I'm using slugs to navigate in my site, but I need the id connected to the slug for a function.
Function:
public function categories(Request $request, $slug)
{
$categories = Category::where('slug', $slug)->get();
$announcements = Announcement::where('category_id', $request->id)->paginate(5);
$category_lists = Category::all();
return view('announcements.index', compact('announcements', 'categories', 'category_lists'));
}
This is the function where I need to get the ID. $request->id isn't working since my $request->id returns 'null'. Is there any way to get the id that's connected to the slug/DB row?
If any more information is needed please tell me.
I've tried getting it with
$announcements = Announcement::where('category_id', Category::get(id))->paginate(5);
and things alike, nothing worked.
I suppose you override the getRouteKeyName in your Category model:
public function getRouteKeyName()
{
return 'slug';
}
Then you can get the Category like this with the route model binding:
public function categories(Request $request, Category $category)
{
$announcements = Announcement::where('category_id', $category->id)->paginate(5);
$category_lists = Category::all();
return view('announcements.index', compact('announcements', 'category', 'category_lists'));
}
Change your code to
$category = Category::where('slug', $slug)->first();
$announcements = Announcement::where('category_id', $category->id)->paginate(5);
if one category has one unique slug, just use first(), instead of get() and you can get the category object and use it.
Related
i am using laravel 7 eloquent. i am very new to laravel
this is basic method i am getting data from category table
public function category(){
$category = Category::orderBy('id', 'desc')->get();
$data['pageData'] = $category;
$data['pageTitle'] = "Category";
return view('admin.category.index')->with('data',$data);
}
But i want to do something like this
public function category(){
$category = Category::orderBy('id', 'desc')->get();
if(!empty($_REQUEST['parent_id']))
$category->where('parent_id',$_REQUEST['parent_id']);
$data['pageData'] = $category;
$data['pageTitle'] = "Category";
return view('admin.category.index')->with('data',$data);
}
So how can this is possible using eloquent.
Any help out of this question are helpful for me as i am beginner.
Try this
public function category(){
$query = Category::orderBy('id','desc');
$query = where('parent_id',$_REQUEST['parent_id']);
$category = $query->get();
$data['pageData'] = $category;
$data['pageTitle'] = 'Category';
return view('admin.category.index')->with('data',$data);
}
You can leverage the when() eloquent method to add conditional clause to query:
public function category()
{
$category = Category::when(request('parent_id'),function($parent_id,$query)
{
$query->where('parent_id',$parent_id);
})->orderBy('id', 'desc')->get();
$data['pageData'] = $category;
$data['pageTitle'] = "Category";
return view('admin.category.index')->with('data',$data);
}
when() doc reference https://laravel.com/docs/8.x/queries#conditional-clauses
You can use the when method to only apply the query if the request contains the parent_id.
From the docs:
Sometimes you may want certain query clauses to apply to a query based
on another condition. For instance, you may only want to apply a where
statement if a given input value is present on the incoming HTTP
request. You may accomplish this using the when method:
$role = $request->input('role');
$users = DB::table('users')
->when($role, function ($query, $role) {
return $query->where('role_id', $role);
})
->get();
The when method only executes the given closure when the first
argument is true. If the first argument is false, the closure will not
be executed. So, in the example above, the closure given to the when
method will only be invoked if the role field is present on the
incoming request and evaluates to true.
In your case it would be the following:
use Illuminate\Http\Request;
public function category(Request $request)
{
$categories = Category::query()
->when($request->input('parent_id'), function ($query, $parent_id) {
$query->where('parent_id', $parent_id);
})
->orderBy('id', 'desc')
->get();
$data['pageData'] = $categories;
$data['pageTitle'] = "Category";
return view('admin.category.index')->with('data', $data);
}
You can do as like below
public function category(){
$category = new Category();
if(!empty($_REQUEST['parent_id'])){
$category->where('parent_id',$_REQUEST['parent_id']);
}
$category = $category->orderBy('id', 'desc')->get()
$data['pageData'] = $category;
$data['pageTitle'] = "Category";
return view('admin.category.index')->with('data',$data);
}
Try using laravel when condition
https://laravel.com/docs/8.x/queries#conditional-clauses
Improve your question with proper details. as you mention in the question the second coding path won't work because it doesn't have $request query to functionally run the if statement. anyhow if you want to get only pageData & pageTitle in laravel Eloquent ORM you have to select both columns as follows.
class CategoryController extends Controller
{
public function category(){
$category = Category::select('pageData', 'pageTitle')->orderBy('id', 'desc')->get();
return view('admin.category.index')->with('data', $category);
}
}
I am trying to retrieve the data on my wishlist table, for a particular user, so far it only retrieves the first data on the table, just returning one array instead of the three in the table with same user id
public function getWishlistByUserId($id){
$wishlists = Wishlist::where('userId', $id)->get();
foreach($wishlists as $wishlist){
$products = Product::where('id', $wishlist->productId)->get();
return $products;
}
}
It happens because the foreach loop returns a value during the first iteration. Place your return statement outside the loop. Also you could improve your performence by making use of relationships.
