PHP to query table with where statment column names defined by array - php

Question

I have a query that returns 2 arrays they can have anywhere from 0 to 5 results for each array. i need to take the results of the array and use them to run a second query where the columns in the where statment are assigned by the array
here is the base code
$result = $conn->query("SELECT UsedQty,NewQty FROM Legend where Name like '$Use%'");
while($row = $result->fetch_assoc()) {
$UsedQty[$g]=$row['UsedQty'];
$NewQty[$g]=$row['NewQty'];
$g++;
}
$result = $conn->query("select * from remainder where po = '$po' and
(($UsedQty[0]>0 or $UsedQty[1]>0 or $UsedQty[2]>0) or
($NewQty[0]>0 or $NewQty[1]>0 or $NewQty[2]>0)) limit $cnt,1");
and as long as there are values for all of the variable is works, but if there are only 1 or 2 (or 0) values for the array it will not work
i have also tried
$result = $conn->query("select * from remainder where po = '$po' and
($UsedQty[$g]>0) limit $cnt,1");
it has to be done in a single query as the variable $cnt is keeping track of records and order---closed system so security injections are not an issue

Answer 1

Pad the arrays with the desired number of elements before executing the query. Something like this might do the trick:
while ($g < [desired_count]) {
array_push($UsedQty,0);
array_push($NewQty,0);
$g++;
}
The [desired_count] should be set to the number of elements that will be tested in the WHERE clause.
It is not apparent how the query will return 0-5 rows, (based on "2 arrays [that] can have anywhere from 0 to 5 results for each array"). The query will return 1 array; the while loop creates 2 arrays. Perhaps this ($UsedQty[0]>0 or $UsedQty[1]>0 or $UsedQty[2]>0) is a typing shortcut and the intention is to test 5 values? In that case [desired_count] will be 5.