I start learn PHP and is very clear I make some error here, I try obtain Unix timestamp of specific hour and minutes of the day:
<?php
date_default_timezone_set('America/Argentina/Buenos_Aires');
$data = new DateTime();
$datafmt = $data->format('Y-m-d');
echo strtotime($datafmt,'18:30:00');
?>
The code return 1554951600 and is equal to:
GMT: Thursday, April 11, 2019 3:00:00 AM
Your time zone: Thursday, April 11, 2019 12:00:00 AM GMT-03:00
This is wrong, timestamp should be:
1555018200 is equal to:
GMT: Thursday, April 11, 2019 9:30:00 PM
Your time zone: Thursday, April 11, 2019 6:30:00 PM GMT-03:00
What I doing wrong?
Fixed!
echo strtotime($datafmt. '18:30:00');
, instead . that is my error!
You do not need strtotime() at all. DateTime class is a replacement and is more powerful. Just pass the time to the constructor or set it with the method setTime()
<?php
date_default_timezone_set('America/Argentina/Buenos_Aires');
$data = new DateTime('18:30:00');
// Alternative ways to set the time of the DateTime object
// $data->setTime('18', '30', '00');
// $data->setTime(...explode(':', '18:30:00'));
$datafmt = $data->format('U'); // U means UNIX timestamp
echo $datafmt;
Related
I got a timestamp from my SQL-database: $DBdata = '2019-10-10 12:25:59', this date is UTC+0. Well i live in Denmark where we have the following UTC.
Central EU time winter (UTC+1)
Central EU summertime (UTC+2)
These UTC's changes from summer to winter different dates each year.
Summer time
• 2019 - The night between Saturday 30 March and Sunday 31 March
• 2020 - The night between Saturday 28 March and Sunday 29 March
• 2021 - The night between Saturday, March 27 and Sunday, March 28
• 2022 - The night between Saturday 26 March and Sunday 27 March
• 2023 - The night between Saturday, March 25 and Sunday, March 26
Winter time
• 2019 - The night between Saturday, October 26 and Sunday, October 27
• 2020 - The night between Saturday, October 24 and Sunday, October 25
• 2021 - The night between Saturday, October 30 and Sunday, October 31
• 2022 - The night between Saturday 29 October and Sunday 30 October
• 2023 - The night between Saturday 28 October and Sunday 29 October
Would it be possible to make an if-statement that changes these UTC's, with the right +1/+2?
Maybe something like this:
$Winter= gmdate('Y-m-d H:i:s', strtotime("WinterUTC"));
$Summer= gmdate('Y-m-d H:i:s', strtotime("SummerUTC"));
if (($$DBdata>= $Winter) && ($$DBdata<= $Summer)){
$gmt_dateWinter = gmdate('Y-m-d H:i:s', strtotime($date + '+ 2 hours') );
}else{
$gmt_dateSummer = gmdate('Y-m-d H:i:s', strtotime($date + '+ 1 hours') );
}
I don't know if this even is a smart way to do this. If there is another more smart way to do it please lead me in another direction.
Thanks!
With the DateTime class you can easy convert a date/time to any other time zone.
function convertTimeZone($strDateTime, $sourceTimeZone, $targetTimeZone){
return date_create($strDateTime, new DateTimeZone($sourceTimeZone))
->setTimeZone(new DateTimeZone($targetTimeZone))
->format('Y-m-d H:i:s');
}
example with a daylight saving time
$localTime = convertTimeZone('2019-10-10 12:25:59', 'UTC', 'Europe/Copenhagen');
echo $localTime."<br>";
returns:
2019-10-10 14:25:59
example wintertime
$localTime = convertTimeZone('2019-02-10 12:25:59', 'UTC', 'Europe/Copenhagen');
echo $localTime."<br>";
returns:
2019-02-10 13:25:59
Note: Solutions based on stringtotime are not recommended because of known issues and limitations on some systems.
You can use gmdate and date("I") to generate the date considering the timezone:
gmdate: Format a GMT/UTC date/time
$DBdata = '2019-10-10 12:25:59';
$timezone = +2; // (GMT +2:00) CEST (European Summer Time)
$GMdate = gmdate("Y-m-d H:i:s", strtotime($DBdata) + 3600*($timezone + date("I")));
echo $GMdate;
returns:
2019-10-10 22:25:59
From the date documentation:
I (capital i) Whether or not the date is in daylight saving time: 1
if Daylight Saving Time, 0 otherwise.
Thats simple change in php script default timezone and then display time:
https://www.php.net/manual/en/function.date-default-timezone-set.php
$time = date('H:i:s', time());
$ok = date_default_timezone_set('America/Los_Angeles');
echo $tz = date_default_timezone_get();
$h = new DateTime();
echo $h->format('H:i:s'); // curr time
$o = new DateTime($time);
echo $o->format('H:i:s'); // time
I have this script
echo 'giorni mese: '.date('t', $mese_start).' - mese start: '.$mese_start;
output is:
giorni mese: 31 - mese start: 11
But november doesn't have 30 days?
What am I missing?
Update:
right, thank you.
The second argument to date() is a timestamp, which is the number of seconds since 1970-01-01 00:00:00 UTC. The value of $mese_start is 11. So that timestamp is 1970-01-01 00:00:11 UTC, and January has 31 days.
