Laravel Where Search Query - php

Question

I have a Spaces and an Interests table.
I am currently able to get a list of the Space Id's saved as $spaceList but I want my $query variable to retrieve a list of interests that the space_id foreign key matches one of the space_id's from my $spaceList variable.
public function index() {
$user_id = auth()->user()->id;
$user = User::find($user_id);
$spaceList = Space::where('user_id', $user_id)->pluck('space_id')->toArray();
$query = Interest::where('space_id', $spaceList);
$interests = $query->get();
return view('dashboard')->with('space', $user->space)->with('interest', $interests);
}
Thanks, I've been at this for ages now.

Answer 1

you should use whereIn instead of where
$spaceList = Space::where('user_id', $user_id)->pluck('space_id')->toArray();
$query = Interest::whereIn('space_id', $spaceList);

Answer 2

In Laravel Eloquent, this is what the Querying Relationship Existence working on
You won't need the $spaceList variable here if it's not used in other places
$query = Interest::whereHas('spaces', function($query) use ($user_id) {
$query->where('user_id', '=', $user_id);
});
Please notice, to get this work, you'll need to declare the spaces one-to-many relation in the Interest Module
Should be something like this, more details see document here
namespace App;
use Illuminate\Database\Eloquent\Model;
class Interest extends Model
{
public function spaces()
{
// space_id is the column name in your space database table
// id the the foreign-key target, generally is the primary-key of space table
return $this->hasMany('App\Space', 'space_id', 'id');
}
}