I am writing a test to count the number of pages in PDFs stored in a folder on a server. I have been able to get it to work on my local machine, I am unable to get it to work on a remote file.
This is my code that works on local files:
require_once 'C:\..\application\libraries\fpdi\fpdf.php';
require_once 'C:\..\application\libraries\fpdi\fpdi.php';
$pathToFile = 'C:\Users\..\Desktop\filename.pdf';
$pdf = new FPDI();
$pageCount = $pdf->setSourceFile($pathToFile);
echo $pageCount;
But if I change the $pathToFile to a link on a remote server, I get an error message.
I tried this:
$pdfname = 'http://../filename.pdf';
$pdftext = file_get_contents($pdfname);
$num = preg_match_all('/\/Page\W/', $pdftext, $dummy);
echo 'Num: ' . $num;
But again, when I use a local file, it works fine, but the remote file gives me an error (failed to open stream: HTTP request failed! HTTP/1.1 403 Forbidden).
From searching online, it seems like that is a common error and I've seen code to use curl, but it makes no sense to me and I can't get it to work either. I saw code to use pdfinfo, but the link in that post is going to another site.
I don't want to have to download anything, so using something like Imagick is not an option either.
All I'm looking for is a simple page number from a file on a remote server. Any help would be much appreciated.
Related
This question is asked before but non of the answers worked for me.
I use the following code to directly copy a file from a remote server to my server,
<?php
set_time_limit(0); //Unlimited max execution time
$remote_file_url = $_GET['url'];
$ext = pathinfo($remote_file_url, PATHINFO_EXTENSION);
$name = basename($remote_file_url);
if(isset($ext)){
$local_file = 'download/'.$name.'.'.$ext;
}
else
$local_file = 'download/'.$name;
$copy = copy( $remote_file_url, "1.mp4" );
if( !$copy ) {
echo "Doh! failed to copy $file...\n";
}
else{
echo "WOOT! success to copy $file...\n";
}
?>
It works well but it doesn't copy the files I get from Youtube. I use 1-Click Youtube Video Downloader extension for Firefox which gives me direct link to youtube videos. I can use these direct links in browser and Internet Download Manager as well.
For example the direct url of
https://www.youtube.com/watch?v=xPXrJwQ5lqQ
is
https://r6---sn-ab5l6nzy.googlevideo.com/videoplayback?ipbits=0&requiressl=yes&sparams=dur,ei,expire,id,initcwndbps,ip,ipbits,ipbypass,itag,lmt,mime,mip,mm,mn,ms,mv,pl,ratebypass,requiressl,source&ei=3DNOWfq4CImGc9rxvcgO&signature=3D188D073D872381433A45462E84928383D10D02.4E0AF7D777E76AA19A576D42983A81F4E62EF84D&lmt=1472135086539955&mime=video%2Fmp4&ratebypass=yes&id=o-ABaoUEn3pBt5SLXdWXlrzCdteMLfLPizrRTPoakDoLSX&expire=1498318908&source=youtube&dur=119.211&itag=22&pl=20&ip=162.217.31.128&key=cms1&redirect_counter=1&req_id=ce038b9993a9a3ee&cms_redirect=yes&ipbypass=yes&mip=159.203.89.210&mm=31&mn=sn-ab5l6nzy&ms=au&mt=1498297234&mv=m
The problem is my code can't copy this file to my server. I would like to know of there is any way to resolve such urls?
The error is
failed to open stream: HTTP request failed! HTTP/1.1 403 Forbidden in /home/...
thanks in advance.
Well, I have no idea why that happened. (Would it be expired?I hope not) I just managed to try another link for the above video (copy the link using right click) in your code as the $remote_file_url and it worked as expected
How did I get that link?
I've used the underlined library : YouTube-Downloader to the 1-Click Youtube Video Downloader extension (it is inherently used by that extension ) this way you will have more control over the process. Then after hosting the files in your web server. Simply run the index.php and when you use it, you'll get something like :
Then you can automate this last part to suit your needs.
