"edge_media_preview_like":{"count":(.*?)},"location":(.*?),"gating_info":(.*?),"media_preview":"(.*?)","owner":{"id":"(.*?)","username":"(.*?)"}#i';
preg_match_all($display, $url, $dop);
foreach ($dop[1] as $displayop1) {
echo $displayop1."<p>";
}
foreach ($dop[9] as $displayop2) {
echo $displayop2."<p>";
}
foreach ($dop[15] as $displayop3) {
$i++;
if($i == 2) {break;}
echo $displayop3."<p>";
}
I've tried.
<?php
foreach ($dop[1] as $displayop1) {
foreach ($dop[9] as $displayop2) {
foreach ($dop[15] as $displayop3) {
echo $displayop1 . "<p>";
echo $displayop2 . "<p>";
$i++;
if ($i == 2) {
break;
}
echo $displayop3 . "<p>";
}
}
}
?>
<?php
foreach (array_combine($dop[1], $dop[9], $dop[15]) as $dop1 => $dop2 => $dop3) {
echo $dop1.$dop2.$dop3;
}
?>
These codes didn't work.
Can someone help me do this? I searched the solution a lot, but I couldn't find any information. I didn't know exactly how to search on the internet because my English isn't very good, thank you.

Answer 1

Closest option I see to a single loop is 2:
for($i=1; $i < 15; $i++) {
//you can do a if statement here if you need 1 9 and 15 respectivley
foreach ($dop[$i] as $displayop) {
}
}