Undefined Variable in Blade Laravel - php

Question

I have this in my controller:
public function detail($id) {
$data = DB::table('data_api')->where('id', $id)->get();
$carousel = DB::table('data_carousel')->where('data_api_id', $id)->get();
return view('detail', ['data_api' => $data]);
return view('detail', ['data_carousel' => $carousel]);
}
But when I try to echo-ing, $carousel by {{ $carousel }}, it says not found. But $data work perfectly. Any idea?
Undefined variable: carousel (View:
/mylaravelproject/resources/views/detail.blade.php)

Answer 1

you need to change the double return statement to a single return
return view('detail', ['data_api' => $data]);
return view('detail', ['data_carousel' => $carousel]);
to
return view('detail', ['data_api' => $data, 'data_carousel' => $carousel]);

Answer 2

you returning view two times that's why only $data_api is available in view,
try this
public function detail($id) {
$data = DB::table('data_api')->where('id', $id)->get();
$carousel = DB::table('data_carousel')->where('data_api_id', $id)->get();
return view('detail', ['data_api' => $data, 'data_carousel' => $carousel]);
}

Answer 3

Update:
public function detail($id) {
$data = DB::table('data_api')->where('id', $id)->get();
$carousel = DB::table('data_carousel')->where('data_api_id', $id)->get();
return view('detail', ['data_carousel' => $carousel,'data_api' => $data]);
}
You are returning two views from the same controller. After the first return execution of code is halt and it will not return the second view. That's why you are unable to get the second view parameters

Answer 4

You cannot return two times from a function and expect both to actually return something. After the first return, execution of the function is stopped.
Try returning both variables at once instead:
return view('detail', [
'data_api' => $api,
'data_carousel' => $carousel
]);

Answer 5

Replace your code with following:
public function detail($id) {
$data = DB::table('data_api')->where('id', $id)->get();
$carousel = DB::table('data_carousel')->where('data_api_id', $id)->get();
return view('detail')->with('data_api', $data)->with('data_carousel', $carousel);
}

Answer 6

You need to return view like below
public function detail($id) {
$data = DB::table('data_api')->where('id', $id)->get();
$carousel = DB::table('data_carousel')->where('data_api_id', $id)->get();
return view('detail', compact('data','carousel'));
}

Answer 7

is that really working now? You tell us you are getting
Undefined variable: carousel (View: /mylaravelproject/resources/views/detail.blade.php)
And you will get that because you are not passing the variable carousel to your view, you are naming your variables as data_api and data_carousell
Second, you should pass your variables as an asociative array in only one sentence not two view calls like this
return view('detail', ['carousel' => $carousel,'data' => $data]);

Answer 8

in my case i use
#if(isset($users))
before my foreach like this example:
<div class="form-group" id="boardAdminUserIdCon">
<p><span class="glyphicon glyphicon-briefcase" aria-hidden="true"></span> مدیر بورد</p>
<select name="boardAdminUserId" id="boardAdminUserId" class="form-control" required="required">
<option value="">{{ __('auth.CHOOSEYOURADMIN') }}...</option>
#if(isset($users))
#foreach($users as $user)
<option value="{{ $user['id'] }}">{{ $user["name"] }}
</option>
#endforeach
#endif
</select>
</div>