Foreach through elements retain the last value of the element - php

Question

I would like to get the value of what I have echoed in the value of an HTML element but I used a foreach so it retains only the last value of the last loop. I would update the reqStatus depending on its ID through a post method to pass the variables.
HTML w/ foreach:
<form method = "POST" action="">
<table>
<th> Request ID:</th>
<th> Request Status:</th>
<?php
$requests = new OrderRequests();
$requests->getAllOrders();
foreach($requests->orderList as $oList){?>
<tr>
<td>
<input type="hidden" name="reqId" value="<?php echo $oList["request_id"];?>"><?php echo $oList["request_id"];?>
</td>
<td>
<input type="hidden" name ="reqStatus" value="<?php echo $oList["request_status"];?> "><?php echo $oList["request_status"];?>
</td>
<?php if($oList["request_status"]=="Delivered"){?>
<input type="hidden" id="reqIDUpdate" name="reqIDUpdate" value ="<?php echo $oList["request_id"];?>">
<td>
<input type="submit" class="button" value="Confirm Delivery">
</td>
<?php }}?>
</tr>
</table>
</form>
After POST:
if (!empty($_POST["reqIDUpdate"])){
$requestIDUpdate = $_POST["reqIDUpdate"];
global $connection;
$sql = "UPDATE order_request SET request_status = 'Received Delivery'
WHERE request_id = {$requestIDUpdate} ";
mysqli_query($connection, $sql);
unset($_POST["reqIDUpdate"]);
}

Answer 1

Though you are echoing unique values, the value that gets assigned to the form hidden fields (reqId and reqStatus) are getting overwritten by new values in the foreach loop. By the end of the foreach loop, only the last values are saved in these hidden fields.