I am trying find the next date.Suppose today is 23-07-2019 and i want to echo 24-07-2019 but i can't. I execute the below code and it gives me some error.
they give this error :
Notice: A non well formed numeric value encountered in
C:\xampp\htdocs\telehealth\twilio_Sms\autometic.php on line 2
24
Now please anyone help what is my mistake and what should i change to correct this. I am trying many thins but i could not solve it
echo (date('d-m-Y')+"1");
The trouble is that the date('d-m-Y') returns string with - symbols and you try to sum it with a "1". You can't mix php types in this way.
First of all you definitely should read about php types, php math operations and type juggling.
Next, there is a special library to work with date and time. And you definitely should use it to date and time operations. The DateTime is an object that contents date and time and can be represented as string by format function.
Operations with date and time are quite difficult (leap years, February and so son). And it is highly recommended to use special API from DateTime.
So, for you task (refer to add function of datetime):
$date = new \DateTime('23-07-2019');
$date->add(new \DateInterval('P1D'));
echo $date->format('Y-m-d);
Related
So,
I know a lot of requests and question has been askeb about this subject but none really worked for my case... I'm working on a liscensing api with php (supposed to be easy) and I get a string date (2000-01-01) from my db and the length of the subscription. So I'm creating a DateTime Object with it using this :
$created_at = date_create($result["created_at"]);
date_add($created_at, date_interval_create_from_date_string($result["length"]." days"));
But for some unknowed reason, It seems I can't get the current date in a DateTime object so I can just compare them with <>=. Even if I use date_sub() or date_diff() It still require two DateTime object. I'm really deseperate at this point so I figured I could ask for some help.
Hope I didn't miss anything obvious
You can use the 'now' attribute,
$today = new DateTime('now'); to get the current time.
Don't forget to set your timeregion in your php.ini to be able to get the right time.
And if you want to compare them, you can use date_diff and then
$var->format('%r') to get the value.
%r is going to be empty if the result is positive.
Good luck!
I am using PHP 7.2, and trying to create a date from a string as follows:
$dateString = '2018-12-31T01:01:01+00:00';
$converted = DateTime::createFromFormat(DATE_ATOM), $dateString);
The snippet above works fine and returns the expected result.
The problem happens when I swap the day and month in the date string provided above, as follows:
$dateString = '2018-31-12T01:01:01+00:00';
$converted = DateTime::createFromFormat(DATE_ATOM), $dateString);
I was expecting this second example to return false, but instead I get an actual date time, 2020-07-12 01:01:01.000000.
So, I have no way of telling whether the second date was a proper date or not, because the system accepted it, and I will be saving in my database something which I shouldn't.
Could this be considered a bug in PHP 7.2?
Could this be considered a bug in PHP 7.2?
No, this is how the method is intentionally implemented. You can argue if it's the right way to implement it, but that's how it is. Notably even if we all agree that it's not right here, it will still keep working as it's implemented.
The practical answer here is to write a validator (for entirety of format and all parts) and run any untrusted input through it.
Hi I have a problem where I am trying to get a total time that a job has taken (using database fields job_start and job_end time(7))
then adding this to another model's field,
the code i have is
if (isset($_POST['Jobs'])) {
$model->attributes = $_POST['Jobs'];
$model->setScenario('closejob');
$model->status = 2; //set status to closed
//date time difference - this is the part I need help with
$diff = $model->job_start - $model->job_end;
//need to get customer model and add time diff to it
$customermodel = Customers::model()->findByPk($model->customer_ID);
$customermodel->total_time = $customermodel->total_time + $diff;
$customermodel->save();
if ($model->save())
$this->redirect(array('view', 'id' => $model->job_ID));
}
I have tried string to time and other date functions but to no avail , the above code throws the following error
CDbCommand failed to execute the SQL statement: SQLSTATE[22007]: [Microsoft][SQL Server Native Client 11.0][SQL Server]Conversion failed when converting date and/or time from character string..
Any ideas on the proper way to do this ?
i.e am I going about the adding of time and calculating the differences all wrong ?
I think it has something to do with converting the string to a time format but I am unsure how to do this
Maybe you have to do
$diff = $model->job_end - $model->job_start;
Instead of
$diff = $model->job_start - $model->job_end;
Unless you have an attached behavior for that model, it is likely that your job_start and job_end attributes are strings that are formatted according to MSSQL, assuming the column types are a date/time representation. This is certainly the way CActiveRecord models work with MySQL and Yii with DATETIME type.
To do differences, you would need to convert first. Take a look at CDateFormatter and use it to convert your attributes to numerical representations that allow for arithmetic.
If you cannot get Xdebug to work, then invest time in getting the Yii::log() function working (it will output to runtime/application.log by default.
In a DB table I have several fields with datetime as field type. So I need to persist data only as date time object.
