Why is this not working? I am trying to insert new data only if it does not meet with my requirements.
$stm= "INSERT INTO `orders` (userid, username, quantity, time, image, uprice, tprice)
VALUES
(:userid, :username, :quantity, :timee, :image, :uprice, :tprice)
WHERE NOT EXISTS (select username from orders where username=:username and image=:image)";
Instead of INSERT .... VALUES which does not allow a WHERE clause, use INSERT .... SELECT:
$stm= "INSERT INTO `orders` (userid, username, quantity, time, image, uprice, tprice)
SELECT :userid, :username, :quantity, :timee, :image, :uprice, :tprice
WHERE NOT EXISTS (select username from orders where username=:username and image=:image)";
Related
I have two tables, user_info and Friend_info. I want to do that when user update his record in user_info then it should also b update in friend_info where friend_id=user_id. I have tried this
UPDATE user_info (name, user_email, Gender, DOB, contact, address) WHERE user_id='$user_id',
friends_info(name, user_email, Gender, DOB, contact, address) WHERE friend_id='$user_id'
values('$name', '$user_email', '$Gender', '$DOB', '$contact', '$address');
But its not working . Any other solution please. It'll be appreciated.
I know this question is too late to ask now a days but its my problem because i am confused after doing so many search and no query is working in my case.
Your question is not clear. So are you testing something like you want query in phpmyadmin. if not then you might need to do in as a transaction. but if its a test or such try this:
UPDATE user_info (name, user_email, Gender, DOB, contact, address)
values('$name', '$user_email', '$Gender', '$DOB', '$contact', '$address')
WHERE user_id='$user_id';
UPDATE friends_info(name, user_email, Gender, DOB, contact, address)
values('$name', '$user_email', '$Gender', '$DOB', '$contact', '$address')
WHERE friend_id='$user_id';
So this is two query which then they are gonna execute together. But now in PHP
check these:
https://stackoverflow.com/a/802474/2226796
http://se2.php.net/manual/en/mysqli.multi-query.php
PHP + MySQL transactions examples
You can join the two tables in your statement using user_id as the joining key.
UPDATE user_info ui
INNER JOIN friends_info fi
ON ui.user_id = fi.user_id
SET ui.name = $name,
SET ui.user_email = $email,
SET ui.Gender = $Gender,
SET ui.DOB = $DOB,
SET ui.contact = $contact,
SET ui.address = $address,
-- set friends_info
SET fi.name = $name,
SET fi.user_email = $email,
SET fi.Gender = $Gender,
SET fi.DOB = $DOB,
SET fi.contact = $contact,
SET fi.address = $address
WHERE ui.user_id = $user_id;
So I'm trying to insert 4 values into a table. I'm getting 3 values from POST and the other one I want to get it from another table. This is how I thought about implementing it but it doesn't seem to be working. Any suggestions?
$query = "INSERT INTO topics (subject, data, uid, role) VALUES (:user, :pass, :uid, SELECT role FROM users WHERE uid=:uid) ";
In SQL, all subqueries need to be surrounded by their own parentheses. So, you can fix your query by using:
INSERT INTO topics (subject, data, uid, role)
VALUES (:user, :pass, :uid, (SELECT role FROM users WHERE uid = :uid));
Personally, I much prefer the INSERT . . . SELECT version of SELECT:
INSERT INTO topics (subject, data, uid, role)
SELECT :user, :pass, :uid, u.role
FROM users u
WHERE uid = :uid;
I would like to select one column from other table and insert it into another one.
I have column named image in table2 and want to select that and insert along with the below data to table1. is that possible?
$stmt = $mysqli->prepare("insert into table1 (username, firstname, lastname, image) ")
$stmt->bind_param('sss', $username, $fname, $lname);
$stmt->execute();
Yes, it's possible:
$stmt = $mysqli->prepare("
insert into table1 (username, firstname, lastname, image)
select ?,?,?,image from table2
");
...but I hope table2 has only one row!
You could do a INSERT ... SELECT query - http://dev.mysql.com/doc/refman/5.1/en/insert-select.html
INSERT INTO table1 (username, firstname, lastname, image)
SELECT ?, ?, ?, image FROM table2 t2 WHERE t2.image_id = ?
The first 3 ? are your bound params - $username, $fname, $lname
t2.image_id = ? represents the id/unique field of your desired img.
I am working on building an employee database but seem to have run into an interesting issue.
When I run my query to add a new user/employee, I get the error:
Column count doesn't match value count at row 1
From what I have researched, this seems to be an error with inserting more/less values than what is declared in the first part of an insert statement example:
INSERT INTO table (col1, col2) VALUES (val1, val2, val3)
The thing is though, I have looked over my query and the columns and values match perfectly (count wise). I have even looked for things in my query such as missing quotes, commas, etc.
Here is my code (query):
$db->query("INSERT INTO userdata (
Username,
Email,
Phone,
Password,
FirstName,
LastName,
Address,
City,
State,
Zip,
JobTitle,
UserGroup,
JobStatus,
Points,
Status,
BirthDate,
HireDate,
HourlyRate,
DateAdded,
SSN
) VALUES (
'$Username',
'$Email',
'$Phone',
'$Password',
'$FirstName',
'$LastName',
'$Address',
'$City',
'$State',
'$Zip',
'$JobTitle',
'$Group',
'$JobStatus',
0,
'$Status',
'$BirthDate',
'$HireDate',
'$HourlyRate'
'$TodaysDate',
'$SSN'
)") or die(mysqli_error($db));
Some things to note:
This not all of the columns in the table have data inserted here (I think its possible to do this and things such as auto incrementing ID's will fill themselves in and others will be left blank)
From the variable dumps I have done, all of these variables are valid.
I am really confused about this and any help would be appreciated.
Check the following portion again:
INSERT INTO userdata(...,
JobStatus,
UserGroup,
Points,
UserGroup,
Status,
.....
,)VALUES(...,
$JobStatus',
0,
'$Group',
'$Status',
......
)
In values(, ?, ?, ?), after jobstatus, there should be UserGroup and then Points. And UserGroup appeared twice.
I am inserting a record and i want to use the id of the last record inserted.
This is what i have tried:
$sql = 'INSERT INTO customer
(first_name, last_name, email, password,
date_created, dob, gender, customer_type)
VALUES(:first_name, :last_name, :email, :password,
:date_created, :dob, :gender, :customer_type)'
. ' SELECT LAST_INSERT_ID()' ;
I am getting the error:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SELECT LAST_INSERT_ID()'.
Can anyone show me where is my mistake?
Thanks!
Check out mysql_insert_id()
mysql_query($sql);
$id = mysql_insert_id();
When that function is run after you've executed your INSERT statement in a mysql_query() command its result will be the ID of the row that was just created.
You can do another query:
$last_id = "SELECT LAST_INSERT_ID()";
Or try to add ; in your query:
INSERT INTO customer
(first_name,
last_name,
email,
password,
date_created,
dob,
gender,
customer_type)
VALUES(:first_name,
:last_name,
:email,
:password,
:date_created,
:dob,
:gender,
:customer_type)<b>;</b>' . ' SELECT LAST_INSERT_ID()';