How to use pathinfo in php? - php

Question

I am working on a php code as shown below on which Line#A prints the following array (shown below php code). My code doesn't seems to go inside switch statement. I am not sure why.
I added print_r($parts) at Line A in order to print the value of $parts.
php code:
<?php
if (!empty($_POST['id']))
{
for($i=0; $i <count($mp4_files); $i++) {
if($i == $_POST['id']) {
$f = $mp4_files[$i];
$parts = pathinfo($f);
print_r($parts); // Line A
switch ($parts['extension'])
{
echo "Hello World"; // Line B
case 'mp4' :
$filePath = $src_dir . DS . $f;
system('ffmpeg -i ' . $filePath . ' -map 0:2 -ac 1 ' . $destination_dir . DS . $parts['filename'] . '.mp3', $result);
}
}
}
}
?>
Output (Line#A):
Array
(
[dirname] => .
[basename] => hello.mp4
[extension] => mp4
[filename] => hello
)
I have used echo "Hello World" at Line B but for some reasons, its not getting printed and throwing 500 internal server error on console.
Problem Statement:
I am wondering what changes I should make in the php code so that it goes inside switch statement.

Answer 1

The error 500 is caused by echo "Hello World" at Line B which is outside of case mp4.
Your switch statement should be like this.
switch ($parts['extension']) {
case 'mp4':
echo "hello world";
$filePath = $src_dir . DS . $f;
system('ffmpeg -i ' . $filePath . ' -map 0:2 -ac 1 ' . $destination_dir . DS . $parts['filename'] . '.mp3', $result);
break;
}