Merge first array particular key and value into second array - php

Question

I have 2 array
$arr1 = Array (
[0] => Array ( [customer_id] => 1 [Expire] => 2019-05-14 [paid] => 1 )
[1] => Array ( [customer_id] => 2 [Expire] => 2019-06-20 [paid] => 0 ))
and
$arr2 = Array (
[0] => Array ( [id] => 3943 [customer_id] => 1 [Expire] => 2019-05-14 )
[1] => Array ( [id] => 3944 [customer_id] => 1[Expire] => 2019-05-14 )
[2] => Array ( [id] => 4713 [customer_id] => 2 [Expire] => 2019-06-20 )
)
and try to put first array key and value [paid]=>1 or 0 in second array if customer id and expire match like
Array (
[0] => Array ( [id] => 3943 [customer_id] => 1 [Expire] => 2019-05-14 [paid] => 1)
[1] => Array ( [id] => 3944 [customer_id] => 1 [Expire] => 2019-05-14 [paid] => 1)
[2] => Array ( [id] => 4713 [customer_id] => 2 [Expire] => 2019-06-20 [paid] => 0)
)
I try to merge array in php but not get exact what i want. Is there any php function to do it?.

Answer 1

Loop your second array $arr2, and find the index of the first array $arr1 where the column customer_id is the same as in the current iteration of $arr2. array_search() returns that index, which we can then use to fetch the paid index of that array. Then we append it to our array $arr2, by doing $a['paid'] = $paid;.
Since we loop the array by reference (the & before $a in the loop), the changes we make to it, will be applied back to the original array.
foreach ($arr2 as &$a) {
$customerID = $a['customer_id']; // This customer ID
$arr1_key = array_search($customerID, array_column($arr1, 'customer_id')); // Find the index of this customerID in the first array
$paid = $arr1[$arr1_key]['paid']; // Find the paid value matching that customer ID
$a['paid'] = $paid;
}
Live demo at https://3v4l.org/Meqtu
Update
If you need it to match the ID as well as the expiration date, then use array_filter() to fetch the array-element within $arr1 that matches the date and the ID. Using reset(), we use the first element in that array.
foreach ($arr2 as &$a) {
// Find the sub-array of $arr1 that matches this array's date and ID
$arr1_match = array_filter($arr1, function($v) use ($a) {
return $v['customer_id'] == $a['customer_id'] && $v['Expire'] == $a['Expire'];
});
// Get the first element from the result
$paid = reset($arr1_match)['paid'];
// Append the paid-value to this array (done by reference)
$a['paid'] = $paid;
}
Live demo at https://3v4l.org/mov6d

Answer 2

sometimes things can be done in hard way:)
<?php
$arr1 = [
['customer_id' => 1, 'Expire' => '2019-05-14', 'paid' => 1],
['customer_id' => 2, 'Expire' => '2019-06-20', 'paid' => 0],
];
$arr2 = [
['id' => 3943, 'customer_id' => 1, 'Expire' => '2019-05-14'],
['id' => 3944, 'customer_id' => 1, 'Expire' => '2019-05-14'],
['id' => 3945, 'customer_id' => 2, 'Expire' => '2019-05-14'],
['id' => 4713, 'customer_id' => 2, 'Expire' => '2019-06-20'],
];
foreach ($arr2 as &$item2) {
foreach ($arr1 as $item1) {
if (
$item2['customer_id'] === $item1['customer_id']
&& $item2['Expire'] === $item1['Expire']
) {
$item2['paid'] = $item1['paid'];
break;
}
}
}
unset($item2);
var_dump($arr2);

Answer 3

If you cannot change the layout of the first array I think it will be best to first create an intermediate array that keeps a record of all expire dates for every customer.
The following implementation does not require you to use a nested loop.
<?php
$arr1 = [
['customer_id' => 1, 'Expire' => '2019-05-14', 'paid' => 1],
['customer_id' => 2, 'Expire' => '2019-06-20', 'paid' => 0],
];
$arr2 = [
['id' => 3943, 'customer_id' => 1, 'Expire' => '2019-05-14'],
['id' => 3944, 'customer_id' => 1, 'Expire' => '2019-05-14'],
['id' => 3945, 'customer_id' => 2, 'Expire' => '2019-05-14'],
['id' => 4713, 'customer_id' => 2, 'Expire' => '2019-06-20'],
];
// Create a list of all paid, expiry dates, keyed by customer_id
$payed = [];
foreach ($arr1 as $item) {
if (!isset($payed[$item['customer_id']])) {
$payed[$item['customer_id']] = [];
}
$payed[$item['customer_id']][] = $item['Expire'];
}
// Lookup the customer and expire date for every entry
$arr2 = array_map(function($item) use ($payed) {
$item['paid'] = in_array($item['Expire'], $payed[$item['customer_id']] ?? []);
return $item;
}, $arr2);
Result:
Array
(
[0] => Array
(
[id] => 3943
[customer_id] => 1
[Expire] => 2019-05-14
[paid] => 1
)
[1] => Array
(
[id] => 3944
[customer_id] => 1
[Expire] => 2019-05-14
[paid] => 1
)
[2] => Array
(
[id] => 3945
[customer_id] => 2
[Expire] => 2019-05-14
[paid] =>
)
[3] => Array
(
[id] => 4713
[customer_id] => 2
[Expire] => 2019-06-20
[paid] => 1
)
)
See demo

Answer 4

This can fix the issue :
$arr1 = array(
["customer_id"=>1,"Expire"=> "2019-05-14", "paid"=>1],
["customer_id"=>2,"Expire"=> "2019-06-20", "paid"=>0]
);
$arr2 = array(
["id"=>3943, "customer_id"=>1,"Expire"=> "2019-05-14"],
["id"=>3944,"customer_id"=>2,"Expire"=> "2019-06-20"],
["id"=>4713,"customer_id"=>1,"Expire"=> "2019-05-14"]
);
$result= array();
function getRowByCustomerID($id, $array){
foreach($array as $value){
if($value['customer_id'] ==$id){
return $value;
}
}
return null;
}
foreach($arr2 as $subarr){
$object = getRowByCustomerID($subarr['customer_id'],$arr1 );
if(!is_null($object)){
$object['id']=$subarr['id'];
$result[]= $object;
}
}
var_dump($result);
the output is similar to what you are looking for :
array(3) {
[0]=>
array(4) {
["customer_id"]=>
int(1)
["Expire"]=>
string(10) "2019-05-14"
["paid"]=>
int(1)
["id"]=>
int(3943)
}
[1]=>
array(4) {
["customer_id"]=>
int(2)
["Expire"]=>
string(10) "2019-06-20"
["paid"]=>
int(0)
["id"]=>
int(3944)
}
[2]=>
array(4) {
["customer_id"]=>
int(1)
["Expire"]=>
string(10) "2019-05-14"
["paid"]=>
int(1)
["id"]=>
int(4713)
}
}