PHP: copy MySQL database tables into new database table with additional columns - php

Question

I am looking for a way to copy an existing database with multiple tables into a new database with the same tables and columns + some additional columns. So far so good. If I just copy the database to a new database with the same amount of tables and columns I am doing it like this:
+---------+---------+---------+
| TABLE 1 | | |
+---------+---------+---------+
| Col1 | Col2 | Col3 |
| Value 1 | Value 2 | Value 3 |
| Value 1 | Value 2 | Value 3 |
| Value 1 | Value 2 | Value 3 |
+---------+---------+---------+
copy to:
+---------+---------+---------+
| TABLE 2 | | |
+---------+---------+---------+
| Col1 | Col2 | Col3 |
| Value 1 | Value 2 | Value 3 |
| Value 1 | Value 2 | Value 3 |
| Value 1 | Value 2 | Value 3 |
+---------+---------+---------+
Code:
public function loadDB($db1,$db2){
$this->db->prepare("use ".$db1."");
$sqlshow = "SHOW TABLES ";
$statement = $this->db->prepare($sqlshow);
$statement->execute();
$tables = $statement->fetchAll(PDO::FETCH_NUM);
foreach($tables as $table){
$sql[] = "INSERT INTO ".$db2.".".$table[0]." SELECT * FROM ".$db1.".".$table[0]."; ";
}
$sqlState = implode(' ', $sql);
$insertStatement = $this->db->exec($sqlState);
return $insertStatement?$insertStatement:false;
}
This code works and my database is copied successfully with all my tables and values inside my tables. What I need now is a working example of how am I able to copy the database to a new database where all tables have four additional columns like this:
+---------+---------+---------+
| TABLE 1 | | |
+---------+---------+---------+
| Col1 | Col2 | Col3 |
| Value 1 | Value 2 | Value 3 |
| Value 1 | Value 2 | Value 3 |
| Value 1 | Value 2 | Value 3 |
+---------+---------+---------+
copying to:
+---------+---------+---------+-----------+-----------+-----------+-----------+
| TABLE 2 | | | | | | |
+---------+---------+---------+-----------+-----------+-----------+-----------+
| Col1 | Col2 | Col3 | Counter | LoadDay | User | UserNew |
| Value 1 | Value 2 | Value 3 | NEW VALUE | NEW VALUE | NEW VALUE | NEW VALUE |
| Value 1 | Value 2 | Value 3 | NEW VALUE | NEW VALUE | NEW VALUE | NEW VALUE |
| Value 1 | Value 2 | Value 3 | NEW VALUE | NEW VALUE | NEW VALUE | NEW VALUE |
+---------+---------+---------+-----------+-----------+-----------+-----------+
Code (what I´ve tried so far):
public function loadDB($db1,$db2,$condition){
$this->db->prepare("use ".$db1."");
$sqlshow = "SHOW TABLES ";
$statement = $this->db->prepare($sqlshow);
$statement->execute();
$tables = $statement->fetchAll(PDO::FETCH_NUM);
foreach($tables as $table){
$sqlshow2 = "SHOW COLUMNS FROM ".$table[0]." ";
$statement = $this->db->prepare($sqlshow2);
$statement->execute();
$columns = $statement->fetchAll(PDO::FETCH_NUM);
foreach($columns as $column){
$sql[] = "INSERT INTO ".$db2.".".$table[0]." SELECT ".$column[0]." FROM ".$db1.".".$table[0]."; ";
}
$sql[] .= "INSERT INTO ".$db2.".".$table[0]." (`Counter`, `LoadDay`, `User`, `UserNew`) VALUES ('1', '".date("Y-m-d H:i:s")."', '".$condition."', '".$condition."')";
}
$sqlState = implode(' ', $sql);
var_dump($sqlState);
$insertStatement = $this->db->exec($sqlState);
return $insertStatement?$insertStatement:false;
}
The creation of the databases are working (not visible in my posted code here). I only get no values copied to my new tables inside my new database. What am I doing wrong here?

Answer 1

Your final SQL query comes out wrong. I suggest changing your code to somthing like this:
foreach($tables as $table){
$sqlshow2 = "SHOW COLUMNS FROM ".$table[0]." ";
$statement = $this->db->prepare($sqlshow2);
$statement->execute();
$columns = $statement->fetchAll(PDO::FETCH_NUM);
$sql[] = "INSERT INTO ".$db2.".".$table[0]." SELECT * , '1', '".date("Y-m-d H:i:s")."', '".$condition."', '".$condition."'" . " FROM ".$db1.".".$table[0]."; ";
}