How to get proper json? [duplicate] - php

Question

This question already has answers here:
How to create an array for JSON using PHP?
(8 answers)
Closed 3 years ago.
I don't know php and JSON i wanted a result like below
How to add array employeelist on my json
{
"employeeList": [
{
"name": "Gretchen Rodriquez",
"email": "gretchenrodriquez#trasola.com"
},
{
"name": "Sharon Harris",
"email": "sharonharris#trasola.com"
},
{
"name": "Serrano Haynes",
"email": "serranohaynes#trasola.com"
}
]
}
My php code
$sql="SELECT * FROM tbl_retro_example";
$result=mysqli_query($conn, $sql);
$response=array();
while($row=mysqli_fetch_array($result))
{
array_push($response,array("name"=>$row["name"],"email"=>$row["email"]));
}
echo json_encode($response,JSON_FORCE_OBJECT);
i am getting response like below
{
"0": {
"name": "jugl",
"email": "jual#gmail.com"
},
"1": {
"name": "gond",
"email": "gond#gmail.com"
},
"2": {
"name": "kaik",
"email": "kaik#gmail.com"
}
}
How do i get proper result ?

Answer 1

I think you are not too far from where you need to be.
If you are looking to have your results under the employeeList key, I would change how you push the results to your array. Also, when using json_enconde you can just tell PHP which array you want to transform. For such, I would transform your:
array_push($response,array("name"=>$row["name"],"email"=>$row["email"]));
into
$response['employeeList'][] = ["name"=>$row["name"],"email"=>$row["email"]];
And, where you have:
json_encode($response,JSON_FORCE_OBJECT)
You can just do
json_encode($response);
For better output results to check your new json I would use print_r instead of echo
Give it a go and let me know how you find it :)
NOTE: I am always working under the most recent PHP version, so I tend to use [] a lot to declare my arrays. I noticed you use array() in your code example, so I am not sure if you are using an older PHP version. If such is the case and [] is not recognised yet by your version, feel free to replace it with your array declaration instead!