Use the same gform twice on the same page - php

Question

I'm working in a website that needs to have the same form displayed multiple times on the same page.
The plugin that builds the forms is Gravity Forms.
I have already research on the documentation provided and I couldn't find any action that does the job.
I think I'll need to create a function that store in an array the ID of every single form created and do a comparison for every new form, so then I can probably change the ID of the form element(???).
Any guesses?

Answer 1

Solved the problem by printing the GravityForm inside a noscript tag and removing from that when the form is required.
See the example:
var $formContainer = $(".formContainer");
function hide_form($container) {
$container.slideUp();
var add_noscript_tag = "<noscript>" + $container[0].innerHTML + "</noscript>";
$container.empty();
$container.append(add_noscript_tag);
}
function show_form($container) {
var remove_noscript_tag = $container[0].innerHTML
.replace("<noscript>", "")
.replace("</noscript>", "");
$container.empty();
$container.append(remove_noscript_tag);
$container.slideDown();
}
$("button").click(function() {
var $FormContainer = $(this).next();
if ($FormContainer.is(":visible")) {
hide_form($FormContainer);
} else {
var $otherForm = $(".formContainer:visible");
if ($otherForm.length > 0) {
hide_form($otherForm);
}
show_form($FormContainer);
}
});
button {
margin: 20px 0;
}
.formContainer {
display: none;
background: #eee;
}
.formContainer form {
padding: 20px;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div>
<button>open form 1</button>
<div class="formContainer">
<noscript>
<form>
<input type="text" value="Name"/>
<input type="text" value="Phone"/>
<input type="text" value="Email"/>
</form>
</noscript>
</div>
</div>
<div>
<button>open form 2</button>
<div class="formContainer">
<noscript>
<form>
<input type="text" value="Name"/>
<input type="text" value="Phone"/>
<input type="text" value="Email"/>
</form>
</noscript>
</div>
</div>