I have a model called MovementsSearch.php with the typical search($params) function that generates the data provider for actionIndex() function of the MovementsController.php.
search($params) in MovementsSearch.php:
public function search($params)
{
$query = Movements::find();
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
$this->load($params);
if (!$this->validate()) {
return $dataProvider;
}
$query->andFilterWhere([
'id_movement' => $this->id_movement,
]);
return $dataProvider;
}
actionIndex() in MovementsController.php:
public function actionIndex()
{
$searchModel = new MovementsSearch();
$dataProvider = $searchModel->search(Yii::$app->request->queryParams);
return $this->render('index', [
'searchModel' => $searchModel,
'dataProvider' => $dataProvider,
]);
}
I need to join all these tables but I can't do it. Maybe it is possible to join the data provider of each model. It will result in a big table with a lot of columns but then I know how to select the columns that I need.
administrators_offices and products_offices are many-to-many relations.
Related
I have a query in Model Autos getSpecialItems() it is used multiple times in project, but i need add in controller to filter $dataProvider.
How make this whitout write same query again in controller?
Autos.php
public function getSpecialItems()
{
return self::find()->where(['id_category' => 18])->all();
}
controller.php
public function actionIndex()
{
$searchModel = new AutosSearch();
$dataProvider = $searchModel->search(Yii::$app->request->queryParams);
//need add query here
//$dataProvider->query->$searchModel->getSpecialItems();
return $this->render('index', [
'searchModel' => $searchModel,
'dataProvider' => $dataProvider,
]);
}
You have to add filter in to your AutosSearch() model after validate():
if (!$this->validate()) {
// uncomment the following line if you do not want to return any records when validation fails
// $query->where('0=1');
return $dataProvider;
}
// grid filtering conditions you need
$query->andFilterWhere([
'id_category' => 18,
]);
The question is confusing, but I'll explain.
I have this search query from AsistenciaSearch.php
public function search($params)
{
$query = Asistencia::find();
// add conditions that should always apply here
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
$this->load($params);
if (!$this->validate()) {
// uncomment the following line if you do not want to return any records when validation fails
// $query->where('0=1');
return $dataProvider;
}
$query->joinWith('rutAlumno0');
$query->joinWith('idPlanificacion0');
// grid filtering conditions
$query->andFilterWhere([
'idAsistencia' => $this->idAsistencia,
//'idPlanificacion' => $this->idPlanificacion,
]);
$query->andFilterWhere(['like', 'asistencia', $this->asistencia])
->andFilterWhere(['like', 'rutAlumno', $this->rutAlumno])
//->andFilterWhere(['like', 'idPlanificacion', $this->idPlanificacion])
->andFilterWhere(['like', 'alumno.nombreAlumno', $this->nombreAlumno])
->andFilterWhere(['like', 'alumno.apellidoAlumno', $this->apellidoAlumno])
->andFilterWhere(['like', 'alumno.cursoAlumno', $this->cursoAlumno])
->andFilterWhere(['like', 'alumno.establecimientoAlumno', Yii::$app->user->identity->escuelaProfesor]);
return $dataProvider;
}
And this a controller function using the search query in PlanificacionController.php:
public function actionVerasistencia($id)
{
$searchModel = new AsistenciaSearch();
$dataProvider = $searchModel->search(Yii::$app->request->queryParams);
return $this->render('verasistencia', [
'model' => $this->findModel($id), //findModel from Planificacion
'searchModel' => $searchModel,
'dataProvider' => $dataProvider,
]);
}
Both Asistencia and Planificacion are related by using a primary key in Planificacion named idPlanificacion and a foreign key from that model in Asistencia using the same name.
The question is, I need to make merge with another filter, where the $id from findModel($id) is like the $idPlanificacion from the search query, like this:
public function actionVerasistencia($id)
{
$searchModel = new AsistenciaSearch();
$dataProvider = $searchModel->search(Yii::$app->request->queryParams);
return $this->render('verasistencia', [
'model' => $this->findModel($id),
'searchModel' => $searchModel,
'dataProvider' => $dataProvider->andFilterWhere('like',$id,$this->idPlanificacion),
]);
}
But I got this error:
Getting unknown property: frontend\controllers\PlanificacionController::idPlanificacion
Any solution, please?
$this inside the controller is related to the controller itself
but your are referring to idPlanificacion alias you are referring to a model attribute
could be you want retrive the value by the model eg:
$model = $this->findModel($id)
so could be
public function actionVerasistencia($id)
{
$searchModel = new AsistenciaSearch();
$dataProvider = $searchModel->search(Yii::$app->request->queryParams);
$model = $this->findModel($id);
return $this->render('verasistencia', [
'model' =>$model,
'searchModel' => $searchModel,
'dataProvider' => $dataProvider->andFilterWhere('like',$id,$model->idPlanificacion),
]);
}
I'm trying display and filter data which I got via SQL SUM operator.