That doesn't mean that all videos could be smoothly downloaded with this method. Because of the used videos that have signatures issue or that are recently uploaded issue and here's the list of issues of Youtube-Downloader
For that There is a fix that is somewhat involved: youtube-dl-php, it is based on a sound principle : there is a very good command line utility to download YouTube videos called youtube-dl : here is the download page
Basically, you'll just call it using php. Then, notice that you'll need its path installed in order for the following to work
After you install Composer, go to your web project folder
and run composer require norkunas/youtube-dl-php as explained in the Github page
When running its example, I've get an error
proc_open() 267 CreateProcess failed
I've never dealt with Symphony before and I've found it particularly interesting to play with YoutubeDl.php and redefine the $arguments passed to createProcess and commenting out much of the less useful configuration options to get rid of that error, give it more time to run with
ini_set('max_execution_time', 300);
And yikes it was downloaded.
You don't have to follow this unless you couldn't figure out a better way. It is just supposed to give you an idea of where lies the problem if you havn'et figure it out. And if you have that problem in the first place.
private function createProcess(array $arguments = [])
{
array_unshift($arguments, $this->binPath ?: 'youtube-dl');
$process = new Process("youtube-dl https://www.youtube.com/watch?v=nDMwW41AlSI");
/*$process->setEnv(['LANG' => 'en_US.UTF-8']);
$process->setTimeout($this->timeout);
$process->setOptions($this->processOptions);
if ($this->moveWithPhp) {
$cwd = sys_get_temp_dir();
} else {
$cwd = $this->downloadPath ?: sys_get_temp_dir();
}
$process->setWorkingDirectory($cwd);*/
return $process;
}
Or you can just write your own code that calls youtube-dl, good luck!
I have a script and I don't know why and how it works - one reason for that is I found contradicting information about file_get_contents.
I have three (internal) webservers - all set up the same way, running the same software.
I need to count the number of files in one specific folder on each server (in order to get the number of users logged into a certain application).
For the local server my file counting PHP script is called by a simple include and for the two remote servers I use file_get_contents.
In both cases I refer to the same PHP file. That works - I get the correct number of files for the folder on each server.
Sometimes you read file_get_contents returns just the file content but does not execute the file. In my case the file is executed and I get the correct number of files. So, I'm a bit confused here why my scripts actually work.
My scripts were saved on one server. I want to be more flexible and be able to call the scripts from each server. Therefore I created a new virtual directory on a network folder and moved the script files there, the virtual folder has the same set up on each server. I had to change my script slightly to get the same result again. Instead of a return $num I now have echo $num. If I use return I won't get a result, if I use echo the correct number of files is given. I would prefer to receive the result via return - but I don't know why this doesn't work anymore in the new context.
script which shows the number of files:
function getUserNum($basis_url_server, $url_vaw_scripte, $script_number_users)
{
$serverName = strtoupper($_SERVER['SERVER_NAME']);
//local server
if(strpos(strtoupper($basis_url_server),$serverName) !== false)
{
$numUsers = (include($script_number_users));
}
//remote server
else
{
$path = $basis_url_server.$url_vaw_scripte.$script_number_users;
$numUsers = file_get_contents($path);
//include($path);
}
return $numUsers;
}
echo getUserNum($basis_url_server1, $url_vaw_scripte, $script_number_users)."($label_server1)";
echo getUserNum($basis_url_server2, $url_vaw_scripte, $script_number_users)."($label_server2)";
echo getUserNum($basis_url_server3, $url_vaw_scripte, $script_number_users)."($label_server3)";
script for counting the files (refered as $script_number_users above)
<?php
// 'include' only contains $fadSessionRepository = "E:\Repository\Session"
include dirname(__DIR__).'/vaw_settings.php';
$fi = new FilesystemIterator($pfadSessionRepository, FilesystemIterator::SKIP_DOTS);
$number = (iterator_count($fi)-1)/2 ;
//return $number;
echo $number;
?>
file_get_contents() will execute a GET if given a url, and will read a file if given filesystem path. It is like 2 different function from the same call.
You are actually building a primitive REST webservice instead of actually loading the files as you though, the remote files are executed and you get the output that you would see if you manually loaded them from a browser
file_get_contents() will return the raw content of a local file. For remote files it will return what the webserver delivers. If the webserver executes the script in the file it will get the result of that script. If the webserver doesn't execute the script in the file (due to a misconfiguration for example) you will still get the raw content of the remote script.
