How to rezolve this error in PHPf for sotring probleme - php

I've tried to make a apply a simple sorting technique like Insertion method, and I've got this annoying error.
I'm using PHP 7.
<br />
<b> Notice: Array to string conversion in <b>[...][...]</b> on line <b>21</b><br /> Array
The line 21 is where I call echo Interschimbare
The code is as following:
<?php
function Interschimbare(array $Vector) : array{
$N = count($Vector);
for($i = 0; $i < $N - 1; $i++)
{
for($j = $i + 1; $j < $N; $j++)
{
if($Vector[$i] > $Vector[$j])
{
$aux = $Vector[$i];
$Vector[$i] = $Vector[$j];
$Vector[$j] = $aux;
}
}
}
return $Vector;
}
$test = [3, 0, 2, 5, -1, 4, 1];
//print_r(Interschimbare($test)); // with this line works just fine
echo Interschimbare($test);
With echo doesn't work but with print_r works just fine

:)
your variable $Vector is an array so you need to convert it to string in order to use echo.
for example:
echo implode(",",Interschimbare($test));
output will be:
-1,0,1,2,3,4,5

Related

Change variable value and push it after loop

I have code like this
$jumlahcolspan = array();//new array
$horizontaldeep = 5;
$level = array(5,4,3,8,7);//old array
for ($j = 0; $j < $horizontaldeep; $j++) {
$jml = 1;
for ($i = $j + 1; $i < $horizontaldeep; $i++) {
$jml = $level[$i] * $jml;
}
array_push($jumlahcolspan, $jml);
}
To put it simple, what I want to get is to multiply old array value which index start from $i+1 to the last and push it to another array.
So, its some thing like this
old array: [5, 4, 3, 8, 7]
new array: [4*3*8*7, 3*8*7, 7, 1]
I've tried this but it doesn't work also
for ($j = 0; $j < $horizontaldeep; $j++) {
$jml = 1;
for ($i = $j + 1; $i < $horizontaldeep; $i++) {
global $jml;
$jml = $level[$i] * $jml;
}
array_push($jumlahcolspan, $jml);
}
Tried this too but not work also.
for ($j = 0; $j < $horizontaldeep; $j++) {
array_push($jumlahcolspan, array_product(array_slice($level, $j+1)));
}
Note: now I'm reviewing my full code. May be something not right in my code.
I think the problem is related to $jml variable but I can't figure how to solve that. Can anyone help me?
One approach would be to use a Recursive Function to achieve that goal. The Recursive Function below demonstrates how. And, by the way, you may as well quick-test it here.
<?php
$oldArray = [5,4,3,8,7];
function arrayMatrixMultiply(array $old, array &$newArray=[]){
$result = 1;
foreach($old as $key=>$value){
if($key != 0){
$result*=$value;
}
}
$newArray[] = $result;
array_splice($old, 0, 1);
if(!empty($old)){
// JUST RECURSE TILL THE $oldArray BECOMES EMPTY
arrayMatrixMultiply($old, $newArray);
}
return $newArray;
}
$newArray = arrayMatrixMultiply($oldArray);
var_dump($newArray);
// PRODUCES::
array (size=5)
0 => int 672
1 => int 168
2 => int 56
3 => int 7

How to calculate Diagonal difference in PHP?

