My code does not read from mysql database - php

I've tried to debug this times without success. Here is what I've tried so far
<?php
$cid= (string)$_GET['cid'];//I passed this from another page using get method
echo $cid; //My code works up to this point
$record = mysql_query("select * from questions where QType = '$cid'");
$array = array();
while($row = mysql_fetch_assoc($record))
{
$array[] = $row;
}
for($var = 0; $var<count($array);$var++)
{
echo $array[$var]['Question'].'<br>';
}
?>

This code will work and is a bit safer
<?php
//Connection part
$servername = "server_adress"; //It can be localhost or 127.0.0.1 or some other IP
$username = "XXXXXX"; //Username for DB
$password = "YYYYYY"; //Password for that user
$database = "ZZZZZZ"; //DB name you are connecting to
//Create a new connection
$conn_to_db = new mysqli($servername, $username, $password,$database);
// Check connection
if ($conn_to_db -> connect_error) {
die("Connection failed: " . $conn_to_db ->connect_error);
}
//Finished connection part
$cid = mysqli_real_escape_string($conn_to_db, $_GET['cid']); //Escapes special characters in a string for use in an SQL statement
$array = array();
if($stmt = $conn_to_db -> ("SELECT * FROM questions WHERE QType = ?")) {
$stmt -> bind_param("s", $cid);
$stmt -> execute();
$stmt -> bind_result($question_from_db); //Here you can put all variables you are fetching from DB
while($stmt -> fetch()){
//Iterate over rows - put your code here to fetch everything you need from DB and put in array
$array[] = array('question' => $question_from_db);
}
$stmt -> close();
}
}
//you can iterate over rows like this
foreach($array as $key => $value) {
echo $value['question'];
}
?>
Couple of things to keep in mind:
it's a good practice to avoid * (selecting everything from DB) and
put only columns you need from DB
use prepared statement which is a safer way and protects you from SQL injection
MySQL is depreciated so try to avoid it (use mysqli or PDO)
The code above you need to adjust to your needs! It will not work as copy/paste. Put your DB connection and select columns from DB you need and add variables which you fetch from DB
Keep in mind there are more ways to do this, and someone will probably give another solution.
if you are not on a production server, it's good to have some error reporting to see the errors that are happening

Related

query doesn't working using php

I am new in Php and MYsql,
I am trying to create a simple query using which contain a variable using php.
however I think I am not writing the querty correctly with the variable since the result of this query is 0.
would be happy for assistance here is my code:
<?php
$phone = $_GET['phone'];
echo $phone;
$query = "SELECT * FROM `APPUsers` WHERE `Phone` LIKE "."'".$phone."' ";
echo $query;
$result = mysqli_query($mysqli, $query);
echo mysqli_num_rows($result);
?>
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
$conn = new mysqli($servername, $username, $password, $dbname);
$sql = "SELECT * FROM APPUsers WHERE Phone LIKE '%$phone%'";
$result = $conn->query($sql);
Above there is a fast solution , but it is not safe ,
because is vulnerable to injection ...
Below let's see how to do it and why to do it in this way
It is a good practice to store sensible information in a separate file
out of the document root , it means will be not accesible from the web .
So let's create a file configDB.ini for example and put in db informations
servername = something;
username = something;
password = something;
dbname = something;
Once did it we can create a script called dbconn.php and import the file with credentials ,
in this way there is an abstraction between credentials and connection .
in dbconn.php :
$config = parse_ini_file('../configDB.ini');
$conn = mysqli_connect('localhost',$config['username'],$config['password'],$config['dbname']);
We can even improve the code connecting to db only once and use the same connection all the time we need query .
function db_connect() {
// static will not connect more than once
static $conn;
if(!isset($conn)) {
$config = parse_ini_file('../configDB.ini');
$conn = mysqli_connect('localhost',$config['username'],$config['password'],$config['dbname']);
}
return $conn;
}
...
$conn = db_connect();
$sql = "SELECT * FROM APPUsers WHERE Phone LIKE '%$phone%'";
$result = mysqli_query($conn,$sql);
In the end let's say something about mysqli_query
Reasons why you should use MySQLi extension instead of the MySQL extension are many:
from PHP 5.5.0 mysql is deprecated and was introduced mysqli
Why choose mysqli (strenghts)
object oriented
prepared statements
many features
no injection
Do you connect to the database?
The apostrophes around APPUsers and Phone might not be the right ones, as they are not the single apostrophes but some weird squiggly ones.
Try this :
$query = "SELECT * FROM 'APPUsers' WHERE 'Phone' LIKE '".$phone."' ";

