$sql = "SELECT COUNT(*) jumlah FROM pasien WHERE DAYNAME(created_at) = 'Tuesday'";
$result = mysqli_query($conn, $sql);
$row = mysqli_fetch_assoc($result);
var_dump($result); var_dump($row);
Above is my code. I tried this on phpmyadmin and it return 1. When i run this on php returns NULL.
Edit :
I use mysqli_error to see what's wrong with it and the result :
Related
I want to show the count of users which have the status 1 (see code) within PHP MySQL.
<?php
// something like this
$result = mysqli_query($mysqli, "SELECT COUNT(*) FROM users WHERE status = '1'");
echo "$result";
?>
Try this:
$query = "SELECT COUNT(*) as countvar FROM users where status = '1'";
$result = mysqli_query($con,$query);
$row = mysqli_fetch_array($result);
$count= $row['countvar '];
i have this code :
$result = mysqli_query($conn, "SELECT SUM(angsuran) FROM `laporan` WHERE id_mustahik=".$detail_campaigner->id_mustahik."");
$row = mysqli_fetch_assoc($result);
print_r($row);
when i run this code, the result is :
Array ( [SUM(angsuran)] => 30000 )
But i want it to display just "30000" number, without "Array ( [SUM(angsuran)] => ) ".
How can i do that ?
add alias in your query like
$result = mysqli_query($conn, "SELECT SUM(angsuran) as sumtotal FROM `laporan` WHERE id_mustahik=".$detail_campaigner->id_mustahik."");
$row = mysqli_fetch_assoc($result);
echo $row['sumtotal']; //outputs 30000
I have 2 ways
Use array php
$result = mysqli_query($conn, "SELECT SUM(angsuran) FROM `laporan` WHERE id_mustahik=".$detail_campaigner->id_mustahik."");
$row = mysqli_fetch_assoc($result);
echo $row["SUM(angsuran)"]; // out 30000
Modify sql
$result = mysqli_query($conn, "SELECT SUM(angsuran) as sum FROM `laporan` WHERE id_mustahik=".$detail_campaigner->id_mustahik."");
$row = mysqli_fetch_assoc($result);
echo $row["sum"]; // out 30000
I have this query. However, it does not work properly. The echo returns always a 1, but there are 3 rows in the db
<?php
include "db_connect.inc.php";
$sql = "SELECT COUNT(id) FROM profiles";
$res = mysqli_query($con, $sql);
$num = mysqli_num_rows($res);
if ($num == 0)
echo "0";
echo $num;
mysqli_close($con);
?>
You're doing an aggregate query, which means you'll ALWAYS get one row of results - one row containing the count() value you requested. Even if that count() is 0, you'll STILL get one row of results.
If you want to check the value of the count, you have to fetch that row and check the field's value, e.g.
$sql = "SELECT COUNT(id) AS cnt FROM profiles";
$result = mysqli_query($con, $sql) or die(mysqli_error($con));
$row = mysqli_fetch_assoc($result);
if ($row['cnt'] == 0) { die("No profiles"); }
Your query returns 1 row with value 3
To see what you do expect you need something like:
<?php
include "db_connect.inc.php";
$sql = "SELECT COUNT(id) myCount FROM profiles";
$res = mysqli_query($con, $sql);
if ($row = mysqli_fetch_array($res, MYSQLI_ASSOC) ) {
echo $row['myCount'];
} else {
echo "0";
}
mysqli_close($con);
?>
How do I get the outcome of
SELECT COUNT(user) FROM game_paths WHERE user = '$user'
to a PHP variable
I tried
mysql_num_rows
but it returns nothing.
You should use mysql_result and get the first column of the result. Like this:
$result = mysql_query("SELECT COUNT(user) FROM game_paths WHERE user='$user'");
$count = mysql_result($result, 0);
You can also alias the column like this:
$result = mysql_query("SELECT COUNT(user) AS total FROM game_paths WHERE user='$user'");
$data = mysql_fetch_assoc($result);
$count = $data['total'];
Which might be better if you're going to select several columns at the same time, and also for readability.
Try like this. you need to use mysql_fetch_assoc or mysql_fetch_array functions
$result = mysql_query(" SELECT COUNT(user) as total FROM game_paths WHERE user='$user' ");
$row = mysql_fetch_assoc($result);
echo $row['total'];
Or
$result = mysql_query(" SELECT COUNT(user) FROM game_paths WHERE user='$user' ");
$row = mysql_fetch_array($result);
echo $row[0];
Docs Link: http://us2.php.net/mysql_fetch_array
http://www.w3schools.com/php/func_mysql_fetch_array.asp
Note: mysql_* function are deprecated try to use mysqli or PDO
You can use the following code:
$result = mysql_query(" SELECT COUNT(user) FROM game_paths WHERE user='$user' ");
$row = mysql_fetch_array($result);
$count= $row[0];
or
$result = mysql_query("SELECT * FROM game_paths WHERE user='$user'");
$count=mysql_num_rows($result);
This will return the number of rows satisying the condition.
Hey friend Try this code, ithink this will solve your problem
<?php
$con=mysql_connect('hostname','DBusername','paassword');
mysql_select_db('Db_name',$conn);
$query="SELECT COUNT(user) as total FROM game_paths WHERE user='$user'";
$result=mysql_query($query,$con);
$row=mysql_fetch_array($result);
echo $row['total'];
?>
$result = mysqli_query("SELECT COUNT(user) AS user_count FROM game_paths WHERE user='$user'");
$result_array = mysql_fetch_assoc($result);
$user_count=$result_array['user_count'];
Please use mysqli_ instead of mysql_ as its deprecated in the new version
I am trying to store a mysql value into a php variable. I have the following query which I know works. However, I the value for $count is always 0. Can someone explain what I need to do to get the count value? The count should be the count of x's w here name_x=.$id.
$query = "SELECT COUNT(name_x) FROM Status where name_x=.$id.";
$result = mysql_query($query);
$count = $result;
Is first letter in table name is really capital. Please check it first.
or Try :
$query = "SELECT COUNT(*) as totalno FROM Status where name_x=".$id;
$result = mysql_query($query);
while($data=mysql_fetch_array($result)){
$count = $data['totalno'];
}
echo $count;
$query = "SELECT COUNT(*) FROM `Status` where `name_x`= $id";
$result = mysql_query($query);
$row = mysql_fetch_row($result);
$count = $row[0];
please try it
$query = "SELECT COUNT(*) FROM Status where name_x=$id";
$result = mysql_query($query);
$count = mysql_result($result, 0);
You are missing single quotes around $id. Should be
name_x = '" . $id . "'";