how to get each user list in array - php

Question

public function getChildren($parent, $level=0,$getlevel=array()) {
$criteria = new CDbCriteria;
$criteria->condition='referred_by_user_id=:id';
$criteria->params=array(':id'=>$parent);
$count = array(0=>0);
$model = $this->findAll($criteria);
// $levelcount = array();
$user=User::model()->findbypk(Yii::app()->user->id);
if($user->level!=$level)
{
foreach ($model as $key) {
$count[0]++;
$index=1;
// echo str_repeat(' — ', $level) . $key->name . "<br />";
$children= $this->getChildren($key->id, $level+1);
// pr($children);die;
foreach ($children as $child)
{
// pr($child);
if ($child==0)
continue;
if (isset($count[$index]))
$count[$index] += $child;
else
$count[$index] = $child;
$index++;
}
}
}
return $count;
}
I can output only the number of users. How do I get the user id for each level in an array?

Answer 1

I think the problem is you must make $index variable outside of for

Answer 2

I made something similiar a while ago:
public static function getChildren($idParent) {
$elem = [];
$childrens = Arbol::model()->findAll("estado = 1 and id_parent = " . $idParent . ' ORDER BY level');
foreach ($childrens as $key => $child) {
$persona = Persona::model()->findbyPk($child->id_child);
if ((int) $persona->id_superior === $idParent) {
$nombre = explode(" ", $persona->nombres);
$elem[$key] = [
"id" => $persona->id_persona,
"image" => Yii::app()->baseUrl . '/images/user-icon' . ($persona->pago_inscripcion ? '-activo.png' : '.png'),
"text" => [
'title' => $nombre[0] . ' ' . substr($persona->apellido_paterno, 0, 1) . '.'
]
];
} else {
$keySUperior = array_search($persona->id_superior, array_column($elem, "id"));
if (is_int($keySUperior)) {
$elem[$keySUperior]["children"] = self::getChildren((int) $persona->id_superior);
}
}
}
return $elem;
}
I hope i give you any help