If you want to use $mese_start as a month number rather than a timestamp, you can use mktime() to create a timestamp from a particular date:
$ts = mktime(0, 0, 0, $mese_start);
echo 'giorni mese: '.date('t', $ts).' - mese start: '.$mese_start;
The second argument of date is interpreted as a Unix timestamp, not a month. You are passing "11" which equals some time on January 1st, 1970. And January has 31 days.
You could either construct a valid timestamp for November or use cal_days_in_month:
echo cal_days_in_month(CAL_GREGORIAN, 11, 2018); // 30
I have a timestamp say 1512070200 which translates to November 30, 2017 7:30:00 PM GMT or December 1, 2017 01:00:00 AM GMT+05:30 in IST.
I want to be able to subtract the time that has passed on that day and revert back to the time at 12:00:00 AM.
For example
If i get a timestamp of 1512978955 which is December 11, 2017 7:55:55 AM GMT I want the output to be 1512950400 which is December 11, 2017 12:00:00 AM GMT.
There is no fixed amount of hours that can be subtracted from the timestamp, instead it would be a variable amount depending on the time that has passed for that particular day so it could be 1 millisecond or 1 second or 1 minute or 1 hour since 12:00:00 AM.
One way would be to convert the timestamp to a date and then break into it's constituent parts so that you can use mktime to generate the date at midday
$ts=1512070200;
$y=date('Y',$ts);
$m=date('m',$ts);
$d=date('d',$ts);
$date=date('Y-m-d H:i:s',mktime(12,0,0,$m,$d,$y));
echo date('Y-m-d H:i:s',$ts).' -> '.$date;
which outputs
2017-11-30 19:30:00 -> 2017-11-30 12:00:00
or, if the output date needs to be as shown use
$format=DATE_COOKIE;
$ts=1512070200;
$y=date('Y',$ts);
$m=date('m',$ts);
$d=date('d',$ts);
$date=date($format,mktime(12,0,0,$m,$d,$y));
echo date($format,$ts).' -> '.$date;
#Thursday, 30-Nov-17 19:30:00 GMT -> Thursday, 30-Nov-17 12:00:00 GMT
Even easier is to use noon as shown by #splash58
echo date( $format, strtotime( 'noon', $ts ) );
You can set noon time to DateTime object
$ts=1512070200;
$date = new DateTime();
$date->setTimestamp($ts);
$date->modify('noon');
echo $date->format(DATE_COOKIE); // Thu, 30 Nov 2017 12:00:00 +0000
demo
I am working on an ancient system written in vanilla PHP.
I am having some time conversion issues.
In the below example, I an expecting both the timestamp and the "pretty date" to reflect one another:
<?php
date_default_timezone_set( 'Europe/London' );
$timestamp = 1509062400; //Friday, October 27, 2017 12:00:00 AM
$date = new DateTime();
$date->setTimezone( new DateTimeZone( 'Europe/London' ) );
$date->setTimestamp( $timestamp + 3601 );
$date->setTime( 0, 0 );
echo $date->getTimestamp();
echo '<br/>';
echo $date->format( 'Y-m-d H:i:s' );
However, when running this script on the server, the result is the following:
Timestamp: 1509058800
Pretty Date: 2017-10-27 00:00:00
The pretty date represents 27th Oct 00:00, but the timestamp (according to epochconvertor) represents 26th Oct 23:00.
I am not sure why the timestamp is an hour slow. Can anyone help?
If you're in London, then your timestamp is likely in British Summer Time. The epoch is going to be in GMT. BST is one hour ahead of GMT.
I'm trying to get the unix time for date strings that are formatted like so:
'second sunday of march 2010'
'first sunday of november 2010'
I was under the impression that strtotime could handle such a string, but apparently not, as this returns false. How can I convert to unix time when given a day of week, which one of those in the month (ie. first, second, etc.), a month and a year.
This should be possible with strtotime. You could try generating a timestamp of the first day of march using mktime() and adding that as a 2nd parameter (leaving just "first sunday" in the string part):
$timestamp = mktime (0,0,0,3,1,2010); // 1st of march
$first_sunday = strtotime("first sunday", $timestamp);
Not sure how this will handle the first day (March 1st) actually being a sunday. Make sure you check that out.
Also, and maybe this more reliable, check this out - the poster says he got good results with the following notation (quoting):
<?php
strtotime('+0 week sun nov 2009'); // first sunday in nov 2009
strtotime('+1 week sun nov 2009'); // second sunday
strtotime('-1 week sun nov 2009'); // last sunday in oct 2009
?>
As always with strtotime, whatever you pick, make sure you test well, especially the edge cases (1st day of month is a sunday, last day of last month was a sunday....)
Your code works for me on PHP 5.3.0. What version of PHP are you using?
<?php
date_default_timezone_set("Europe/Oslo");
$time_march = strtotime('second sunday of march 2010');
$time_november = strtotime('first sunday of november 2010');
echo date("Y-m-d", $time_march) . " (timestamp: $time_march)\n";
echo date("Y-m-d", $time_november) . " (timestamp: $time_november)\n";
?>
gives:
2010-03-14 (timestamp: 1268521200)
2010-11-07 (timestamp: 1289084400)