This question already has answers here:
How to search SQL column containing JSON array
(5 answers)
Closed 3 years ago.
I have a column contain json data,
{
"city":"\u0628\u063a\u062f\u0627\u062f",
"town":"\u0627\u0644\u0627\u0639\u0638\u0645\u064a\u0629",
"queue":"316",
"lane":"22",
"home":"15"
}
how can I search on the object (town) in the table?
I have tried
$query ="SELECT * FROM tabel WHERE JSON_CONTAINS(colom_name,'town') like '%$Word%' order by id DESC";
Also There are no results at all
We are using JSON fields in one of our projects, and for example, we have everything related to a user in one column, called simply JSON. So in order to search easier for a specific user, we are using JSON_EXTRACT. So for your example, you could do it like:
SELECT * FROM Table_Name WHERE JSON_EXTRACT(<json_column>,'$.town') LIKE '%something%'
You could even get town name, or city, by doing it like this:
SELECT JSON_EXTRACT(<json_column>,'$.<filed_from_json>') FROM Table_Name WHERE JSON_EXTRACT(<json_column>,'$.town') LIKE '%something%'
BR
You dont have to use JSON_CONTAINS function.
In the documentation:
JSON_CONTAINS() function tests whether or not a specified value is found in the given JSON document or, optionally, at the specified path within the document
You do not have a json document, but a normal column.
Your SQL query should be:
$query ="SELECT * FROM tabel WHERE town like '%$Word%' order by id DESC";
Related
This question already has answers here:
SELECT * EXCEPT
(15 answers)
Closed 1 year ago.
Suppose I have a table that contains "200" columns, how do I select all colons except a few, and the way I know is to select it manually:
"SELECT id, user, name, email, city... FROM table WHERE id = 1";
However my wish would be something like:
"SELECT * (exeto essas tabelas) FROM table WHERE id = 1";
The only way you can achieve that in MySQL is to use hidden columns (https://dev.mysql.com/doc/refman/8.0/en/invisible-columns.html).
This question already has answers here:
Is storing a delimited list in a database column really that bad?
(10 answers)
Closed 4 years ago.
I have an issue with SQL IN query: I'm storing multiple employee IDs in a table, separated with commas for each task. When I try to fetch a task with an IN query, I'm not getting the row which contains the employee IDs.
My query is:
select
t.*,
e.emp_name,
d.department_name
from
task as t
LEFT JOIN employee as e on(e.emp_id=t.assign_to)
LEFT JOIN department as d on(d.depart_id=e.depart_id)
where
t.task_status='PENDING'
AND t.created_by!='31'
AND t.assign_to IN ('31')
order by
t.task_id DESC
The stored value in database
IN doesn't work like that
Example if your data looks like:
ManagerName, ManagerOf
'John', 'Steve,Sarah,Dave'
You can't do:
SELECT * FROM managers WHERE 'sarah' IN ManagerOf
IN is best conceived as an extension of OR:
SELECT * FROM managers WHERE managerof IN ('Sarah','Steve')
--is the same as:
SELECT * FROM managers WHERE
managerof = 'Sarah' OR
managerof = 'Steve'
There would be as many OR clauses as there are items in the IN list.
Hopefully this shows you why the database doesn't return you any results.. Because a value of Steve,Sarah,Dave is not equal to either Sarah or Steve. The database doesn't look at the commas and say "oh, that's a list" - it's just a single string of characters that happens to have a comma character every now and then
There are nasty quick hacks to so-so achieve what you want, using LIKE and string concat but they aren't worthy of an answer, to be honest
You need to change your database structure to include a new table that tracks the task id and the employee(s) id it is/was assigned to. After doing that, you'll be able to use IN on the employee id column as you're expecting to with this query
This question already has answers here:
how to highlight search results
(3 answers)
Closed 4 years ago.
I am stuck with the query result and need help plz.
My sample column
How are you
what is your name
where are you from
whats the age of the youth
Now this is my column in Table and I query the below
$search='you';
$s=mysqli_query($con,"Select * from tblxyz where column1 is LIKE '%{$key}%'");
I am getting the result of all the 4 rows as there is "you" in all, But I would like to get the result of the exact word which SQL searched, so the result from the 4th row would be "youth". How to get those words which SQL found based on my query.
Thanks in Advance
try this query.
$search='you';
$sql=" SELECT * FROM tblxyz WHERE column1 like '%".$search."%'";
to get the exact word don't use %
$search='you';
$s=mysqli_query($con,"Select * from tblxyz where column1 is LIKE '{$search}'");
Let's say you are looking for the word you and you want to select only data with the word you. In this case, you might want to use REGEXP.
"SELECT * FROM table WHERE tname RLIKE "[[:<:]]you[[:>:]]"
The above can be used for exact word matching.
This question already has answers here:
How can I search within a table of comma-separated values?
(6 answers)
Closed 8 years ago.
For example, when a table has a record column named 'product' that contain value such as: 'Laptop, Desktop, Case'. How can I validate these 3 values that break down with a comma against two PHP variables value with $var1='Laptop' and $var2='Desktop' ? So that this row can be found! However, the two variables could be passed in the order of 'Desktop', 'Laptop' as well. Meanwhile, the column could have pattern of 'Case, Desktop, Laptop'. I wonder if there is a solution in MySQL for this kind of scenario that somehow, pick up each element like PHP could and match them with each var individually.
Without knowing anything about your table structure this is a quick example of what you can do.
SELECT * FROM table WHERE $var1 IN (SELECT product FROM table WHERE something = somethingelse) AND $var2 IN (SELECT product FROM table WHERE something = somethingelse)
As I understood, you want the data to be found, if the column 'product' contains 'Laptop' or 'Desktop'. Write this with the LIKE operator in your query:
"SELECT * FROM table WHERE `product` LIKE '%Desktop%' OR `product` LIKE '%Laptop%'"
If you pass the variables it would be:
"SELECT * FROM table WHERE `product` LIKE '%$var1%' OR `product` LIKE '%$var2%'"
Make sure to use the % sign before and after the searched string, so that it will match even if the keyword is anwhere inside the product content.
This question already has answers here:
MySQL SELECT LIKE or REGEXP to match multiple words in one record
(7 answers)
Closed 9 years ago.
Hm, I think this will be an easy question but I can't find an answer to it.
I have a column called "name" in a mysql table.
A input might look like "How to programme 13".
I select it like this:
"SELECT * FROM lists WHERE name LIKE '%to programme 13%'"
This returns the row. But I want to be able to search for "how programme" or "how to 13". How can I search for this and make it return a result?
Thanks
Edit:
So basically I have to split the search string variable before searching?
I have a search string
$sw = $_GET['sw'];
"SELECT * FROM lists WHERE name LIKE '%".$sw."%'"
SELECT * FROM lists WHERE name LIKE '%programme%' AND name LIKE '%how%'
you can use REGEXP
SELECT * FROM lists WHERE name REGEXP 'programme.+how'
Here you have a similar question: MySQL SELECT LIKE or REGEXP to match multiple words in one record
SELECT * from lists where name REGEXP 'how|program|13'
simple repeat condition with OR
SELECT * FROM lists
WHERE name LIKE '%how programme%'
OR name LIKE '%how to 13%'
This query, searches for rows that have programme AND how
SELECT * FROM lists WHERE name LIKE '%programme%' AND name LIKE '%how%'