Get total amount of hours from 2 variables - php

Question

Here is my code:
$time = "20:58:05";
$time2 = "10:40:00";
$secs = strtotime($time2)-strtotime("00:00:00");
$result = date("H:i:s",strtotime($time)+$secs);
echo $result;
The output of the above code is - 07:38:05
i want it to display like this - 31:38:05. How can i achieve this?

Answer 1

Convert both times to seconds, add them, and then calculate the hours, minutes, and seconds yourself.
$time = "20:58:05";
$time2 = "10:40:00";
$secs = strtotime($time)-strtotime("00:00:00");
$secs2 = strtotime($time2)-strtotime("00:00:00");
$total = $secs + $secs2;
$hours = floor($total/3600);
$mins = floor(($total % 3600) / 60);
$secs = $total % 60;
echo sprintf("%d:%02d:%02d", $hours, $mins, $secs);

Answer 2

The solution of Barmar works when adding hours that are below 24:00:00, but when you add 2 variable with each variable exceeds 24:00:00 it gives a wrong output. For example:
$time = "20:58:05";
$time2 = "30:40:00";
$secs = strtotime($time)-strtotime("00:00:00");
$secs2 = strtotime($time2)-strtotime("00:00:00");
$total = $secs + $secs2;
$hours = floor($total/3600);
$mins = floor(($total % 3600) / 60);
$secs = $total % 60;
echo sprintf("%d:%02d:%02d", $hours, $mins, $secs);
output of the above code: -431348:-2:-55
Here is a code that works even if the data of the variables exceeds 24:00:00:
function sum_the_time($time1, $time2) {
$times = array($time1, $time2);
$seconds = 0;
foreach ($times as $time)
{
list($hour,$minute,$second) = explode(':', $time);
$seconds += $hour*3600;
$seconds += $minute*60;
$seconds += $second;
}
$hours = floor($seconds/3600);
$seconds -= $hours*3600;
$minutes = floor($seconds/60);
$seconds -= $minutes*60;
if($seconds < 9)
{
$seconds = "0".$seconds;
}
if($minutes < 9)
{
$minutes = "0".$minutes;
}
if($hours < 9)
{
$hours = "0".$hours;
}
return "{$hours}:{$minutes}:{$seconds}";
}
i found this code here