An example could be:
// Product.php
public function wishlists()
{
return $this->hasMany(Wishlist::class);
}
// Your method
public function getWishlistByUserId($id)
{
return Product::whereHas('wishlists', function ($query) use ($id) {
$query->where('userId', $id);
});
}
Ideally this is n+1 situation
So i will suggest to use laravel relationship like:
in your whishlist model
public function product(){
return $this->hasMany(Product::class,'productId','id');
}
get data with relationship
public function getWishlistByUserId($id){
$wishlists = Wishlist::with('product')->where('userId', $id)->get();
}
I was finally able to get it working this way, i just pushed the result into an array, and then returned it outside the loop, thanks everyone for your help
public function getWishlistByUserId($id){
$wishlists = Wishlist::where('userId', $id)->get();
$wishlist = [];
foreach($wishlists as $wish){
$product = Product::where('id', $wish->productId)->get();
array_push($wishlist, $product);
}
return $wishlist;
}
In my routes/web.php I have a route like this...
Route::get('/tags/{tag}', 'TagsController#show');
Then, inside TagsController because I have a post_tag pivot table that has been defined as a many-to-many relationship.
Tag.php...
public function posts(){
return $this->belongsToMany(Post::class);
}
public function getRouteKeyName(){
return 'name';
}
Post.php...
public function tags(){
return $this->belongsToMany(Tag::class);
}
I get the posts for a certain tag like this...
public function show(Tag $tag){
$posts = $tag->posts;
return view('posts.index', compact('posts','tag'));
}
Then, to sort the posts into newest first I can do this in index.blade.php...
#foreach ($posts->sortByDesc('created_at') as $post)
#include('posts.post')
#endforeach
This works fine, but I'm doing the re-ordering at collection level when I'd prefer to do it at query level.
From Eloquent: Relationships I can see that I can do something like this, which also works...
$user = App\User::find(1);
foreach ($user->roles as $role) {
//
}
But, something like this does not seem to work...
public function show($tag){
$posts = \App\Tag::find($tag);
return view('posts.index', compact('posts'));
}
My question is, how can I filter/order the data at a query level when using pivot tables?
To order your collection you must change
public function tags(){
return $this->belongsToMany(Tag::class);
}
to
public function tags(){
return $this->belongsToMany(Tag::class)->orderBy('created_at');
}
Extending #leli. 1337 answer
To order content without changing the relation created.
First, keep the original relation
class User
{
public function tags
{
return $this->belongsToMany(Tag::class);
}
}
Second, during query building do the following
//say you are doing query building
$users = User::with([
'tags' => function($query) {
$query->orderBy('tags.created_at','desc');
}
])->get();
With this, you can order the content of tags data and in query level also if needed you can add more where clauses to the tags table query builder.
In my Menu controller I have a method which should display the specified record and all its children.
I have two models: MenuItem and MenuVariation, My items will have many variations as outlined in my methods:
MenuItem model
public function variant()
{
return $this->hasMany('App\MenuVariation');
}
MenuVariation model
public function item()
{
return $this->belongsTo('App\MenuItem', 'menu_item_id');
}
Now in my controller I have the following method:
public function show($id)
{
$item = MenuItem::findOrFail($id);
return $item;
}
...which currently only shows the item record but not its variations, so I have changed the code like this...
public function show($id)
{
$item = MenuItem::findOrFail($id)->with('variant')->get();
return $item;
}
but this oddly return ALL items and their variations.
Could someone help me get this working as desired? I would like to still utilise FindOrFail on the Item record, but it should also retrieve any variants (if found).
findOrFail will initiate the query, so you want to switch the order and put with in-front of it. Then use findOrFail. See Below:
public function show($id)
{
$item = MenuItem::with('variant')->findOrFail($id);
return $item;
}
There is also no need for get when you do that.
Im new in Laravel 4, and right now im coding for small project, i use laravel as framework to build my website, but my code i always wonder it's optimize or not because in my model i just wrote:
Category Model
public function parents()
{
return $this->belongsTo('Category', 'cat_father');
}
public function children()
{
return $this->hasMany('Category', 'cat_father');
}
}
Post Model:
<?php
class Post extends BaseModel{
public $table = "post";
protected $primaryKey = 'idpost';
public function Category()
{
return $this->belongsTo('Category', 'cat_id');
}
}
because i didn't know how to join 2 tables in laravel 4, i have a condition is find all post from my categories, which it hadn't belong to category name "Reunion", but i didn't know how to do that, therefore i wrote 2 lines code for that purpose (im not sure wrote code in controller is best way but i didn't know how to call method from Model to controller and get return value)
My method from controller for select all post, it hasn't belong to category name "Reunion"
public function getAllPostView()
{
$getCat = Category::where('cat_name','=', 'Reunion')->firstOrFail();
$post = Post::where('cat_id', '!=', $getCat->idcategory)->get();
return View::make('layouts.post')->with('post',$post);
}
My question, my code is optimize when i wrote it in controller? and how to wrote it in model and get parameter for passing it to controller and use it to view.
second question is how to order "POST" because some cases post need to be ordered from new to old
This is how you do it:
$exclude = 'Reunion';
$posts = Post::select('posts.*')->join('categories', function ($j) use ($exclude) {
$j->on('posts.cat_id', '=', 'categories.idcategory')
->where('categories.name', '<>', $exclude);
})->get();
could just use simple joins
public function getAllPostView()
{
$getCat = Category::where('cat_name','=', 'Reunion')
->join('post','post.cat_id', '!=','Category.idcategory')->get();
return View::make('layouts.post')->with('post',$post);
}
Look out for same field names in both the tables if so can use select
$getCat = Category::select('Category.idcategory as cat_id','Category.cat_id as pos_id','many other fields')
// 'as cat_id' not required for unique field names
->join('post','post.cat_id', '!=','Category.idcategory')
->where('cat_name','=', 'Reunion')
->get();