Dynamically get page link based on breadcrumb level - php

Question

I'm trying to create a breadcrumb menu via PHP and have the following so far:
<?php
// 1. Get URL
$crumbs = explode("/",$_SERVER["REQUEST_URI"]);
$address = 'http://'.$_SERVER['HTTP_HOST'];
// 2. Strip extras
foreach($crumbs as $crumb){
$crumb = ucfirst(str_replace(array(".php","_"),array(""," "),$crumb) . ' ');
echo ""."<span class='crumbMenu'>".$crumb."</span>";
}
?>
Let's say I have the following page hierarchy: Products > Products Level 2 > Products Level 3
The above code will spit out:
Products
Products Level 2
Products Level 3
Which is correct. However, the links are not.
After reading up on HTTP_HOST, I'm certain my approach is wrong, but unsure on what other approach I can take to dynamically get each crumb items link?
Links I am getting:
localhost:8080
Links I am expecting:
Products: /products
Products Level 2: /products/products-level-2
Products Level 3: /products/products-level-2/products-level-3

Answer 1

You seem to have forgotten about adding routes to $address variable, so all your breadcrumbs point to base server address. Try the following:
<?php
// 1. Get URL
$crumbs = explode("/",$_SERVER["REQUEST_URI"]);
$address = 'http://'.$_SERVER['HTTP_HOST'];
// 2. Strip extras
$build = $address.'/products';
foreach($crumbs as $crumb){
if(in_array($crumb, [$_SERVER['HTTP_HOST'], 'products'])) {
continue;
}
$build .= '/'.$crumb;
$crumb = ucfirst(str_replace(array(".php","_"),array(""," "),$crumb) . ' ');
echo ""."<span class='crumbMenu'>".$crumb."</span>";
}
?>

Answer 2

It is very hard to ready your echo which is not helpful. I created small function which should do what you have asked for. Feel free to modify it for your needs.
$crumbs = "/x/y/z";
$address = "localhost:8080";
$crumbs = explode('/', $crumbs);
$end = '';
$href = '';
foreach ($crumbs as $crumb) {
$crumb = str_replace('.php', '', $crumb);
$end .= $crumb . ' ';
$href .= $crumb . '/';
}
echo("HREF => " . $href);
echo("\n");
echo("TITLE => " . $end);