I have a N*N Matrix.Now i want to know the diagonal difference of this Matrix.What will be the best approach of this solution?
I am trying with given approach:
Such as it is 3*3 Matrix say it is:
11 15 85
66 72 21
14 21 47
the diagonal simple formula will be:
firstD= (11+72+47) = 130
secondD = (85+72+14)= 171
diagonalDiff = |firstD - secondD| = |130-171| = 41
If I count every row such as first to find out firstD (First row's first value + Sec row's Sec value + Third row's third value+..).This is my thinking.
Can anyone tell me best approaches?
Try this:
$arr = array(
array(11, 15, 85),
array(66, 72, 21),
array(14, 21, 47),
);
$arrDiag = count($arr);
$firstD = 0;
$secondD = 0;
$i = 0;
for($j = 0; $j < $arrDiag; $j++){
$firstD += $arr[$i++][$j];
$secondD += $arr[$arrDiag - $i][$j];
}
echo abs($firstD - $secondD);//41
Model your matrix with a multi-dimensional array and iterate through it. The easiest way should be the following:
<?
$matrix = array(array(1,2,3),array(4,5,6),array(7,8,9)); //Insert or define your matrix here..
$n = count($matrix); //Size of matrix, thanks to VolkerK
$firstD = 0;
$lastD = 0;
for($i = 0; $i < $n; $i++){
$firstD += $matrix[$i][$i];
$lastD += $matrix[$i][$n-$i-1];
}
echo $firstD."\n";
echo $lastD;
Here is a pseudo code for your problem using one simple loop:
// $array - predefined 2 dimentional array with $N rows and $N columns
$result = 0;
for ($i=0;$i<$N;$i++) {
$result += ($array[$i,$i] - &array[$i,$N-$i-1]);
}
return echo abs($result);
that way you can do the calculation in one pass, and do a diff between two elements in each row insead of calculation the sum of each diagonal
Try this:
function diagonalDifference($arr) {
$left = 0;
$right = 0;
$i = 0;
foreach($arr as $ar){
$left+= $ar[0+$i];
$right+= $ar[count($ar) - (1+$i)];
$i++;
}
return abs($left - $right);
}
Try this
$result=0;
for($i=0;$i<=count($arr)-1;$i++){
$result= $result+($arr[$i][$i])-($arr[(count($arr)-1-$i)] [$i]);
}
return abs($result);
This is the code you need:
$first = 0;
$second = 0;
for($i = 0; $i < N; $i++) {
for($j = 0; $j < N; $j++) {
if($i == $j) {
$first += $matrix[$i][$j];
} else if($i + $j == N) {
$second += $matrix[$i][$j];
}
}
}
$diagonalDiff = abs($first - $second);
Where $matrix is a N*N array
Just using the function array_reduce:
function diagonalDifference($arr) {
$i = 0;
$n = count($arr);
return abs(array_reduce($arr,
function ($c, $str) use (&$i, $n ) {
$i++;
return $c + $str[$i-1] - $str[$n-$i];
}, 0));
}
demo
you can try this :
$first_diag=$second_diag=0;
$matrix=array(array(11,15,85),array(66,72,21),array(14,21,47));
foreach($matrix as $index=>$sub_array){
$first_diag +=$sub_array[$index];
$second_diag +=$sub_array[count($matrix)-1-$index];
}
print abs ($first_diag-$second_diag);
For one you can use a matrix library like Math_Matrix. But if this is the only operation you are gona need then it's best to write a generalized function for this using the same method you quoted yourself.
function diagonalDiff($n){
$firstD = 0;
$secondD = 0;
for($i=0;$i<$n;$i++){
for($j=0;$j<$n;$j++){
if($i == $j) {
$first += $matrix[$i][$j];
} else if($i + $j == $n) {
$secondD += $matrix[$i][$j];
}
}
}
return abs($firstD-$secondD);
}
Should give you the answer you need for a matrix of a given size $n. (Only square Matrixes ofcourse :) )
Another better solution and it's easy to understand:
<?php
$arr = array(
array(11, 15, 85),
array(66, 72, 21),
array(14, 21, 47),
);
$arrDiag = count($arr);
$firstD = 0;
$secondD = 0;
$i = 0;
for($j = 0; $j < $arrDiag; $j++){
$i++;
$firstD += $arr[$j][$j];
$secondD += $arr[$arrDiag - $i][$j];
}
echo abs($firstD - $secondD);
?>
DEMO
Recently solved this question in Hacker Rank.
<?php
$m=array(array(3,4,-1,11,2),
array(-3,2,1,6,9),
array(3,4,6,5,-2),
array(1,9,9,7,-3),
array(12,9,16,7,-3));
echo count($m)."<br>";
$i=0;
$j=0;
$ek=0;
$k=0;
$n=1;
$es=count($m)-1;
for($i=0;$i<count($m);$i++)
{
for($j=0;$j<count($m);$j++)
{
echo $m[$i][$j]." ";
}
echo "<br>";
}
echo "<br>";
for($k=0;$k<count($m);$k++)
{
for($n=0;$n<count($m);$n++)
{
if($k==$n){
$ek=$ek+$m[$k][$n];
}
}
echo "<br>";
}
echo "<hr>";
$p=0;
for($k=0;$k<count($m);$k++)
{
echo $m[$k][$es-$p]."<br> ";
$p++;
}
?>
Sorry I used different variable names, I had to take this to my vs code.
$b = array(
array(1,2,5),
array(3,4,5),
array(3,4,5)
);
//So for each diag
echo $b[0][0] + $b[1][1] + $b[2][2]; //to sum the first diag
echo $b[0][2] + $b[1][1] + $b[2][0]; //to sum the second diag
//notice the pattern 00, 11, 22 vs 02,11, 20. hence why I have written the function below
function difference($b){
$d1 = 0;
$d2 = 0;
$count = count($b);
for($i=0; $i<$count; $i++){
$d1 += $b[$i][$i];
$d2 += $b[$i][$count-1-$i];
}
return abs($d1 - $d2);
}
I had the same issue, the instructions was given by the site, mislead me. However, I solved it in this way,
$n = count and store the length of input array
//define variables to store first diagonals and second diagonals
$fd = 0;
$sd = 0;
//loop through the 2D array with $i increment
$j = get an array from the main array
//in each iteration
$pd += get the values from the left to the right and add;
$sd += get the values from the right to the left and add;
}
find absolute difference between the sums using built in abs function and return it;
I think this would help someone