Connection is made to the database with php script but no values are returned

I have a successful connection to the database through this php script but it is not returning any values even though it is connected. I am checking for the results on my web browser and it just returns a blank screen. I have used the same script (different queries) to access two other tables in the database and they are both working fine. Here is my code:
<?php
$username = "xx";
$password = "xxx";
$host = "xxxxx";
$database="xxxxx";
$server = mysql_connect($host, $username, $password);
$connection = mysql_select_db($database, $server);
$myquery = "SELECT `AUTHOR`, `In_order` from `authors`";
$query = mysql_query($myquery);
if ( ! $query ) {
echo mysql_error();
die;
}
$data = array();
for ($x = 0; $x < mysql_num_rows($query); $x++) {
$data[] = mysql_fetch_assoc($query);
}
echo json_encode($data);
mysql_close($server);
?>
It is probably some silly mistake that I have over looked but I have been stuck on it for longer than I should! thanks in advance for any feedback
Tried you code locally on some data and it returns everything ok.
I needed to change the select to match my data
So I am 95% sure the problem is in your query / db settings.
I would first check if your columns in database is really called AUTHOR and 'In_order' with the exact capital letters.
MySql names can be case sensitive depending on your db server settings, and this could be the problem
Sidenote: if you can research mysqli and pdo for connecting to DB instead of mysql that is deprecated.
Try this:
$myquery = "SELECT `AUTHOR`, `In_order` from `authors`";
$query = mysql_query($myquery);
$num = mysql_num_rows($query);
var_dump($query);
var_dump($num);
echo mysql_error();
and tell us what it all says.
Edit: okay, so it's 231 rows in your table, as the var_dump($num) says. Now let's try and get them at last, but in a slightly more efficient way:
while ($row = mysql_fetch_assoc($query)) {
$data[] = $row;
}
echo json_encode($data);
I have a feeling that your "for" loop and mysql_fetch_assoc() inside is what plays tricks with you, because both of them use different internal counters.

