Compute sum of values in array using PHP - php

Question

I'm trying to combine the scores of employee for my program. My sample is one employee is evaluated more than one. So basically, if employee 1 have scored of 87 and 90 the total should be 177. After computation, I need to return the result with the highest score.
Here so far my sample code (I simplified my code for this question because it is too long to post the original code):
$scores = array(
array(1, "allan", 90),
array(2, "allan", 85),
array(3, "mark", 100),
array(4, "jason", 88),
array(5, "allan", 92),
array(6, "mark", 77),
array(7, "mark", 88),
array(8, "jason", 90)
);
print_r($scores);
get_topemployee($scores);
function get_topemployee($scores) {
$total_score = 0;
$combined_score = array();
foreach($scores as $key) {
for($i=0; count($scores) <= $i; $i++) {
if($key[0] == $key[0][$i]) {
$total_score += $key[1];
}
$combined_score[] = array($key[0], $key[1], $total_score);
}
}
$employee = ""; // employee with highest score
$compare_score = 0;
foreach($combined_score as $value) {
$compare_score = $value[1];
if($value[1] >= $compare_score) {
$employee = $value[0];
}
}
return $employee;
}
The result does not return the employee with highest score and not sure which in my code is incorrect. thanks for help
do this:- https://3v4l.org/WhVaN

Answer 1

You can use array_reduce to convert your scores array into an array of total scores indexed by employee:
$scores = array_reduce($scores, function ($c, $v) {
$name = $v[1];
if (isset($c[$name])) {
$c[$name] += $v[2];
}
else {
$c[$name] = $v[2];
}
return $c;
}, array());
You can then use arsort to sort the array in reverse order while maintaining the key association. You can then use key to get the key of the first element, which will be the name of the employee with the highest score:
arsort($scores);
echo key($scores);
Output:
allan
Demo on 3v4l.org
To print out all the scores, you can simply print_r($scores):
Array (
[allan] => 267
[mark] => 265
[jason] => 178
)
Alternatively to print just the highest score, change echo key($scores); to echo key($scores) . ' ' . current($scores);:
allan 267
Updated demo.

Answer 2

You can do that with simple foreach loop:
foreach($scores as $e) {
if (!isset($res[$e[1]])) $res[$e[1]] = 0;
$res[$e[1]] += $e[2];
}
print_r(array_keys($res, max($res)));
Live example: 3v4l

Answer 3

Here is a snippet for you, please see inline doc for explanation
$result = [];
array_walk($scores, function($item) use(&$result){
// pushing on the behalf of name and checking if not isset with '??'
$result[$item[1]] = ($result[$item[1]] ?? 0) + $item[2];
});
// searching for index with max value in result and show max value too
echo array_search(max($result), $result).' -> '. max($result);
array_search — Searches the array for a given value and returns the first corresponding key if successful
array_walk — Apply a user supplied function to every member of an array
Output
allan -> 267
Demo Link.

Answer 4

$scores = [
[1, 'allan', 90],
[2, 'allan', 85],
[3, 'mark', 100],
[4, 'jason', 88],
[5, 'allan', 92],
[6, 'mark', 77],
[7, 'mark', 88],
[8, 'jason', 90]
];
function maxScore(array $scores): string {
$preparedScores = [];
foreach ($scores as $score) {
$key = $score[1];
$value = $score[2];
if (isset($preparedScores[$key])) {
$preparedScores[$key] += $value;
} else {
$preparedScores[$key] = $value;
}
}
arsort($preparedScores);
return array_key_first($preparedScores);
}
echo maxScore($scores);
Result:
allan

Answer 5

$scores = array(
array(1, "allan", 90),
array(2, "allan", 85),
array(3, "mark", 100),
array(4, "jason", 88),
array(5, "allan", 92),
array(6, "mark", 77),
array(7, "mark", 88),
array(8, "jason", 90)
);
get_topemployee($scores);
function get_topemployee($scores) {
$total_score = 0;
$combined_score = array();
$highest_score = 0;
$highest_employee = '';
foreach($scores as $key => $value) {
if ( ! isset($combined_score[$value[1]])) {
$combined_score[$value[1]] = $value[2];
}
else {
$combined_score[$value[1]] += $value[2];
}
if ($highest_score < $combined_score[$value[1]]) {
$highest_score = $combined_score[$value[1]];
$highest_employee = $value[1]; //the highest value employee
}
}
return $highest_employee;
}