MYSQL Get a column value and display it in PHP - php

Question

I have a problem
I want to echo the value of "points" column.
What I tried, but did not work:
$stmt = $mysqli->prepare("SELECT points FROM member_profile WHERE user_id = '$firstName'");
$stmt->execute();
$array = [];
foreach ($stmt->get_result() as $row)
{
$array[] = $row['points'];
}
print_r($array);
THis is my current code:
<?php
header('Content-Type: text/html; charset=Windows-1250');
session_start();
$firstName = $_SESSION['firstname'];
$servername = "db.xxxx.gsp-europe.net";
$username = "xxxxxxxxxxxxx";
$password = "xxxxxxxxxxxxxx";
$dbname = "xxxxxxxx";
/// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
// check if the user exist
$check = "SELECT * FROM `member_profile` WHERE user_id = '$firstName'";
$result = mysqli_query($conn,$check) or die(mysqli_error($conn));
$rows = mysqli_num_rows($result);
//if exist increse points with 1
if($rows>=1){
$sql = "UPDATE `member_profile` SET points = points + 1 WHERE user_id = '$firstName'";
if ($conn->query($sql) === TRUE) {
echo "Thingz created successfully";
} else {
echo "Error doing sum thingz: " . $conn->error;
}
}
// if don't exist create user with points 0
if ($rows == 0)
{
$query = "INSERT into `member_profile` (user_id, points) VALUES ( '$firstName' ,'0')";
$result = mysqli_query($conn,$query)or die(mysqli_error($conn));
$conn->close();
}
?>
What I need in the nutshell: In the end of file, will be a "echo" that will show the current value of "points" column with identificator "user_id". Thats all
Thanks for your time, I appreciate it !

Answer 1

You are getting the result, but aren't fetching the datas.
$stmt->get_result() returns a result set -> mysqli_result and to handle this, you need to call the method fetch_array() from that result.
change your code to :
$results = $stmt->get_result();
while ($row = $result->fetch_array(MYSQLI_ASSOC))
{
$array[] = $row['points'];
}
If you only want 1 result without using arrays, don't use arrays (yes, yes).
$results = $stmt->get_result();
while ($row = $result->fetch_array(MYSQLI_ASSOC))
{
$points = $row['points'];
}