Get value from a table through an ID from another table - php

Question

So basically I have a table : "task":
- id - morada -
- 1 - 1 -
And a "moradas" table:
- ID - Morada - CodPostal
- 1 - Street 1th - 1523
I want through task.Address from the task table get the Address and Postal Code from the moradas table. Right now I'm only showing the int number of the address in the trip table.
<td><?php echo $fetch['address']?></td>
The query I have now is this
$query = $conn->query("SELECT * FROM `task` WHERE status != 'Done' ORDER BY `id` ASC");
How do I get the values from the Address table with that int and show them in that echo?

Answer 1

You can user INNER JOIN for joining the two tables and get data from them.
INNER JOIN is used in this context assuming that each address id from database Trip corresponds to the actual address from database table: address.
SELECT T.Trip, A.Address, A.Postal_Code FROM Trip T
INNER JOIN address A ON T.Address = A.Address_ID
Note:
Your specified field names contain spaces.
I have added underscores instead of spaces in them.
Please put proper field names here.
Reference:
EDIT:
Updated Query as per updated question:
SELECT T.id, A.Morada, A.CodPostal FROM task T
INNER JOIN moradas A ON T.morada = A.ID

Answer 2

Updated according to your tables and columns.
If you want address and postal code where your task.id and moradas.id value matches, then you should join two tables and get address and postal code from moradas table -
Try this :-
$sql = "SELECT
task.id,
CONCAT(
moradas.`Morada`,
' ',
moradas.`CodPostal`
) AS address
FROM
task
LEFT JOIN moradas
ON (task.id = moradas.id)
WHERE task.`status` != 'Done'
ORDER BY task.id ASC";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "Address : " . $row["address"]."<br>";
}
} else {
echo "0 results returned";
}
$conn->close();
I assume that status column is in your task table
This query will show your address and postal code as one column address. If you want those into saperate columns, you can skip concat and select Morada and CodPostal separately.

Answer 3

Follow this scheme always as I will show you regarding your table names
If you have big data in MySQL like name. Postal code Id. And suppose you have addresses in another table witch related to another tracking services as example
$ret = mysql_query("select t2.id, t2.name, t2.phone, t1.address From t2 Left join t1 on t2.id = t1.id where t2.id = $id ")
// $id = is variable you get from php request like $_GET and id table should have index in MySQL then do the following
echo'<table>'
While ($row = mysql_fetch_assoc($ret) {
echo"<td>" .$row["addresse"]."<td>";
// repeat this for all retrieved data
}
echo '</table>'
Now you will have table in php output with all data in the query.
If query returns one record so table will have one result
If query have 10000 records as result so table will have 10000
You may put limit in query to retrieve 100 result per request