Database Query Syntax - php

Question

Solution: I used db facade, DB::select() to run raw sql query.
I have two tables users(id, username, city, country) and friends(id, user_id, friend_id, status). The 'users' table stores the user information and 'friends' table store the currently logged in user's id, friend_id is the id of the user who sent a friend request to the current user and status will be 'received'. I want to show information of the users to sent requests to the current user. Is my database query syntax correct? I can see correct output if I don't use the nested subquery. Thanks in advance!
My DB query:
$friendrequests = DB::table('users')->select(['username','city','country'])->where('id',DB::table('friends')->select('friend_id')->where([['status','received'],['user_id',$user->id]]));
My html:
#extends('layouts.master')
#section('title')
Friend Requests
#endsection
#section('content')
#include('includes.message-block')
<section class="row requests">
<div class="col-md-6 col-md-offset-3">
<header><h3>Friend Requests</h3></header>
<div class="requestlist">
<header><h2>You have request from:</h2></header>
#foreach($users as $user)
<p>Name: {{ $user->username }}<br />City: {{ $user->city }}<br />Country:{{ $user->country }}</p>
<div class="interaction">
//stuff here
</div>
#endforeach
Back
</div>
</div>
</section>
#endsection
The route:
Route::get('/friendrequests',[
'uses' => 'FriendController#getFriendRequests',
'as' => 'friendrequests',
'middleware' => 'auth'
]);
The controller (works if I don't use the nested subquery):
public function getFriendRequests()
{
$user = Auth::user();
$friendrequests = DB::table('users')
->select(['username','city','country'])
->where('id',
DB::table('friends')->select('friend_id')->where([['status','received'],['user_id',$user->id]])->get())->get();
return view('friendrequests',['users' => $friendrequests]);
}

Answer 1

You can solve this problem with the approach of "hasManyThrough". In your User's model you should do something like this:
class User extends Model{
//... your code here
public function possibleFriends(){
$this->hasManyThrough(User::class, Friend::class, 'friend_id', 'id')->wherePivot('status', 'received');
}
}
More details in the official docs.

Answer 2

Please try this may be helpful
$friendrequests = DB::table('users')
->select(['username','city','country'])
->whereIn('id', function($query) use($user) {
$query->select('friend_id')
->from('friends')
->where('status', 'received')
->where('user_id', $user->id);
})->get();