If statement to display Post meta - php

Question

I have a taxonomy named talent_cat which is the category of said post, has 4 values: modelos, atores, musica, djs and inside each individual talent_cat there are these post meta keys:talent_id_1495127471815 for modelostalent_id_1495127471816 for atorestalent_id_1495127471817 for musica talent_id_1495127471818 for djs
How can I build a conditional to show the right post meta depending on the talent_cat of said post? So if the post belongs to talent_cat = modelos it returns the talent_id_1495127471815 and not the other values.
I tried this but unsuccessfully:
$talent_data = get_the_term_list( $post->ID, 'talent_cat');
switch( $talent_data ) {
case 'modelos':
echo get_post_meta(get_the_ID(), 'talent_id_1495127471815', true);
break;
}
Thanks.

Answer 1

The function get_the_term_list returns HTML but you need to get an array or object to check your statement. You need to use get_the_terms function instead. Your code should look like this:
global $post;
$talent_data = get_the_terms( $post->ID, 'talent_cat');
// check for errors or empty data
if ( is_wp_error( $talent_data ) || empty( $talent_data ) ) {
return;
}
foreach ( $talent_data as $term ) {
// you can check for name or slug or id
switch( $term->slug ) {
case 'modelos':
echo get_post_meta($post->ID, 'talent_id_1495127471815', true);
break;
}
}