I have 2 table employee and department. Table employee contains department_id filed and salary filed. I need display all department and total SUM salary for every department.
I followed this guide, but GridView does not display any data.
Here is action:
public function actionIndex()
{
$searchModel = new DepartmentFrontendSearch();
$dataProvider = $searchModel->search(Yii::$app->request->queryParams);
return $this->render('index',
[
'dataProvider' => $dataProvider,
'searchModel' => $searchModel,
]
);
}
Model:
class DepartmentFrontendSearch extends DepartmentFrontend
public $employee_count;
public $salary;
public function rules() {
return [
[['employee_count','salary','name'], 'safe']
];
}
public function search($params) {
$query = DepartmentFrontend::find();
$subQuery = Employee::find()
->select('department_id, SUM(salary) as salary_amount')
->groupBy('department_id');
$query->leftJoin(['salarySum' => $subQuery], 'salarySum.department_id = id');
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
$dataProvider->setSort([
'attributes' => [
'name',
'salary'
]
]);
$this->load($params);
if (!$this->validate()) {
return $dataProvider;
}
$query->andFilterWhere(['like', 'name', $this->name]);
$query->andWhere(['salarySum.salary_amount' => $this->salary]);
return $dataProvider;
}
GRID:
echo GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
'salary_amount',
'employee_count',
'name',
],
]);
So, can anybody tell me what I did wrong?
If You need a filter for the alias salary_amount you should add a specific var for this (do the fact salary_amount is an alias for sum(salary) the var $salary is not useful)
public $employee_count;
public $salary;
public $salary_amount;
otherwise use salary as alias too
the in your filter you are using
$query->andWhere(['salarySum.salary_amount' => $this->salary]);
But salary_amount is the result of an aggregation so you should use having(SUM(salary) = $this->salary_amount)
$query->having('SUM(salary) = ' . $this->salary_amount);
Can you help me out with implementing filters to GridView in Yii2? Right now, my rendered table does not respond to my actions (search GET params are not added, nothing changes if I enter a query to a filter input). Here's my code:
Controller:
$searchModel = new UserSearch();
$dataprovider = $searchModel->search(\Yii::$app->request->get());
return $this->render('index', [
'dataProvider' => $dataprovider,
'searchModel' => $searchModel
]);
Model (UserSearch.php):
public $fullname;
public function rules()
{
return [
[['fullname'], 'safe'],
];
}
public function search($params) {
$query = StUsers::find();
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
if(!($this->load($params) && $this->validate())) {
return $dataProvider;
}
$query->andFilterWhere(['LIKE', 'fullname', $this->fullname]);
return $dataProvider;
}
View:
GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
'id',
'fullname'
],
]);
I have the same problem when filtering in DataView. Perhaps the problem is in the client side.
Check again if your jquery called twice on your page ( browser/source code ).
May be your problem related with this also :
jQuery(...).yiiGridView is not a function
There should be no need for a solution since 4 years have passed. But, problem is in next statement:
if(!($this->load($params) && $this->validate())) {
return $dataProvider;
}
Change it to:
$this->load($params);
if (!$this->validate()) {
return $dataProvider;
}
possibly issue is jquery.min.js
You should referencing not more than once
Try to see if you have repeated.
Yii2 has a searchModel to search each field in the GridView. Is it possible to just create a single search field outside the GridView where the user can input keywords and by the time Search button is hit, the results will display in the GridView based on the keywords entered.
CONTROLLER
public function actionIndex()
{
$session = Yii::$app->session;
//$searchModel = new PayslipTemplateSearch();
$PayslipEmailConfig = PayslipEmailConfig::find()->where(['company_id'=> new \MongoId($session['company_id'])])->one();
$payslipTemplateA = PayslipTemplate::find()->where(['company_id' => new \MongoId($session['company_id'])])->andwhere(['template_name' => 'A'])->one();
$payslipTemplateB = PayslipTemplate::find()->where(['company_id' => new \MongoId($session['company_id'])])->andwhere(['template_name' => 'B'])->one();
$pTemplateModel = PayslipTemplate::find()->where(['company_id' => new \MongoId($session['company_id'])])->all();
$user = User::find()->where(['_id' => new \MongoId($session['user_id'])])->one();
$module_access = explode(',', $user->module_access);
//$dataProvider = User::find()->where(['user_type' => 'BizStaff'])->andwhere(['parent' => new \MongoId($session['company_owner'])])->all();
$searchModel = new UserSearch();
$dataProvider = $searchModel->search(Yii::$app->request->queryParams);
return $this->render('index', [
'PayslipEmailConfig' => $PayslipEmailConfig,
'dataProvider' => $dataProvider,
'payslipTemplateA' => $payslipTemplateA,
'payslipTemplateB' => $payslipTemplateB,
'searchModel' => $searchModel,
]);
}
public function actionSearchresults($keyword)
{
$session = Yii::$app->session;
if ( $keyword == '') {
return $this->redirect(\Yii::$app->request->getReferrer());
} else {
$user = User::find()->where( [ '_id' => new \MongoId($id) ] )->one();
$searchModel = new PayslipTemplateSearch();
$payslipTemplateA = PayslipTemplate::find()->where(['company_id' => new \MongoId($session['company_id'])])->andwhere(['template_name' => 'A'])->one();
$payslipTemplateB = PayslipTemplate::find()->where(['company_id' => new \MongoId($session['company_id'])])->andwhere(['template_name' => 'B'])->one();
return $this->render('searchresults', [
'searchModel' => $searchModel,
'user' => $user,
'payslipTemplateA' => $payslipTemplateA,
'payslipTemplateB' => $payslipTemplateB,
]);
}
}
I asked a question connected to this problem here: Main Search Form in Yii2
It didn't due to some complications in Kartik's Select2 search dropdown widget. Now I switched temporarily to a simple Yii2 search field.
