I have a called class called ClientPolicy which is like this
class ClientPolicy {
var $serverHost="www.example.com";
var $httpPort = 80;
var $httpsPort = 443;
var $appKey;
var $secKey;
var $defaultContentCharset = "UTF-8";
}
and another class file name SyncAPIClient which looks like this
class SyncAPIClient{
function SyncAPIClient(ClientPolicy $clientPolicy) {
$this->clientPolicy = $clientPolicy;
}
function SyncAPIClient($appKey, $appSecret) {
$this->clientPolicy = new ClientPolicy();
$this->clientPolicy->appKey=$appKey;
$this->clientPolicy->secKey=$appSecret;
}
}
My questions are
1.) If you check the function in SyncAPIClient, you will notice that the ClientPolicy class was passed as a parameter before a variable, what does it really mean? What is the essence of passing a class in function parameter?
2.) I am getting an error "Cannot redeclare SyncAPIClient::SyncAPIClient()" in my script log and the reason is that SyncAPIClient function was called twice in SyncAPIClient class. How can I solve this issue? Is there any better way to write this SyncAPIClient function instead of passing it twice?
The author of this script is nowhere to be found and I am left to fix it.
1) Here the $clientPolicy variable that is passed to this function, needs be a ClientPolicy instance.
In this way, if the argument that is passed is different from an instance of ClientPolice class, an error is generated.
function SyncAPIClient(ClientPolicy $clientPolicy) {
$this->clientPolicy = $clientPolicy;
}
https://wiki.php.net/rfc/typed_properties_v2
https://laravel-news.com/php7-typed-properties
2) The error Cannot redeclare SyncAPIClient::SyncAPIClient() is caused because you are trying to declare two functions called SyncAPIClient ().
If in first SyncAPIClient() method you just want save the $clientPolicy in $this->clientPolicy, you can use the magic method __construct. Or just try changing the name of one of the functions, and the problem should be a problem.
class SyncAPIClient{
__construct(ClientPolicy $clientPolicy) {
$this->clientPolicy = $clientPolicy;
}
function SyncAPIClient($appKey, $appSecret) {
$this->clientPolicy = new ClientPolicy();
$this->clientPolicy->appKey=$appKey;
$this->clientPolicy->secKey=$appSecret;
}
}
https://www.php.net/manual/en/language.oop5.decon.php
http://www.zentut.com/php-tutorial/php-constructor-and-destructor/
Hope this helps!
I would've fix the code you have like this:
class SyncAPIClient
{
private $clientPolicy = null;
function SyncAPIClient(ClientPolicy $clientPolicy = null)
{
if($clientPolicy instanceof ClientPolicy){
$this->clientPolicy = $clientPolicy;
}else{
$this->clientPolicy = new ClientPolicy();
}
}
public function setAuthParams($appKey, $appSecret) {
$this->clientPolicy->appKey=$appKey;
$this->clientPolicy->secKey=$appSecret;
}
}
This way you can instantiate a SyncAPIClient with or without a ClientPolicy.
Without ClientPolicy:
$syncAPI = new SyncAPIClient();
$syncAPI->setAuthParams($apiKey, $apiSecret);
With ClientPolicy:
$clientPolicy = new ClientPolicy();
$clientPolicy->appKey=$appKey;
$clientPolicy->secKey=$appSecret;
$syncAPI = new SyncAPIClient($clientPolicy);
When using class and functions in combination like
Rtin::
Functions nested inside that class Rtin should have different names than that class name
So you shouldn't have function called rtin
However you can call function from outside the class with it's name
From the error you have may be due to:
function you nested in the class or the function outside the class has a duplicate outside the script itself. Like having function mentioned in included function.php file and also mentioned in the script itself so php get confused because function name is written in two php files at the same time
Example of class
class Rtin{
private $data;
private $results;
public function getResultsType(){
return ........
}
}
To call class use
$q = Rtin::getResultsType($data['name']);
In your example. Adapt it to the example I have provide and review the included files for duplicate function .
Related
I need to use method from Nette library, that I'm including by use command. But it doesn't work as I want to, throws fatal error, that I am calling undefined method.
How should I approach that method to make it work? Stupid question, but I am kinda new to OOP...
Method from class PresenterComponent.php
public function getPresenter($need = TRUE)
{
return $this->lookup('Nette\Application\UI\Presenter', $need);
}
And my code, where I need to use that method:
use Nette\Application\UI\PresenterComponent;
class DatabaseCollectionAdapter extends ArrayDataAdapter
{
// ..... some code......
