How to Keep an array and dynamic Checkbox stays checked after submit? - php

Question

I have one dynamic checkbox (can be ++) that needs to stay checked after user submit.
I already tried some tricks like using a hidden input before my checkbox code in HTML. Now I stuck in doing an isset(_POST) and the checkbox didn't stay checked.
Here's my HTML:
<input type="hidden" name="hidden_name[]" id="hidden_name0">
<input type="checkbox" name ="name[]" id="name0">
<label for="name">Name</label>
--------UPDATE--------
And in my PHP file, here's the code:
$valueName = array();
if(isset($_POST["hidden_name"]))
{
foreach($_GET['hidden_name'] as $value)
{
array_push($valueName,$value);
}
}
That code doesn't work :/
How to make the checkbox stays checked after user check it and submit the form? What should I write in PHP? Do I really need a hidden input before my checkbox?

Answer 1

isset might be returning false since the submitted value is NULL. I suggest adding a value='1' on the hidden input field -- or are you updating that field with the corresponding checkbox value?
Alternatively, you have some other options:
Change the name for each dynamic checkbox to have an identifier.
<input type="checkbox" name="name-x" <?php echo isset( $_POST['name-x'] ) ? 'checked="checked"' : '' ?> />
Where x could be your dynamic ID. Notice the addition of the PHP code and using a ternary operator, you can check the checkbox if the $_POST['name-x'] is set.
Add a value to the checkbox.
<input type="checkbox" name="name[]" id="name0" value="name0" />
<input type="checkbox" name="name[]" id="name1" value="name1" />
<input type="checkbox" name="name[]" id="name2" value="name2" />
However, you need to match this value in your PHP code.
<?php
if ( isset( $_POST['name'] ) ) {
$values = array();
foreach( $_POST['name'] as $value ) {
array_push( $values, $value );
}
}
?>
Then you have to modify your checkbox again to have inline PHP.
<input type="checkbox" name="name[]" id="name0" value="name0" <?php echo in_array( "name0", $values ) ? 'checked="checked"' : '' ?> />
<input type="checkbox" name="name[]" id="name1" value="name1" <?php echo in_array( "name1", $values ) ? 'checked="checked"' : '' ?> />
<input type="checkbox" name="name[]" id="name2" value="name2" <?php echo in_array( "name2", $values ) ? 'checked="checked"' : '' ?> />
You can also create a function to display these inline codes to make it much cleaner. HTH!

Answer 2

i assume that you have a form that have some checkboxes and try to check which checkbox is checked. here is an example code
<form action="" method="post">
<label for="name">Name 1</label>
<input type="checkbox" name ="name[]" value="name1">
<label for="name">Name 2</label>
<input type="checkbox" name ="name[]" value="name2">
<label for="name">Name 3</label>
<input type="checkbox" name ="name[]" value="name3">
<label for="name">Name 4</label>
<input type="checkbox" name ="name[]" value="name4">
<button type="submit" name="submit">Submit</button>
</form>
and the php code
<?php
if(isset($_POST["submit"])){
$valueName = array();
foreach($_POST['name'] as $value){
array_push($valueName,$value);
print_r($valueName);
}
?>