warning occuring in php word occurence

I have written the following code to count the number of string occurrences in a given file.
PHP
<?php
$p = fopen("g.txt", "r");
$q = fread($p, filesize("g.txt"));
$t = explode(" ", $q);
$m = explode(" ", $q);
$i = 0;
$j = 0;
$r = 0;
$count = 0;
$c = count($t);
$d = array();
echo "count of".
"<br/>";
for ($i = 0; $i < $c; $i++) {
for ($j = $i; $j < $c; $j++) {
if ($t[$i] == $t[$j]) {
$count = $count + 1;
}
}
for ($r = $i + 1; $r < $c; $r++) {
if ($t[$i] == $t[$r])
unset($t[$r]);
}
echo $t[$i].
"=".$count.
"<br/>";
$count = 0;
}
?>
I am getting a notice of undefined offset on line numbers 17 and 24, though my output is coming out to be correct. Can you please help me in rectifying the above problem?
The problem is that you are deleting items from the array $t. You saved the count in $c, but the actual count will change by your last inner loop.
Even if you replace $c by count($t) everywhere, it will go wrong, because the last loop should be in reverse order, otherwise you skip items. For instance if you have the list 'a', 'b', 'c'. then when you delete 'b' and increment $r, you will not check 'c' at all.
So, if I fix those things, your code becomes as below. Although I didn't really check it for other issues. Frankly, I don't really get what is should do. ;-)
<?php
$p=fopen("g.txt","r");
$q=fread($p,filesize("g.txt"));
$t=explode(" ",$q);
$m=explode(" ",$q);
$i=0;
$j=0;
$r=0;
$count=0;
$d=array();
echo "count of"."<br/>";
for($i=0; $i<count($t); $i++)
{
for($j=$i; $j<count($t); $j++)
{
if($t[$i]==$t[$j])
{
$count=$count+1;
}
}
for($r=count($t) - 1; $r > $i; $r--)
{
if($t[$i]==$t[$r])
unset($t[$r]);
}
echo $t[$i]."=".$count."<br/>";
$count=0;
}
?>
In conclusion, you should do more tests. If the outcome of this script was okay, then it was by accident.