VIEW
echo $form->field($model, '_id')->textInput(array('placeholder' => 'search'))->label(false);
MODEL
<?php
namespace app\models;
use Yii;
use yii\base\Model;
use yii\data\ActiveDataProvider;
use app\models\User;
/**
* UserSearch represents the model behind the search form about `app\models\User`.
*/
class UserSearch extends User
{
/**
* #inheritdoc
*/
public function rules()
{
return [
[[/*'_id',*/ 'creator_id'], 'integer'],
[['fname', 'lname', 'email', 'username', 'user_type'], 'safe'],
];
}
/**
* #inheritdoc
*/
public function scenarios()
{
// bypass scenarios() implementation in the parent class
return Model::scenarios();
}
/**
* Creates data provider instance with search query applied
*
* #param array $params
*
* #return ActiveDataProvider
*/
public function search($params)
{
$session = Yii::$app->session;
$query = User::find();
$query->where(['user_type' => 'BizStaff'])->andwhere(['parent' => new \MongoId($session['company_owner'])]);
$dataProvider = new ActiveDataProvider([
'query' => $query,
]);
$this->load($params);
if (!$this->validate()) {
// uncomment the following line if you do not want to any records when validation fails
// $query->where('0=1');
return $dataProvider;
}
$query->andFilterWhere([
'_id' => $this->_id,
'creator_id' => $this->creator_id,
]);
$query->andFilterWhere(['like', 'fname', $this->fname])
->andFilterWhere(['like', 'lname', $this->lname])
->andFilterWhere(['like', 'email', $this->email])
->andFilterWhere(['like', 'username', $this->username])
->andFilterWhere(['like', 'user_type', $this->user_type]);
return $dataProvider;
}
}
Do you have any idea on how to I implement a single search? It's kind of a smarter search since it can search everything in the database table based on keywords inputted.
EDIT
When I search a keyword, say for example 'hello', it then gives me this url and error after hitting enter key:
URL:
http://localhost/iaoy-dev/web/index.php?r=payslip-template%2Fsearchresults&PayslipTemplateSearch%5B_id%5D=hello
Error message:
Bad Request (#400) Missing required parameters: id
Help.
I had the same problem and my solution is:
Model
Extend your UserSearch Model with a search parameter
class UserSearch extends User
{
public $searchstring;
...
Enable passing the variable
public function rules()
{
return [
...
[['searchstring'], 'safe'],
];
}
Change your search-Method (beware: the searchfields are combined with orFilterWhere, depends on your needs).
$query->orFilterWhere(['like', 'fname', $this->searchstring])
->orFilterWhere(['like', 'lname', $this->searchstring])
->orFilterWhere(['like', 'email', $this->searchstring])
->orFilterWhere(['like', 'username', $this->searchstring])
->orFilterWhere(['like', 'user_type', $this->searchstring]);
View (could be also layout)
Extend your form with a search-input. You can style the input-field by yourself, this is just an example:
<?php
/* #var $searchModel app\models\UserSearch */
echo $form->field($searchModel, 'searchstring', [
'template' => '<div class="input-group">{input}<span class="input-group-btn">' .
Html::submitButton('GO', ['class' => 'btn btn-default']) .
'</span></div>',
])->textInput(['placeholder' => 'Search']);
?>
Controller
Also check for the value of $searchstring after posting the form.
public function actionIndex()
{
...
$searchModel = new UserSearch();
$dataProvider = $searchModel->search(Yii::$app->request->queryParams);
...
return $this->render('index', [
'searchModel' => $searchModel,
'dataProvider' => $dataProvider,
]);
}
That's it.