Laravel/PHP Refactor code to use same different modal - php

Question

I am using Laravel (PHP). I want to refactor below code to ask class A and class B to use the same funsth(). funSth() is repeated in two class while the only difference is the model.
Is there a way I can simplify to below? Is that possible to refactor it into second code?
Current:
class A {
public function funSth(){
Models\Profile::create();
}
public function main(){
$this->funA();
}
}
class B {
public function funSth(){
Models\Location::create();
}
public function main(){
$this->funB();
}
}
Expected:
class A {
public function main(){
(new Y)->funSth();
}
}
class B {
public function main(){
(new Y)->funSth();
}
}
class Y {
public function funSth(){
Models\AnyModel::create();
}
}

Answer 1

One way you could do this is to make a Trait. Traits essentially allow you to use the same code in multiple classes.
Base on the code in your question, your trait would look something like:
trait Y
{
public function funSth()
{
Models\AnyModel::create();
}
}
Don't forget to add the correct namespace for the file.
Then in your other classes you would have the use the use keyword inside the class body:
class A
{
use Y;
public function main()
{
$this->funA();
}
}
If you're trait is in a different namespace then you'll need to either give the full class name with the namespace or import the trait into your class.

Answer 2

After researching for a while. Here is my solution.
use Illuminate\Database\Eloquent\Model;
trait Y
{
protected function create(Model $model, array $attributes){
model->create($attributes);
}
}
Therefore, for Class A and Class B:
class A
{
use Y;
public function main($data){
$this->create((new Models\ModelAA), $data)
}
}
class B
{
use Y;
public function main($data){
$this->create((new Models\ModelBB), $data)
}
}
The basic idea is to use the abstract class Illuminate\Database\Eloquent\Model in trait Y and initialize model before it.