$this->user = $this->getPresenter()->getUser();
Error:
Fatal Error
Call to undefined method Ctech\Gridator\DataAdapter\DatabaseCollectionAdapter::getPresenter()
change this
$this->user = $this->getPresenter()->getUser();
to this:
$object = new yourObject(); // yourObject extends PresenterComponent
$this->user = $object->getPresenter()->getUser();
use Nette\Application\UI\PresenterComponent; does not include or do any kind of magic to make it's functions available on the fly.
https://secure.php.net/manual/de/language.namespaces.importing.php
It's just a shorthand that helps you to use PresenterComponent directly without specifying the whole namespace.
Your DatabaseCollectionAdapter or ArrayDataAdapter has to have a function that looks like this:
class AdapterClass
public function getPresenter() {
return new Nette\Application\UI\PresenterComponent;
}
}
or something like this
use Nette\Application\UI\PresenterComponent;
class AdapterClass
public function getPresenter() {
return new PresenterComponent;
}
}
I have a class file: we'll call it class.php. The functionality of that is to grab info from an ini file (yeah, I posted the question about security and was given the great suggestion to use either a config file or an ini file to hold the DB information).
Essentially, my class is this:
<?php
class myClass
{
public function getAttached()
{
$file = "../../myFile.ini";
if (!$settings = parse_ini_file($file, TRUE)) throw new exception('Unable to open ' . $file . '.');
$hoost = $settings['mysqli']['default_host'];
$useer = $settings['mysqli']['default_user'];
$pazz = $settings['mysqli']['default_pw'];
$dbs = $settings['mysqli']['default_db'];
$con = mysqli_connect($hoost ,$useer, $pazz, $dbs);
return $con;
}
}
$obj = new myClass();
$obj->getAttached();
$vals = $obj->getAttached();
//echo $vals; //didn't know if I should echo this or not.
?>
I want to call this in my somePage.php file to make my "mysqli" connection and go from there...
I tried this:
require_once('class.php');
getAttached();
Obviously that didn't work (I knew it wouldn't but - I did it anyway just to see if "maybe"), so - how do I call that function from my class file in the regular php page?
Any thoughts would be appreciated.
Thanks in advance.
You need to make an instance of the class before calling the functions as they're not static.
require_once('class.php');
$myClass = new myClass();
$myClass-> getAttached();
or, like I said above you could make the function static.
public static function myFunction() {
//etc...
}
Then to call it you would use:
require_once('class.php');
myClass::getAttached();
You have to instanciate your class first, the same way you did it in you class.php file:
$myclass = new myClass();
$myClass->getAttached();
Note that if your method can be used without any relation with your class, you could make it static:
public static function getAttached() {
// ...
}
And use it without having to instanciate your class:
myClass::getAttached();
Your getAttached() method within the myClass ,create the instance for the class and call
the function
$call = new myClass();
$call->getAttached();
Given answers are correct, but if you keep your class file as you posted, you have object already in $obj so there is no need to make new one. If it is just temporary you can ignore my post.
One more thing:
$obj->getAttached(); // this line is not needed, as you call this function in next line
$vals = $obj->getAttached();
I have a class like this:
// file /models/person.php
class Person
{
public function create_path()
{
self::log();
path_helper($this); //a global function in other php file
}
public function log()
{
echo "trying to create a path";
}
}
This is the way how Person is instanciated:
//file /tools/Builder.php
include('/models/Person.php');
class Builder
{
public function build()
{
$type = 'Person';
$temp = new $type();
$temp->create_path();
}
}
As you note in Person class, I am calling the object in question with $this reference. But this is not correct because an error is showed:
Message: Undefined variable: this
I suppose that $this reference point to other object or it is unable to work because the object is created from another script. Also, I tried to use self because there was not problem calling methods with that, but as parameter I get:
Message: Use of undefined constant self - assumed 'self'
So, can you guide me to the right direction?
I tested your code out for myself, with a few minor changes. It appears to work properly.
Changed self::log() to $this->log()
Added global function path_helper (I have no idea what this does)
PHP
function path_helper(Person $object)
{
var_dump($object);
}
class Person
{
public function create_path()
{
$this->log();
path_helper($this); //a global function in other php file
}
public function log()
{
echo "trying to create a path";
}
}
class Builder
{
public function build()
{
$type = 'Person';
$temp = new $type();
$temp->create_path();
}
}
$Build = new Builder();
$Build->build();
Result
trying to create a path
object(Person)[2]
Your code is correct and your going in the right direction.
You should call the log method like this:
$this->log();
because using self:: is reserved for static methods.
Also, try calling the path_helper function like this:
path_helper(self);
Hope I could help you. Couldn't test it, but it should work.
I need an idea to create anonymous class on PHP. I don't know how I can works.
See my limitations:
On PHP you can't make anonymous class, like anonymous function (like class {});
On PHP you don't have class scope (except in namespaces, but it have the same problem below);
On PHP you can't use variables to specify the class name (like class $name {});
I don't have access to install the runkit PECL.
