How to connect html to Azure database? - php

Question

I'm trying to connect my Azure Sql storeage and html to show everything i have. but i'm having some trouble. i researched w3school and other resources but i still don't know what is wrong?
so i use Notepad++ and save it as html and use php to establish the connection
here is the code in my notepad+++ so far:
<?php
$servername = "servername*****.mysql.database.azure.com";
$username = "loginfor****n#mysql***";
$password = "*****";
$db = "db";
// Create connection
$conn = new mysqli($servername, $username, $password. $db);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
echo "Connected successfully";
?>
and this is what i got
connect_error) { die("Connection failed: " . $conn->connect_error);
i have no idea where did i went wrong. please help me if you can, thanks

Answer 1

I'm not 100% sure as I'm not a PHP dev, but Microsoft have the following on their Azure documentation (here):
<?php
$serverName = "your_server.database.windows.net"; // update me
$connectionOptions = array(
"Database" => "your_database", // update me
"Uid" => "your_username", // update me
"PWD" => "your_password" // update me
);
//Establishes the connection
$conn = sqlsrv_connect($serverName, $connectionOptions);
$tsql= "SELECT TOP 20 pc.Name as CategoryName, p.name as ProductName
FROM [SalesLT].[ProductCategory] pc
JOIN [SalesLT].[Product] p
ON pc.productcategoryid = p.productcategoryid";
$getResults= sqlsrv_query($conn, $tsql);
echo ("Reading data from table" . PHP_EOL);
if ($getResults == FALSE)
echo (sqlsrv_errors());
while ($row = sqlsrv_fetch_array($getResults, SQLSRV_FETCH_ASSOC)) {
echo ($row['CategoryName'] . " " . $row['ProductName'] . PHP_EOL);
}
sqlsrv_free_stmt($getResults);
?>
My guess is that your PHP is malformed and you're getting a render of the code rather than it actually properly executing - be sure to read the documentation.

Answer 2

i've also tried this code too
<?php
$host = '****.mysql.database.azure.com';
$username = '****#mysql****';
$password = '****';
$db_name = '*****';
//Establishes the connection
$conn = mysqli_init();
printf("hello")
mysqli_real_connect($conn, $host, $username, $password, $db_name, 3306);
if (mysqli_connect_errno($conn)) {
printf("sory");
die('Failed to connect to MySQL: '.mysqli_connect_error());
}
// Run the create table query
if (mysqli_query($conn, '
select * from table1;
')) {
printf("Table created\n");
}
//Close the connection
mysqli_close($conn);
?>
it returns a blank page, i feel that some how it just skip all of my php code