multidimensional array counting according to the value - php

Question

$feetypes=[
[30,35,50],
[30,35],
[30,50],
[30,34]
];
i have this code, want to count as per there value like count 30*4, 35*2, 50*2 & 34*1.
i have already tried:
$counts = array();
foreach ($array as $key=>$subarr) {
// Add to the current group count if it exists
if (isset($counts[$subarr['group']]) {
$counts[$subarr['group']]++;
}
// or initialize to 1 if it doesn't exist
else $counts[$subarr['group']] = 1;
// Or the ternary one-liner version
// instead of the preceding if/else block
$counts[$subarr['group']] = isset($counts[$subarr['group']]) ? $counts[$subarr['group']]++ : 1;
}
but my problem still there

Answer 1

You can merge all the inner arrays into one with array_merge and then use array_count_values to get the counts.
$counts = array_count_values(array_merge(...$feetypes));

Answer 2

Merge all the subarray into a single array and apply array_count_values function to get the result
function merageAll($arr) {
$flatArray = array();
foreach($arr as $element) {
if (is_array($element)) {
$flatArray = array_merge($flatArray, merageAll($element));
} else {
$flatArray[] = $element;
}
}
return $flatArray;
}
$res = array_count_values(merageAll($feetypes));
Result
Array
(
[30] => 4
[35] => 2
[50] => 2
[34] => 1
)
function merageAll work if there are values and sub arrays in the array.
Working DEMO LINK

Answer 3

I used recursion in case values are more than two levels deep. note the $count variable is passed by reference to the function due to recursion.
<?php
$feetypes=[
[30,35,50],
[30,35],
[30,50],
[30,34]
];
$counts = array();
function countValues($arr, &$count) {
foreach($arr as $subval) {
if(is_array($subval)) {
countValues($subval,$count);
} else {
if(isset($count[$subval])) {
$count[$subval] += 1;
} else {
$count[$subval] = 1;
}
}
}
}
countValues($feetypes,$counts);
print_r($counts);