I'm trying to add some Javascript coming from Google for Ad Conversions on the thank you page. So this script should only appear on one page. Trying to use an if statement in PHP to echo the code but running into errors. This is what I currently have (with the Google ID replaced with something generic):
<?php if ( is_page( 'thankyou' )) {
echo '<script>';
echo 'gtag('event', 'conversion', {'send_to': 'AW-12345678901234567890123456'});'
echo '</script>';
?>
The first and third echo's are fine but the middle one is not. What might be the proper fix?
Your second echo line breaks your string.
You have 2 options to fix this:
1. Change the inner quotes to double quotes
echo 'gtag("event", "conversion", {"send_to": "AW-12345678901234567890123456"});';
2. Break out of the quotes.
You can use back slashes to not break out of your main string.
echo 'gtag(\'event\', \'conversion\', {\'send_to\': \'AW-12345678901234567890123456\'});';
I have also noticed on the second echo you were missing a semi colon.
Source: PHP-Strings
You need to escape the single quotes in the brackets of gtag().
Try echo 'gtag(\'event\', \'conversion\', {\'send_to\': \'AW-12345678901234567890123456\'});' instead.
Related
The following text link works fine when I place it directly in my html:
Click here to <?php echo $showOrHideText; ?> the suggested sequence of lessons.
But I want to replace it with:
<?php echo $gradeNote; ?>
Elsewhere $gradeNote is assigned a string based on the grade of the student user. My question after many hours of searching and failing is how can I pass this snippet as a literal string, without PHP attempting to parse it and giving me a junk url? What am I doing wrong here:
$gradeNote = "Click here to <?php echo $showOrHideText; ?> the suggested sequence of lessons.";
You're running <?php and ?> tags inside of a PHP variable. As you're already dealing with PHP, these are unnecessary.
Although the quotation marks "" allow you to echo out evaluated variables, because you're also running a condition in this 'string', you'll want to extrapolate that out and simply store the result as a variable. I've called mine $show.
As such, you're simply looking for:
if($slcustom29 == 0) {
$show = 1;
}
else {
$show = 0;
}
$gradeNote = "Click here to $showOrHideText the suggested sequence of lessons.";
Remember to either escape the double-quotes in the <a href="">, or swap them for single-quotes.
This can be seen working here.
Hope this helps!
Try something like this.
$s = ($slcustom29 == 0) ? 1 : 0;
$gradeNote = "Click here to {$showOrHideText} the suggested sequence of lessons.";
Any string with double quotes "" can have a variable embedded, the {} are not necessary, but i always use them for cases like this where you are trying to embed a variable with no spaces around it, "$xabc" which will return a different result "{$x}ab"
the probelm is that you are trying to put php logic into the string. Notice you have an IF command within the string literal. start with a small or empty string, and concat onto it piece by piece, as opposed to doing it in one line.
then you can echo out the single variable link
I'm a beginner PHP programmer, and I was wondering what was wrong with my code.
Here is the small excerpt from the affected spot:
echo "<form action='?tab=4' name='toedit5' method='get'><input value='text' onblur='edit('toedit5')' /></form>";
In Chrome's Developer Tools, the form element totally disappears, and the edit('toedit5') becomes edit(' toedit5').
The edit() function doesn't execute.
Is there anything wrong with this one line of code? Otherwise it is outside code messing with it. Sorry I didn't include it, but I don't know what to include. If you need more information, please tell me.
Thanks.
You need to escape your quotes inside your quoted echo'd statement, like this:
<?php
echo "<form action='?tab=4' name='toedit5' method='get'>";
echo "<input value='text' onblur='edit(\"toedit5\")' />"; // escaped..!
echo "</form>";
?>
It helped me to think about it like this when I was starting out: how does your browser know if the second single quote in onblur='edit('toedit5')' is closing your onblur statement or opening up the parameter? In this example, your browser will pair up the first 2 quotes it sees and assign that to the onblur attribute, i.e.: onblur='edit(' only!
