How can I check if an object method exists? [duplicate] - php

Question

This question already has answers here:
Is there a way to check if a function exists within a class?
(3 answers)
Check if method exists in the same class
(4 answers)
Closed 3 years ago.
I want to use some code only if the method getProductgroup exists.
My first approach:
if(isset($item->getProductgroup())){
$productgroupValidation = 0;
$productgroupId = $item->getProductgroup()->getUuid();
foreach($dataField->getProductgroup() as $productgroup){
$fieldProductgroup = $productgroup->getUuid();
if($productgroupId==$fieldProductgroup){
$productgroupValidation = 1;
}
}
I got the error message:
Compile Error: Cannot use isset() on the result of an expression (you
can use "null !== expression" instead)
if(($item->getProductgroup())!==NULL){
$productgroupValidation = 0;
$productgroupId = $item->getProductgroup()->getUuid();
foreach($dataField->getProductgroup() as $productgroup){
$fieldProductgroup = $productgroup->getUuid();
if($productgroupId==$fieldProductgroup){
$productgroupValidation = 1;
}
}
But like this I also get an error message:
Attempted to call an undefined method named "getProductgroup" of class
"App\Entity\Documents".

Answer 1

You can use the function method_exists to check if the method is existing in a class or not. for example
if(method_exists('CLASS_NAME', 'METHOD_NAME') )
echo "it does exist!";
else
echo "nope, it is not there...";
In your code try
if(method_exists($item, 'getProductgroup')){
$productgroupValidation = 0;
if(method_exists($item->getProductgroup(), 'getUuid'))
{
$productgroupId = $item->getProductgroup()->getUuid();
foreach($dataField->getProductgroup() as $productgroup)
{
$fieldProductgroup = $productgroup->getUuid();
if($productgroupId==$fieldProductgroup){
$productgroupValidation = 1;
}
}
}
}