What I need, and why:
Well, I need create a function called ie create_class() that receives a key name and a anonymous class. It'll be useful for me because I want use different name class symbols that PHP can't accept. For instance:
<?php
create_class('it.is.an.example', function() {
return class { ... }
});
$obj = create_object('it.is.an.example');
?>
So, I need an idea that accept this use. I need it because on my framework I have this path: /modules/site/_login/models/path/to/model.php. So, the model.php need to declare a new class called site.login/path.to.model.
On call create_object() if the internal cache have a $class definition (like it.is.an.example it simply return the new class object. If not, need load. So I will use the $class content to search fastly what is the class file.
In PHP 7.0 there will be anonymous classes. I don't fully understand your question, but your create_class() function might look like this:
function create_class(string $key, array &$repository) {
$obj = new class($key) {
private $key;
function __construct($key) {
$this->key = $key;
}
};
$repository[$key] = $obj;
return $obj;
}
This will instantiate an object with an anonymous class type and register it into the $repository. To get an object out you use the key you created it with: $repository['it.is.an.example'].
You can create a dummy class using stdClass
$the_obj = new stdClass();
So basically you want to implement a factory pattern.
Class Factory() {
static $cache = array();
public static getClass($class, Array $params = null) {
// Need to include the inc or php file in order to create the class
if (array_key_exists($class, self::$cache) {
throw new Exception("Class already exists");
}
self::$cache[$class] = $class;
return new $class($params);
}
}
public youClass1() {
public __construct(Array $params = null) {
...
}
}
Add a cache within to check for duplicates
If you really need to to that, you could use eval()
$code = "class {$className} { ... }";
eval($code);
$obj = new $className ();
But the gods won't approve this. You will go to hell if you do it.
i have 2 classes
for DB
for language
i want to use my language things in the DB
so it outputs the result
ex :
class db_control{
var $db_connection, $lang_var;
//create the function for the connection
function db_connect(){
//define some variables
global $db_host, $db_username, $db_password, $db_name, $lang_var;
$this->db_connection = mysql_connect("$db_host","$db_username","$db_password")or die("can't connect to server with these informations");
//checl that the connection is established
if($this->db_connection){
echo $lang_vars->getvar("$langvals[lang_con_est]");
}
but this
$lang_vars->getvar("$langvals[lang_con_est]");
doesn't work
i mean it outputs many problems
and am sure my problem is that i didn't define my variables and classes correctly
P.S : the language class is in file called language.php and this part is in DB.MySQL.php
EDIT :
this is the language class
class lang_vars{
public static function getvar($variable){
return $variable;
}
}
i want the DB class to display text from the language class
thats why i used
echo $lang_vars->getvar("$langvals[lang_con_est]");
but it doesn't work
cuz when i declare the language class
$lang_vars = new lang_vars;
inside the db_control it shows error unexpected T_something expected T_Function
and when i declare it outside nothing up
hope i made things more clear now
Any reason why you are still using PHP4 syntax?
When creating an instance of the db_control class, pass the object to be stored as $lan_var into the constructor or set it via a dedicated setter. See Dependency Injection.
class DBControl
{
protected $_lang;
public function __construct($lang = NULL)
{
if($lang !== NULL) {
$this->_lang = $_lang;
}
}
public function setLang($lang)
{
$this->_lang = $lang;
}
}
Then do either
$dbControl = new DBControl(new LangThing);
or
$dbControl = new DBControl;
$dbControl->setLang(new LangThing);
Also, get rid of the globals. Pass those in via Dependency Injection too.
Make your language class methods static . Read more here.
class LangClass
{
public static function getvar()
{
// your code here
}
}
Then, you can use its functions without creating objects like this:
$LangClass::getvar("$langvals[lang_con_est]");
This can do the trick.
$lang_vars = new LanguageClassOrWhateverItIsCalled();
$lang_vars->getvar($langvals[lang_con_est]);
But maybe you should think of making it a static method. In that case you can call it with:
LanguageClassOrWhateverItIsCalled::getVar($langvals[lang_con_est]);
You can define the method static like:
public static function getVar() {
// Do something
}
Edit: #SAFAD
You should use the static method for this. To make this work, be sure your class language.php is loaded. To do so just add in the DB.MYSQL.php file the following line:
require_once('language.php');
class db_control {
...
Make sure you have the right path to the language.php file.
Then you should call the method in db_control class like this:
if($this->db_connection){
echo lang_vars::getvar("$langvals[lang_con_est]");
}
Besides, what is the use of a function like this? You should either do:
if($this->db_connection){
echo $langvals[lang_con_est];
}
or change your static getvar method to:
public static function getvar($variable){
return $langvals[$variable];
}
and your function call to:
if($this->db_connection){
echo lang_vars::getvar("lang_con_est");
}