Learning SELECT FROM WHERE prepared statements

Can someone re-write the below code as a prepared statement?
result = mysqli_query($con,"SELECT * FROM note_system WHERE note = '$cnote'")
or die("Error: ".mysqli_error($con));
while($row = mysqli_fetch_array($result))
{
$nid = $row['id'];
}
I am trying to learn prepared statements and am having trouble understanding how it works from the many examples I have found while searching. I am hoping that if I see some code I am familiar with re-written as a prepared statement that it might click for me. Please no PDO, that is too confusing for me at my current level of knowledge. Thanks.
Hello ButterDog let me walk you through PDO step by step.
Step 1)
create a file called connect.php (or what ever you want). This file will be required in each php file that requires database interactions.
Lets start also please note my comments :
?php
//We set up our database configuration
$username="xxxxx"; // Mysql username
$password="xxxxx"; // Mysql password
// Connect to server via PHP Data Object
$dbh = new PDO("mysql:host=xxxxx;dbname=xxxxx", $username, $password); // Construct the PDO variable using $dbh
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); // Set attributes for error reporting very IMPORTANT!
$dbh->setAttribute(PDO::ATTR_EMULATE_PREPARES, FALSE); // Set this to false so you can allow the actual PDO driver to do all the work, further adding abstraction to your data interactions.
?>
Step 2) Require the connect.php please take a look :
require ('....../........./...../connect.php'); // Require the connect script that made your PDO variable $dbh
Step 3)
to start database interactions just do the following also please read the code comments. For the moment we will not worry about arrays! Get the full gyst of PDO then worry about making it easier to work with! With repetition the "long way" comes more understanding of the code. Do not cut corners to begin with, cut them once you understand what you are doing!
$query = $dbh->prepare("SELECT * FROM note_system WHERE note = :cnote"); // This will call the variable $dbh in the required file setting up your database connection and also preparing the query!
$query->bindParam(':cnote', $cnote); // This is the bread and butter of PDO named binding, this is one of the biggest selling points of PDO! Please remember that now this step will take what ever variable ($cnote) and relate that to (:cnote)
$query->execute(); // This will then take what ever $query is execute aka run a query against the database
$row = $query->fetch(PDO::FETCH_ASSOC); // Use a simple fetch and store the variables in a array
echo $row['yourvalue']; // This will take the variable above (which is a array) and call on 'yourvalue' and then echo it.
Thats all there is to PDO. Hope that helped!
Also take a look at this. That helped me so so much!
I also use this as a reference (sometimes) - The web site looks like crap but there is quality information on PDO on there. I also use this and I swear this is the last link! So after this any questions just ask, but hopefully this can turn into a little reference guide on PDO. (hopefully lol)
Use pdo:
http://php.net/manual/en/book.pdo.php
from various docs:
/* Connect to an ODBC database using driver invocation */
$dsn = 'mysql:dbname=testdb;host=127.0.0.1';
$user = 'dbuser';
$password = 'dbpass';
try {
$dbh = new PDO($dsn, $user, $password);
} catch (PDOException $e) {
echo 'Connection failed: ' . $e->getMessage();
}
$sql = 'SELECT name, colour, calories
FROM fruit
WHERE calories < :calories AND colour = :colour';
$sth = $dbh->prepare($sql, array(PDO::ATTR_CURSOR => PDO::CURSOR_FWDONLY));
$sth->execute(array(':calories' => 150, ':colour' => 'red'));
$red = $sth->fetchAll();
This is one way to do it with PDO:
$sel = $db->prepare("SELECT * FROM note_system WHERE note=:note");
$sel->execute(array(':note' => $_POST['note']));
$notes = $sel->fetchAll(PDO::FETCH_ASSOC);
See the placeholder :note in the query in line 1, which is bound to $_POST['note'] (or any other variable for that matter) in line 2.
If I want to run that query again, with a different value as :note, I'll just call lines 2 and 3.
Displaying the results:
foreach ($notes as $note) {
echo $note['id'] . ": " . $note['text'] . "<br />";
}
This should help you on the right path...
$link = mysqli_connect("localhost", "my_user", "my_password", "world");
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$query = "SELECT id FROM note_system WHERE note = ?";
$stmt = mysqli_stmt_init($link);
if(!mysqli_stmt_prepare($stmt, $query)) {
print "Failed to prepare statement\n";
}
else {
$note = "mynote";
mysqli_stmt_bind_param($stmt, "s", $note);
mysqli_stmt_execute($stmt);
$result = mysqli_stmt_get_result($stmt);
while ($row = mysqli_fetch_array($result))
{
$nid = $row['id'];
}
}
mysqli_stmt_close($stmt);
mysqli_close($link);

