How to show leave expiry date of an employee - php

Question

First I count the number of days between leave dates and resume date e.g. From 26–July-2019 To 31-July-2019 is 5 days. Then I need to know the number of days counting from the leave date to the current date and store in a variable named $count_days. if the no of leave days minus count_days is equal zero then I would say your leave has expired.
I could not figure it out how to get it right
<?php
// include the file that defines (contains) the username and password
require_once("includes/mysqlconn.php");
// build qry
$qry = "SELECT employee.emp_num,employee.emp_lname,employee.emp_fname,eleave.leave_date,eleave.resume_date from employee INNER JOIN eleave ON employee.emp_num = eleave.emp_num where employee.emp_num = '".$_SESSION['empno']."'";
$records = mysqli_query($dbconn,$qry) or die('Query failed: ' . mysqli_error($dbconn));
$time_current = time();
while ($line = mysqli_fetch_array($records))
{
$leavedate = strtotime($line['leave_date']);
$resume_date = strtotime($line['resume_date']);
//count days between dates to get no of leave days
$leave_days = ceil(abs($resume_date - $leavedate) / 86400);
//this is to get days difference between no of leave days and the current day
//when echo $count_days give me -1564264800 I don't know what this value stand for
$count_days = $leavedate - strtotime($time_current);
if (($leave_days-$count_days) <> 0){
echo "enjoy your leave";
}else{
echo "your leave has expired";
}
}
mysqli_close($dbconn);
?>

Answer 1

First of all, $time_current is already in 'time' (integer) format, so strtotime($time_current) is probably NOT what you want to do. Second, if you are checking whether resume_time has passed (aka their leave is over), all you have to do is:
if( $time_current < $leave_time ){
echo 'your leave has not started';
}elseif( $time_current > $resume_time ){
echo 'your leave has expired';
}else{
echo 'enjoy your leave';
}
Otherwise, if you want to know the number of days between, correctly subtract (already integer) $time_current and $resume_date and divide by 86400. For the sake of ease (and understanding) I have wrapped this into a function for you:
function numDaysBetweenTimes(int $time1, int $time2 = null) : int{
if( !$time2 ){
$time2 = time();
}
return ceil(abs($time1 - $time2) / 86400);
}
Example usage:
$line['leave_date'] = '2019-01-15 00:00:00';
$line['resume_date'] = '2019-01-05 00:00:00';
$time_current = time();
$leaveTime = strtotime($line['leave_date']);
$resumeTime = strtotime($line['resume_date']);
echo numDaysBetweenTimes($leaveTime, $resumeTime) . ' leave days<br/>';
echo numDaysBetweenTimes($resumeTime) . ' days between leave and now<br/>';
Output:
4 leave days
202 days between leave and now