How to fix Fatal error: Cannot redeclare connectdb() - php

Question

I am new for PHP and MYSQL. I have tried some learnings using xampp. when I try to connect database with the script it shows below error.. this showing on index.php
Fatal error: Cannot redeclare connectdb() (previously declared in
C:\xampp1\htdocs\core.php:18) in C:\xampp1\htdocs\core.php on line 24
I have a search on google and try to fix this. but it's not worked...
core.php line 18th to 24 th codes as follows.
function connectdb()
{
global $dbname, $dbuser, $dbhost, $dbpass;`
$conms = #mysql_connect($dbhost,$dbuser,$dbpass); //connect mysql`
if(!$conms) return false;`
$condb = #mysql_select_db($dbname);`
if(!$condb) return false;`
return true;`
}
config.php codes as follows
$dbname = "aw"; //change to your mysql database name
$dbhost = "localhost"; //database host name
$dbuser = "sam";
$dbpass = "1234";
$max_buds=100; //maximum number of buds
$topic_af = 120; //topic antiflood
$post_af = 45; //post antiflood
$onver = true; //isonline versoion
$timeadjust = (0 * 60 * 60); // 4 hours
putenv("TZ=Africa/Johannesburg");

Answer 1

It's called "include guard":
if(!function_exists('connectdb')) {
function connectdb() {
}
}

Answer 2

I think the issue that connectdb function already loaded.
Try use include_once instead of include.
example:
include_once 'Functions.php';
The include_once statement includes and evaluates the specified file during the execution of the script. This is a behavior similar to the include statement, with the only difference being that if the code from a file has already been included, it will not be included again, and include_once returns TRUE. As the name suggests, the file will be included just once.
https://www.php.net/manual/en/function.include-once.php

Answer 3

Try replacing your connectdb function with the following code:
if (!function_exists('connectdb')) {
function connectdb()
{
global $dbname, $dbuser, $dbhost, $dbpass;
$conms = #mysql_connect($dbhost,$dbuser,$dbpass); //connect mysql
if (!$conms) return false;
$condb = #mysql_select_db($dbname);
if (!$condb) return false;
return true;
}
}
It will only create the function if it does not exist.