Multidimensional array value if exits - php

Question

I want to bring results that have a status 1 in the array.(Sorry i don't speak english)
My array is;
[10100002] => Array
(
[0] => stdClass Object
(
[ID] => 664
[barcode] => 10100002
[status] => 0
)
[1] => stdClass Object
(
[ID] => 1339
[barcode] => 10100002
[status] => 0
)
)
[10100004] => Array
(
[0] => stdClass Object
(
[ID] => 1116
[barcode] => 10100004
[status] => 1
)
[1] => stdClass Object
(
[ID] => 1826
[barcode] => 10100004
[status] => 0
)
)
in 10100002 two status is 0 but second array found status 1. if the status value is 1 in multiple arrays i like result this ;
[10100004] => Array
(
[0] => stdClass Object
(
[ID] => 1116
[barcode] => 10100004
[status] => 1
)
[1] => stdClass Object
(
[ID] => 1826
[barcode] => 10100004
[status] => 0
)
)
My code is here;
$result = array();
foreach ($fetch_data as $value) {
if($value->status== 1)
$result[$value->barcode][] = $value;
}
// this give me only one result. Output;
[10100004] => Array
(
[0] => stdClass Object
(
[ID] => 1116
[barcode] => 10100004
[status] => 1
)
)

Answer 1

You can use array_walk
$arr = Array(
'10100002' => Array
(
'0' => Array
(
'ID' => 664,
'barcode' => 10100002,
'status' => 0
),
'1' => Array
(
'ID' => 1339,
'barcode' => 10100002,
'status' => 0
)
),
'10100004' => Array
(
'0' => Array
(
'ID' => 1116,
'barcode' => 10100004,
'status' => 1
),
'1' => Array
(
'ID' => 1826,
'barcode' => 10100004,
'status' => 0
)
)
);
$res = [];
array_walk($arr, function($v, $k) use (&$res){
foreach($v as $key => $value){
if($value['status']){
!empty($value['status']) ? ($res[$k][] = (object)$v[$key]) : '';
}
}
});
echo '<pre>';
print_r($res);
Output
Array
(
[10100004] => Array
(
[0] => stdClass Object
(
[ID] => 1116
[barcode] => 10100004
[status] => 1
)
)
)
LIVE DEMO