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Well, I Will developer a close blog in laravel, this blog needs take the name of the people who has logged!
I wanna replace for example {[userName]} for auth->user()->name()
I Will write {[userName]} in my text editor Ane show the name of user logged in my view!
i think just use str_replace
eg:
$input = "My name is [USERNAME]";
echo str_replace("[USERNAME]", auth->user()->name(), $input);
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http://example.com/geturl.php?url=http://example.org/index.php?parafile=1698%3A1562%3A0%3A0¶_action=print_ticket¶file=dance://here.kodas/print&token=3ec2b0d3e6e0ca152bc024cc3f30f16c
So i want each of this parameters in a different varaible in the geturl.php file. I am using the regular get url
You can use anything like this :
$url = "http://example.com/geturl.php?url=".urlencode($urlPart);
$_server[QUERY_STRING] solved my problem
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How can i create a comment system in php which will not display the writers name.
Like- If a person comments then his/her name should not be displayed.
Here is the article that shows you how to make comment system using html css and php.
Link: How to make comment system.
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<?php _e('Copyright-, All rights reserved | Build by this *company- this is the word I want to href*','theme'); ?>
I want to link a word on this phrase, but i dont know what is php_e and how to a href this.
Modify your Code to
<?php _e('Copyright-, All rights reserved | Build by this ','theme');?><?php _e('Company','theme');?>
_e is used to translate output.
Here the doc : https://codex.wordpress.org/Function_Reference/_e
You can just link your word inside, it's not a problem.
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Essentially the title, please keep it simple, im not accustom with code.
You can use header('Location:yourpage.php') at the end of your function.
Header
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Using php+mysql how can i get an item from database with a criteria as shown below.
Check if string lookat(which is 'look at' without space) exist in Take an in-depth look at Wednesday's World Cup semifinal
If you have a lot of data in your table, this wouldn't be ideal. But you could do something like.
WHERE REPLACE(column, " ", "") LIKE "%lookat%"