In your case I'd just remove the include path and just fetch all scripts over http. It reduces the complexity and the overhead of calling one of three scripts via http instead of loading it directly is negligible.
I want to store some data retrieved using an API on my server. Specifically, these are .mp3 files of (free) learning tracks. I'm running into a problem though. The mp3 link returned from the request isn't to a straight .mp3 file, but rather makes an ADDITIONAL API call which normally would prompt you to download the mp3 file.
file_put_contents doesn't seem to like that. The mp3 file is empty.
Here's the code:
$id = $_POST['cid'];
$title = $_POST['title'];
if (!file_exists("tags/".$id."_".$title))
{
mkdir("tags/".$id."_".$title);
}
else
echo "Dir already exists";
file_put_contents("tags/{$id}_{$title}/all.mp3", fopen($_POST['all'], 'r'));
And here is an example of the second API I mentioned earlier:
http://www.barbershoptags.com/dbaction.php?action=DownloadFile&dbase=tags&id=31&fldname=AllParts
Is there some way to bypass this intermediate step? If there's no way to access the direct URL of the mp3, is there a way to redirect the file download prompt to my server?
Thank you in advance for your help!
EDIT
Here is the current snippet. I should be echoing something, correct?
$handle = fopen("http://www.barbershoptags.com/dbaction.php?action=DownloadFile&dbase=tags&id=31&fldname=AllParts", 'rb');
$contents = stream_get_contents($handle);
echo $contents;
Because this echos nothing.
SOLUTION
Ok, I guess file_get_contents is supposed to handle redirects just fine, but this wasn't happening. So I found this function: https://stackoverflow.com/a/4102293/2723783 to return the final redirect of the API. I plugged that URL into file_get_contents and volia!
You seem to be just opening the file handler and not getting the contents using fread() or another similar function:
http://www.php.net/manual/en/function.fread.php
$handle = fopen($_POST['all'], 'rb')
file_put_contents("tags/{$id}_{$title}/all.mp3", stream_get_contents($handle));
I am writing some php script to update the code on my sites. In order to do that I have written the following lines which checks for the update version and bring the name from where I use to distribute my updates ans then creates the link of that name. I have done something like this.
$filename = "http://www.hf-live.com/codeupdate/Get_Files_Name.php";
$contents = file_get_contents($filename);
echo $contents;
I am getting this error
failed to open stream: No such file or directory.
Even though the file is present still I am getting the same error. I have turned on my allow_url_fopen to on. The above code is working from my local host but not from the server. I have to update a major bug fix and I am stuck.. Please someone help me soon..
remove extra .php from url
$filename = "http://www.hf-live.com/codeupdate/Get_Files_Name.php";
You will get error if you are doing this way...
$filename = "marynyhof.com/Info.php"; // will give you error, which exactly you are getting
use full url like this
$filename = "http://www.marynyhof.com/Info.php"; //will work
I'm working with wordpress locally and for some reason when I call getimagesize() from page.php to retrieve the sizes it does not work. I get the warning:
getimagesize(http://localhost:8080/wordpress/wp-content/themes/minimize/_/images/img-2.jpg )
[function.getimagesize]: failed to open stream: HTTP request failed! HTTP/1.0 404
Not Found in C:\wamp\www\wordpress\wp-content\themes\minimize\page.php on line 13
The actual code that is calling it is:
$items = get_post_meta($post->ID, 'test');
foreach($items as $item) {
$img_pth = 'http://localhost:8080/wordpress/wp-content/themes/HTML5-Reset-Wordpress-Theme/_/images/'.$item;
list($width, $height) = getimagesize($img_pth);
echo '<img src="'.$img_pth.'" height="'.$height.'" width="'.$width.'">';
}
I'm new to working with PHP so I wouldn't be surprised if it is something very obvious with my code, but I think what I'm trying to do is pretty easy and straight forward. I've tried changing localhost to 127.0.0.1 as I saw in another thread but to no avail. The images are being rendered, so the image paths are correct, but the function is failing. Thanks for any help I can get...
I had the same problem.
Use relative path to the file instead.
You are using wordpress, so it's probably one of two:
php configuration (php.ini)
one of the plugins you're using
Please see my full answer at this link