From a form I get date time as string like
2012-10-05 17:45:54
Now when ever I persist my entity I get following error:
Fatal error: Call to a member function format() on a non-object in
..\DateTimeType.php on line 44
I tried with
$protocol->setStartedAt(strtotime($post['started_at']));
or
$from = \DateTime::createFromFormat('yy-mm-dd hh:mm:ss', $post['started_at']);
$protocol->setStartedAt($from);
or just
$from = new \DateTime($post['started_at']);
$protocol->setStartedAt($from);
The last code works but it does not uses the timestamp passed as arguement but just gets the current time.
Any ideas?
I always create a DateTime object with its constructor, in your case it would be:
$protocol->setStartedAt(new \DateTime($post['started_at']));
if this works but does not use the timestamp posted you probably do not have the value in $post['started_at']. Try debugging it or just do the dirty trick:
die($post['started_at']);
For the sake of future readers who surely will someday encounter this problem (this is the first post if you google "symfony 2 datetime from string"), keep in mind that in Symfony 2 the DateTime object does NOT accept a string with that format : "d/m/Y H:i:s", and probably doesn't support many others either.
For the sake of not becoming mad at that, I've actually found out that the easiest and safest solution to avoid such errors is this one:
First, get your date string from whatever kind of request you are doing (In my case a generic AJAX request) and convert it to a DateTime Object, this example assumes that we need to create a dateTime object for 25/04/2015 15:00, which is the format of the jQuery UI italian DateTimePicker (that's just an example):
$literalTime = \DateTime::createFromFormat("d/m/Y H:i","25/04/2015 15:00");
(note: use \ to use php's DateTime object, else you will be using Symfony's datetime object that will throw you an exception)
Then, once you did it, create a date string using the comfort format function, by giving to the first parameter the output format expected (Y-m-d H:i:s):
$expire_date = $literalTime->format("Y-m-d H:i:s");
In this way you are 100% sure that whatever kind of format you are passing or receiving this will properly be converted and you won't get any kind of exception from the DateTime symfony object, as long as you provide what you are expecting as an input.
Knowing that this post is actually quite old, I've just decided to post that because I didn't find any other valuable source but this one to understand where the problem could have been.
Please note that the best solution is still to send the datetime string in the correct format already, but if you literally have no ways to do that the safest way to convert such a string is the one above.
How about createFromFormat?
http://uk.php.net/manual/en/datetime.createfromformat.php
$from = DateTime::createFromFormat($post['started_at'], 'Y-m-d H:i:s');
I'm trying to parse a string in a specific format and I'm really surprised to discover that I can't find a good function to do that.
The only one I found is strtotime and it doesn't fit as it guesses the date format. I really don't trust the "guess" part.
Moreover my string input is in a french format (dd/mm/aaaa) which it seems that it's not well understood (it parses american formats like mm/dd/aaaa).
What I'm looking for is a function that take in input a date string and a format to parse.
I could do it myself with a regexp but I can't believe that it doesn't already exist.
I found :
DateTime::createFromFormat(). But it only work with PHP 5.3 and I don't have the power to upgrade the PHP version (5.2)
strptime(). This method does what I want but is not implemented on windows platform (by the way: WTF ??)
Any suggestion ?
Unfortunately, it seems that such parsing is better done manually, by exploding the string at slashes and then switching day and month.
Check out Zend_Date, which lets you specify the format when you set a date. As well as including constants for many common formats, you can specify your own too.
$date = new Zend_Date();
$date->set('27/08/2009','DD/MM/YYYY');
The following comment from php.net on strtotime may help:
Fails for non-US dates where the
ordering is uncertain, such as
01/02/2003 - parses this as Feb 1st,
rather than Jan 2nd.
If you are parsing dates for a non-US
locale, you can flip these elements of
your date:
<?php
$y = $_POST['date'];
if (preg_match('/^\s*(\d\d?)[^\w](\d\d?)[^\w](\d{1,4}\s*$)/', $y, $match)) {
$y = $match[2] . '/' . $match[1] . '/' . $match[3];
}
echo date('d # m # Y', strtotime($y));
?>
WARNING: Above only works for dates,
and breaks for times: 12:30:01 will be
converted to 30/12/01.
I've written a class myself, I think you'll find an ok version in gadmdatecommand.php in http://sourceforge.net/projects/phpdbedittk
Regarding the comments here to just explode by '/' and swap the number, its not quite that simple. If you offer to enter dates into an input box, you may get - depending on the locality of the user and the application
1/7/2010
1.7.2010
1-7-2010
15 Jul
1 Jul 2010
1/6/8
and many more variations. I've solved this problem (at least for me successfully) by creating dateformats, each of which have
a) a regex that matches the format
b) an array mapper that matches regex brackets into date pieces (day, month, minute, am/pm)
c) an output format for date()
HTH
If you know your date format input will be English-formatted, then you can process it into a more standard date format. A simple parsing of 24/7/2007 to 2007-07-24 is trivial. Explode with the forward slash and put the parts in the right spot. I know for a fact that strtotime will parse 2007-07-24 correctly.
strptime():
Internally, this function calls the strptime() function provided by the system's C library. This function can exhibit (!) noticeably different behaviour across different operating systems. The use of date_parse_from_format(), which does not suffer from these issues, is recommended on PHP 5.3.0 and later.
http://www.php.net/manual/en/function.strptime.php