Trying to search ID and Display selected information

I have made a search box so that you can enter the product id that you wish to gain the information of. When i input data in the product id box, there are no results returned, anyone know what im doing wrong? I think that 'while ($row = mysql_fetch_array($result)) {' is wrong but not too sure as everything ive tried didn't work.
<div class="searchbox">
<form action="Search.php" method="get">
<fieldset>
<input name="search" id="search" placeholder="Search for a Product" type="text" />
<input id="submit" type="button" />
</fieldset>
</form>
</div>
<div id="content">
<ul>
<?php
// connect to the database
include('base.php');
$search = mysql_real_escape_string($_GET['search']);
$query = "SELECT * FROM Product WHERE ProductID LIKE '%{$search}%'";
$result = mysql_query($query);
while ($row = mysql_fetch_array($result)) {
echo "<li><span class='name'><b>{$row['ProductID']}</b></span></li>";
}
Don't use mysql specific syntax, It's outdated and can get you into real trouble later on, especially if you decide to use sqlite or postgresql.
Use a PDO connection, you can init one like this:
// Usage: $db = connectToDatabase($dbHost, $dbName, $dbUsername, $dbPassword);
// Pre: $dbHost is the database hostname,
// $dbName is the name of the database itself,
// $dbUsername is the username to access the database,
// $dbPassword is the password for the user of the database.
// Post: $db is an PDO connection to the database, based on the input parameters.
function connectToDatabase($dbHost, $dbName, $dbUsername, $dbPassword)
{
try
{
return new PDO("mysql:host=$dbHost;dbname=$dbName;charset=UTF-8", $dbUsername, $dbPassword);
}
catch(PDOException $PDOexception)
{
exit("<p>An error ocurred: Can't connect to database. </p><p>More preciesly: ". $PDOexception->getMessage(). "</p>");
}
}
And then init the variables:
$host = 'localhost';
$user = 'root';
$dataBaseName = 'databaseName';
$pass = '';
Now you can access your database via
$db = connectToDatabase($host , $databaseName, $user, $pass); // You can make it be a global variable if you want to access it from somewhere else.
Then you should make sure that you actually have the variable:
$search = isset($_GET['search']) ? $_GET['search'] : false;
So you can actually skip the database thing if something, somehow, fails.
if(!$search)
{
//.. return some warning error.
}
else
{
// Do what follows.
}
Now you should construct a query that can be used as a prepared query, that is, it accepts prepared statements so that you prepare the query and then you execute an array of variables that are to be put executed into the query, and will avoid sql injection in the meantime:
$query = "SELECT * FROM Product WHERE ProductID LIKE :search;"; // Construct the query, making it accept a prepared variable search.
$statement = $db->prepare($query); // Prepare the query.
$statement->execute(array(':search' => $search)); // Here you insert the variable, by executing it 'into' the prepared query.
$statement->setFetchMode(PDO::FETCH_ASSOC); // Set the fetch mode.
while ($row = $statement->fetch())
{
$productId = $row['ProductID'];
echo "<li class='name><strong>$productId</strong></li>";
}
Oh yes, don't use the b tag, it's outdated. Use strong instead (It's even smarter to apply font-weight: bold; to .name in a separate css file.
Feel free to ask questions if anything is unclear.
remove the {} before and after $search.
should be:
$query = "SELECT * FROM Product WHERE ProductID LIKE '%$search%'";
You can use:
$result = mysql_query($query) or die($query."<br/><br/>".mysql_error());
To confirm that the data is returning.