Update 1:
Using the code above, I inspected a quick PHP page I created in Chrome's developer tools and was able to see the following (form available for inspection):
You really should use the more standard double quotes around the HTML properties and use single quotes around your string, with escaped single quotes within the javascript method calls. Like this:
echo '<form action="?tab=4" name="toedit5" method="get"><input value="text" onblur="edit(\'toedit5\')" /></form>';
I have following code which displays the price in Magento.
<?php echo $this->getPriceHtml($_product); ?>
I have to put this code inside echo instead and I can't get it to work.
I am trying
echo "$this->getPriceHtml ($_product)";
It just displays () on the page.
I tried other combinations and I can't come up with anything else.
What am I doing wrong?
Using single quotes will prevent $vars to be interpreted:
echo '$this->getPriceHtml ($_product)';
Or escape the $ sign:
echo "\$this->getPriceHtml (\$_product)";
http://php.net/manual/en/language.types.string.php
Or if by echo-ing you mean that you want to get something like
The price is 123.00
then do:
echo "The price is {$this->getPriceHtml($_product)}";
or even :
echo sprintf("The price is %s", $this->getPriceHtml($_product));
why not you are using this ?
$_product->getFinalPrice() or
if you want in formatted order then why you are not using this
number_format($pr->getPrice(), 2)
and if you want price with currency format then you can use this also
Mage::helper('core')->currency($pr->getPrice());
Hope it will help you.
:)
have a question about a php echoing script that has a link to a javascript with some variables. I need to know the format for the echo so it will work properly. Could anyone shed any light on this? My code is posted below
echo "<a href='javascript: toggle('variable1', 'variable2')'><label1 for='nameEditor'>Manage</label1></a>";
Now when you hover over the link it just shows javascript:toggle( Now I have tried multiple things and I still cant get it to work. Anyone have any suggestions?
Assuming variable1 and variable2 are the PHP bits you want inserted into the javascript, then
echo "<a href='javascript: toggle('$variable1', '$variable2')'><label1 for='nameEditor'>Manage</label1></a>";
However, be aware that if either of those variables contain Javascript metacharacters, such as a single quote, you'll be breaking the script with a syntax error (think of it as the same situation as SQL injection).
To be sure that the variable's contents become legal Javascript, you'd want to do something like:
<script type="text/javascript">
var variable1 = <?php echo json_encode($variable1); ?>;
var variable2 = <?php echo json_encode($variable2); ?>
</script>
...
try like this:
echo "<label1 for='nameEditor'>Manage</label1>";
you have to escape \ quotes
It's because you're mixing your quotes that the browser see. Do this:
echo "<label1 for='nameEditor'>Manage</label1>";
If you escape the double quotes (\"), you'll be fine. The browser itself is seeing '''' (all single quotes), so you need to retain "''" (double,single,single,double) in your html element attribute, irregardless of PHP (except for the escaping).
I barely know how to use PHP and I can't seem to make my code show an image if a condition proves true. This is the code:
<?php
$search=get_search_query();
$first=$search[0];
if ($first=="#"){
}
?>
I tried writing this thinking it would work and it didn't:
echo "<html>";
echo "<img src='http://chusmix.com/Imagenes/grupos/lujan.jpg'>";
Also I tried a code I found which started with the function: header() but it caused a tremendously long error, which said something like header already defined.
Thanks
You have used 'double quotes' incorrectly in the echo statement.
Try the following:
echo "<img src='http://chusmix.com/Imagenes/grupos/lujan.jpg' alt='Preview not available' />"
Regards,
Mahendra Liya.
You should var_dump($first) to know what it contains
check if the condition is really getting true
and also put single quote inside the double quote.
if ($first=="#"){
echo 'yes it is true';
echo "<img src='http://chusmix.com/Imagenes/grupos/lujan.jpg'>";
}
close the img tag
The part of the query string starting with # (so-called "hash") is not being sent to the server. That is, if your page is called like myblog.com/foo?bar=baz#quux, you php script will only receive myblog.com/foo?bar=baz. You need javascript if you want to handle urls with hashes.