Facing error in LCS function in php

I am coding LCS(longest common subsequence) in php program by using recursive approach. I have the following code:
<?php
$lcsTbl = array(array(128),array(128));
$backTracks = array(array(128),array(128));
$str1 = 'asdvadsdad';
$str2 = 'asdasdadasda';
$len1 = strlen($str1);
$len2 = strlen($str2);
echo LCS_Length($lcsTbl, $backTracks, $str1, $str2, $len1, $len2); //longest common sub sequence
echo '<br/>';
function LCS_Length(&$LCS_Length_Table, &$B, &$s1, &$s2, &$m, &$n)
{
//reset the 2 cols in the table
for($i=1; $i < $m; $i++) $LCS_Length_Table[$i][0]=0;
for($j=0; $j < $n; $j++) $LCS_Length_Table[0][$j]=0;
for ($i=1; $i <= $m; $i++) {
for ($j=1; $j <= $n; $j++) {
if ($s1[$i-1]==$s2[$j-1])
{ $LCS_Length_Table[$i][$j] = $LCS_Length_Table[$i-1][$j-1] + 1; $B[$i][$j] = '\\';}
else if ($LCS_Length_Table[$i-1][$j] >= $LCS_Length_Table[$i][$j-1])
{ $LCS_Length_Table[$i][$j] = $LCS_Length_Table[$i-1][$j]; $B[$i][$j] = '|';}
else
{ $LCS_Length_Table[$i][$j] = $LCS_Length_Table[$i][$j-1]; $B[$i][$j] = '-';}
}
}
return $LCS_Length_Table[$m][$n];
}
To print the LCS, I call the following function:
$x = str_split($str1);
echo lcs_print($backTracks, $str1, $len1, $len2); //print longest common sub sequence
function lcs_print(&$B, &$x, &$i, &$j)
{
if( $i == 0 || $j == 0 )
return;
if( $B[$i][$j] == '\\' ) {
echo $x[$i-1];
lcs_print( $B, $x, $i = $i-1, $j = $j-1 );
} else if( $B[$i][$j] == '|' ) {
lcs_print( $B, $x, $i = $i-1, $j );
} else {
lcs_print( $B, $x, $i, $j = $j-1 );
}
}
?>
This code counts the total lengthof LCS correctly but gives "Notice: Undefined offset: -1" on every call of this line in print function echo $x[$i-1]; and prints nothing. I have tried almost everything to split the string of $str1 and then pass it to function, but nothing works. It does not print LCS string because something is wrong with this line of code echo $x[$i-1]; which I am unable to get. Please help.
Note: The pseudocode of the above code has been taken from book of Thomas H. Cormen, "Introduction to Algorithms 3rd Edition". I am writing it into PHP with the intention of extending it so that it can print LCS of more than two strings. I'll appreciate if anyone shares idea of How can I extend this code so that it can print LCS of an array with multiple strings like $array{'sdsad','asddaw','asd',...n}. Later, I intend to convert the entire program into MATLAB.
There are issues in your LCS_length
1.if ($s1[$i-1]==$s2[$j-1]) ,it should have been if ($s1[$i]==$s2[$j])
2.your boundary condition ($j=0; $j < $n) is unclear, you need to include this upperbound
and you are trying to print it calling this lcs_print($backTracks, $str1, $len1, $len2).
It should have been ($j=0;$j<=n;$j++)
I think these changes will solve the problem.
I haven't done coding in PHP so can't say about the syntaxes.
I have solved the error: I have placed echo $x[$i-1]; before lcs_print( $B, $x, $i = $i-1, $j = $j-1 ); in lcs_print function, all is working fine now.

Notice: Undefined offset: 2

I'm new to php and I have done an example in php book. In there I got below notice. How to prevent this notice ?
<?php
require_once('AddingMachine.php');
$arrayofnumbers = array(100,200);
$objectname = new AddingMachine();
$objectname->addNumbers($arrayofnumbers);
?>
and
<?php
Class AddingMachine
{
private $total = 0;
function addNumbers(array $numbers)
{{
for($i=0;$i<=sizeof($numbers);$i++)
{
$this->total = $this->total + $numbers[$i];
}
echo $this->total;
}
}
}
Change your loop from
for($i=0; $i <= sizeof($numbers); $i++)
to
for($i=0; $i < sizeof($numbers); $i++)
Also preferable to use count.
for($i=0; $i < count($numbers); $i++)
The problem is with the <= sizeof($numbers) (which is equal to count($numbers). It will give you the total count of array elements, which is always one more than the maximum index, because arrays begin counting at 0.
Simply replace the <= with < and you'll be fine.

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