Mysql Query, comparing values and assigning to PHP variables

I have done a fair bit of research into what i want to do, although i haven't found anything. I am not too sure if i am looking for the right thing :( I am also a little bit new to PHP and MySQL syntax, so please be kind.
I wish to perform the following in this order:
Connect to a database (DONE)
Query for a specific string (I think im done)
From here is gets a bit fuzzy :(
If a match is found for the variable, copy the whole row (I need other variables).
Assign the values from the SQL query to a PHP variables.
From there i will be right to carry on.
I have established the connection to the database with the following:
function connect() {
$dbname = 'database';
$dbuser = 'username';
$dbpass = 'password';
$dbhost = 'localhost';
mysql_connect($dbhost, $dbuser, $dbpass) or die("Unable to connect to database");
}
And then calling the function connect();
I then wish to query the database for a particular value, for the sake of this argument i will use a static value. This is what i have:
mysql_select_db(DATABASENAME) or die( "Unable to select database");
$query = "SELECT * FROM `TABLE` WHERE `COLUMN` LIKE 'VAULE'";
$result=mysql_query($query);
From here i am not too sure how to compare the query result to see if it is a match (something along the lines of mysql rows?).
If there is a match, then i would like to obtain the entire row, and assign each value to a php variable.
I am not asking for you to do it for me, simply i kick in the right direction should be fine!
Hope it explains it enough :)
Thanks for your kind guidance
Ok. You will want to keep the connection to the mysql database somewhere. A common use is $conn.
So you would have
$conn = mysql_connect($dbhost, $dbuser, $dbpass) or die("Unable to connect to database");
Then, either from the URL or Post, or just some variables you have sitting in your php file, you can query the database by putting the variables in the query itself. Also, here you can use $conn so that you have one place to connect to the database, in an include for example, and you won't have to make all of the connection string in each place you need to connect to the DB.
$query = "SELECT * FROM `TABLE` WHERE `COLUMN` LIKE '%" . $varToCompare . "%'";
$result=mysql_query($query,$conn);
Above you are using a like. You may want to just look at doing .. Where column=$var.
Then you can use php to spin through the results into an array (for queries where would get multiple rows).
Where the hell you learned how to use MySQL in PHP ? The mysql_* functions are more then 10 years old and not maintained anymore. Community has already begun to work on deprecating them.
You should be using PDO or MySQLi for that.
// connection to database
$db = new PDO('mysql:host=localhost;dbname=datadump_pwmgr;charset=UTF-8',
'datadump_pwmgr',
'kzddim05xrgl');
$db->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
// setting up prepared statement for the query
$statement = $db->prepare('SELECT * FROM table WHERE column LIKE :value');
$statement->bindParam(':value', $some_variable, PDO::PARAM_STR, 127);
// executing query and fetching first result
if ( $statement->execute())
{
$data = $statement->fetch(PDO::FETCH_OBJ);
var_dump( $data );
}
This should give you something like what you needed. Though, I would recommend to try this tutorial. And learning more about prepared statements could be useful too.
Also , if you are working with objects, then it is possible to create a single DB connection object , and pass it to multiple other classes to use it:
$pdo = new PDO('sqlite::memory:');
$a = new Foo( $pdo );
$b = new Bar( $pdo, 'something');
This way you pass both objects the same database connection, and you do not need to reinitialize it.
I think you're looking for something like this:
$count = mysql_num_rows($result);
//if there is more then 1 record retrieved from the database
if($count > 0)
{
//Do what ever you want to do here, which I think you want to be
while ($row = mysql_fetch_assoc($result))
{
echo $row["Columnname1"];
echo $row["Columnname2"];
echo $row["Columnname3"];
}
}
else
{
echo "There are no matches for this specific value";
}
You can get the queried data by rows as an associated array using mysql_fetch_array():
$row = 0;
$data = mysql_query("SELECT name1,name2 FROM ....");
while(($result = mysql_fetch_array($data)) !== false)
{
echo "row = $row, name1 = " . $result["name1"] . ", name2 = " . $result["name2"];
$row ++;
}
... or as an objects using mysql_fetch_object():
$row = 0;
$data = mysql_query("SELECT name1,name2 FROM ....");
while(($result = mysql_fetch_object($data)) !== false)
{
echo "row = $row, name1 = $result->name1, name2 = $result->name2";
$row ++;
}
I'm not too sure of what you want, but I can see one probable bug here: you're using LIKE in a way which means =: in order to have LIKE to behave like a like, you need some joker chars :
"SELECT * FROM `TABLE` WHERE `COLUMN` LIKE 'VAULE'" // This will return all rows where column='VAUL'
"SELECT * FROM `TABLE` WHERE `COLUMN` LIKE '%VAULE%'" // This will return all rows where column='%VAUL%' // This will return any row containing 'VAUL' in column
"SELECT * FROM `TABLE` WHERE `COLUMN` LIKE '%VAULE'" // This will return all rows where column='%VAUL' // this will return all rows ending by VAUL. I guess you get it now :)
An to retrieve the actual results:
$query = "SELECT * FROM `TABLE` WHERE `COLUMN` LIKE '%VAULE%'";
$result=mysql_query($query);
while (false !== ($row = mysql_fetch_assoc($result))) {
//here $row is an array containing all the data from your mysql row
}
Try to write the database connection in another page no need to use function and include that page in where ever you need.
ex: require_once 'dbConnect.php';
dbConnect.php consists:
<?php
$dbname = 'datadump_pwmgr';
$dbuser = 'datadump_pwmgr';
$dbpass = 'kzddim05xrgl';
$dbhost = 'localhost';
mysql_connect($dbhost, $dbuser, $dbpass) or die("Unable to connect to database");
?>

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