<?php
$uname = $_POST["username"]$uname =
stripslashes(trim($uname));
$pward = $_POST["password"];
$pward = stripcslashes(trim($pward));
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "index_data";
$conn = new mysqli($servername, $username,
$password, $dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM 00_user_details WHERE
username = '$uname' ";
$result = mysqli_query($conn, $sql);
$rows = mysqli_fetch_row($result);
echo "_".$rows["first_name"]."_";
?>
I am a bigger.
It's my code but it outputs nothing .
Any if you respected sir/ma'm help me kindly...
Please put semicolon after $_POST["username"] and use mysqli_fetch_assoc in place of mysqli_fetch_row.
mysqli_fetch_assoc return a row as an associative array where the column names will be the keys storing corresponding value.
Please find actual code as below:
$uname = $_POST["username"];
$uname = stripslashes(trim($uname));
$pward = $_POST["password"];
$pward = stripcslashes(trim($pward));
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "index_data";
$conn = new mysqli($servername, $username,$password, $dbname);
if ($conn->connect_error)
{
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM 00_user_details WHERE username = '$uname'";
$result = mysqli_query($conn, $sql);
$rows = mysqli_fetch_assoc($result);
echo "_".$rows["first_name"]."_";
Related
I have a test MySQL with a field which is unique as e-mailadres. Now I want to check before adding a record if the email already exists. I have the following code
<?php
$servername = "localhost";
$username = "xxxxxx";
$password = "xxxxxx";
$dbname = "xxxxxxx";
$servername = "localhost";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
//test met voorbeeld
$emailtest="adres#me.com ";
$sql = "SELECT * FROM salonkeuze WHERE emailadres='$emailtest' ";
$data = mysqli_query($connect, $sql);
$row = mysqli_fetch_assoc($data);
$id = $row['voorkeur_id'];
Echo $id;
?>
When I use an email address which is in de table. I don’t get any output. What do I wrong?
Here $emailtest="adres#me.com "; you can extra space after com, try to remove it -> $emailtest="adres#me.com";
Firstly, you use wrong variable in this line:
$data = mysqli_query($connect, $sql);
Correct:
$data = mysqli_query($conn, $sql);
And it's optional, but it will be good, if you use trim() function for your $email. Because if your data comes from inputs and if $email have spaces, you can't show correct results:
$emailtest = "adres#me.com ";
$emailtest = trim($emailtest);
$sql = "SELECT * FROM salonkeuze WHERE emailadres='$emailtest' ";
I want to fetch time column from mysql database and to compare with current time.
It should execute only if it matches with the current time.
Please tell me a MySql query or php code to do this.
I am new to php.
Try This:
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$today = date("h:i a")
$sql = "SELECT * FROM Table_name WHERE SUBSTRING_INDEX(time, ' ', 2) = '".$today."'";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// execute you code
} else {
}
$conn->close();
?>
Try this: Updated Code
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$today = date("h:i a")
$sql = "SELECT * FROM Table_name WHERE time = $today";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// execute you code
} else {
}
$conn->close();
?>
I would need some help with showing data that I have on my database but I can't seen to be able to.`
$servername = "servername";
$username = "username";
$password = "password";
$dbname = "dbname";
$connect = mysqli_connect($servername, $username, $password, $dbname) or die ("connection failed");
//Query
$query = "SELECT * FROM 'Students'";
mysqli_master_query($dbname, $query) or die ("Error while Query");
$result = mysqli_master_query($dbname, $query);
$row = mysql_fetch_array($result);
while ($row = mysql_fetch_array($result)) {
echo "<p>".$row['Name']."</p>";
};
mysql_close($connect);
?>`
I am pretty new to this so I could have missed something simple. Any help appreciated.
Below is a sample code of the normal procedure to connect to a database and to select data from it. Please follow this type of coding since MySQL is now deprecated and MySQLi is used.
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "SELECT id, firstname, lastname FROM MyGuests";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
echo "id: " . $row["id"]. " - Name: " . $row["firstname"]. " " . $row["lastname"]. "<br>";
}
} else {
echo "0 results";
}
mysqli_close($conn);
?>
For further reference check out http://php.net/manual/en/book.mysqli.php and also https://www.w3schools.com/php/php_mysql_insert.asp
Hi guys im trying to check if a value(token) inside my MYSQL DB exists.
Main informations:
Table: Tokens
Column: Token
My latest try:
<?php
// DATABASE STUFF
$servername = "localhost";
$username = "userhere";
$password = "passhere";
$dbname = "zwinky";
$token = $_GET['a'];
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$result = mysql_query("SELECT * FROM Tokens WHERE Token = '$token'");
$matchFound = mysql_num_rows($result) > 0 ? 'yes' : 'no';
echo $matchFound;
?>
Does anyone have a idea?
If you are using mysqli_* then you can't use mysql_*
Try this one
<?php
// DATABASE STUFF
$servername = "localhost";
$username = "userhere";
$password = "passhere";
$dbname = "zwinky";
$token = $_GET['a'];
$con=mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (mysqli_connect_errno()){
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
// Perform queries
$result = mysqli_query($con,"SELECT * FROM Tokens WHERE Token = '$token'");
$matchFound = mysqli_num_rows($result) > 0 ? 'yes' : 'no';
echo $matchFound;
?>
I have one number in a mysql database
This is my code:
$servername = "xxxxx";
$username = "xxxxxx";
$password = "xxxxxx";
$dbname = "xxxxxx";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql1 = "SELECT date FROM test";
$result1 = $conn->query($sql1);
$res1 = mysqli_fetch_assoc($result1);
echo $res1['date'];
I want to load that number into variable and count with that variable. After that i will store in same the db and table on the same place
$numvar = $res1['date'];
There yah go.