How to commit just part of transaction PHP? - php

Question

I need ideas to solve the problem where there's an order to be updated, and payments to be created to this order. But if the order charging fails. The updates made to the order should be undone, but the charges created to it should persist.
Example controller code:
$order = Order::find(1);
DB::beginTransaction();
try {
$order->update(['status' => 1]);
chargeOrder ($order);
} catch (PaymentErrorException $e) {
DB::rollback();
throw $e;
}
catch (\Exception $e) {
DB::rollback();
throw $e;
}
DB::commit();
Example function that make the order charging:
function chargeOrder( $order ) {
$payments_service->charge($order);
$order->payments()->create( new Payment() );
}
What i need is, when a PaymentErrorException occurs, only the $order->update() should be undone, but the changes made inside chargeOrder function, should persist.

Answer 1

If I understand the question correctly:
$order = Order::find(1);
$previousStatus = $order->status;
DB::beginTransaction();
try {
$order->update(['status' => 1]);
chargeOrder ($order);
} catch (PaymentErrorException $e) {
$order->update(['status' => $previousStatus]);
}
catch (\Exception $e) {
DB::rollback();
throw $e;
}
DB::commit();