How to use insert_string query helper with SQL function? - php

My database is using UUIDs as a primary key. When I insert into the DB (mariaDB), I need to do:
insert into table_name (id, parent_id, name,... etc. )
values (UUID_TO_BIN(UUID()), 'a UUID', 'record name', .etc)
I would like to use CI's insert_string function, but this array:
$data = array(
'id' => 'UUID_TO_BIN(UUID())',
'name' => 'record name',
'parent_id' => 'UUID_TO_BIN(' . $parent_id . ')'
);
$this->db->insert_string('table_name',$data);
...I do not think will work, because each result is escaped, so CI will escape the whole text including the function, instead of only what is inside the UUID_TO_BIN function in the parent_id value.
I am trying to figure out if this is a possibility for the parent_id to run the function given. Otherwise, I guess the easiest way is to do the conversion to BIN from HEX in PHP, but will that break the SQL?

You could use the set() method, which accept optional third parameter ($escape), that will prevent data from being escaped if set to FALSE on the id column.
$data = array(
// 'id' => 'UUID_TO_BIN(UUID())',
'name' => 'record name',
'parent_id' => 'UUID_TO_BIN(' . $parent_id . ')'
);
//set id column value as UUID
$this->db->set('id', 'UUID_TO_BIN(UUID())', FALSE);
$this->db->insert_string('table_name', $data);
more on set() method.

Related

Append array to JSON column to multiple rows at once

I have a column type JSON in database, and I'm performing an update on multiple rows.
For example, this query
Model::whereIn('id',$ids)->update([
'status' => 'canceled'
]);
And this table has another column called history (JSON type), each row already has its own history in JSON.
How do I append to each one of them? This array, for example
[
'user_id' => '144',
'action' => 'cancel',
'at' => '2021 - 08 - 30'
]
My idea and question, is there something like
Model::whereIn( 'id', $ids )->appendJson('field_name',$array);
The easiest approach could be like this:
$status = 'canceled';
$extraHistoryData = [...];
Model::whereKey($ids)->get(function ($model) use ($status, $extraHistoryData) {
$history = $model->history;
$history = array_merge($history, $extraHistoryData);
$model->update(compact('status', 'history'));
});
If you want to update all rows in a single query, the closest I can get is this thread. But It's not very likely to solve your problem.

Dynamically add columns to query results via CakePHP 3 ORM queries

I'm trying to write a query using CakePHP 3.7 ORM where it needs to add a column to the result set. I know in MySQL this sort of thing is possible: MySQL: Dynamically add columns to query results
So far I've implemented 2 custom finders. The first is as follows:
// src/Model/Table/SubstancesTable.php
public function findDistinctSubstancesByOrganisation(Query $query, array $options)
{
$o_id = $options['o_id'];
$query = $this
->find()
->select('id')
->distinct('id')
->contain('TblOrganisationSubstances')
->where([
'TblOrganisationSubstances.o_id' => $o_id,
'TblOrganisationSubstances.app_id IS NOT' => null
])
->orderAsc('Substances.app_id')
->enableHydration(false);
return $query;
}
The second custom finder:
// src/Model/Table/RevisionSubstancesTable.php
public function findProductNotifications(Query $query, array $options)
{
$date_start = $options['date_start'];
$date_end = $options['date_end'];
$query = $this
->find()
->where([
'RevisionSubstances.date >= ' => $date_start,
'RevisionSubstances.date <= ' => $date_end
])
->contain('Substances')
->enableHydration(false);
return $query;
}
I'm using the finders inside a Controller to test it out:
$Substances = TableRegistry::getTableLocator()->get('Substances');
$RevisionSubstances = TableRegistry::getTableLocator()->get('RevisionSubstances');
$dates = // method to get an array which has keys 'date_start' and 'date_end' used later.
$org_substances = $Substances->find('distinctSubstancesByOrganisation', ['o_id' => 123);
if (!$org_substances->isEmpty()) {
$data = $RevisionSubstances
->find('productNotifications', [
'date_start' => $dates['date_start'],
'date_end' => $dates['date_end']
])
->where([
'RevisionSubstances.substance_id IN' => $org_substances
])
->orderDesc('RevisionSubstances.date');
debug($data->toArray());
}
The logic behind this is that I'm using the first custom finder to produce a Query Object which contains unique (DISTINCT in SQL) id fields from the substances table, based on a particular company (denoted by the o_id field). These are then fed into the second custom finder by implementing where(['RevisionSubstances.substance_id IN' ....
This works and gives me all the correct data. An example of the output from the debug() statement is as follows:
(int) 0 => [
'id' => (int) 281369,
'substance_id' => (int) 1,
'date' => object(Cake\I18n\FrozenDate) {
'time' => '2019-09-02T00:00:00+00:00',
'timezone' => 'UTC',
'fixedNowTime' => false
},
'comment' => 'foo',
'substance' => [
'id' => (int) 1,
'app_id' => 'ID000001',
'name' => 'bar',
'date' => object(Cake\I18n\FrozenDate) {
'time' => '2019-07-19T00:00:00+00:00',
'timezone' => 'UTC',
'fixedNowTime' => false
}
]
],
The problem I'm having is as follows: Each of the results returned contains a app_id field (['substance']['app_id'] in the array above). What I need to do is perform a count (COUNT() in MySQL) on another table based on this, and then add that to the result set.
I'm unsure how to do this for a couple of reasons. Firstly, my understanding is that custom finders return Query Objects, but the query is not executed at this point. Because I haven't executed the query - until calling $data->toArray() - I'm unsure how I would refer to the app_id in a way where it could be referenced per row?
The equivalent SQL that would give me the required results is this:
SELECT COUNT (myalias.app_id) FROM (
SELECT
DISTINCT (tbl_item.i_id),
tbl_item.i_name,
tbl_item.i_code,
tbl_organisation_substances.o_id,
tbl_organisation_substances.o_sub_id,
tbl_organisation_substances.app_id,
tbl_organisation_substances.os_name
FROM
tbl_organisation_substances
JOIN tbl_item_substances
ON tbl_organisation_substances.o_sub_id = tbl_item_substances.o_sub_id
JOIN tbl_item
ON tbl_item.i_id = tbl_item_substances.i_id
WHERE
tbl_item.o_id = 1
AND
tbl_item.date_valid_to IS NULL
AND
tbl_organisation_substances.app_id IS NOT NULL
ORDER BY
tbl_organisation_substances.app_id ASC
) AS myalias
WHERE myalias.app_id = 'ID000001'
This does a COUNT() where the app_id is ID000001.
So in the array I've given previously I need to add something to the array to hold this, e.g.
'substance' => [
// ...
],
'count_app_ids' => 5
(Assuming there were 5 rows returned by the query above).
I have Table classes for all of the tables referred to in the above query.
So my question is, how do you write this using the ORM, and add the result back to the result set before the query is executed?
Is this even possible? The only other solution I can think of is to write the data (from the query I have that works) to a temporary table and then perform successive queries which UPDATE with the count figure based on the app_id. But I'm really not keen on that solution because there are potentially huge performance problems of doing this. Furthermore I'd like to be able to paginate my query so ideally need everything confined to 1 SQL statement, even if it's done across multiple finders.
I've tagged this with MySQL as well as CakePHP because I'm not even sure if this is achievable from a MySQL perspective although it does look on the linked SO post like it can be done? This has the added complexity of having to write the equivalent query using Cake's ORM.

Save all record records using request->all in Laravel

Laravel provides a great help for developers to save all input fields of a form which is one record with one line of code.
like if I want to save a form which has multiple input fields and one record to database like:
then I can save it with below code and it works great:
SaveOrder:: create($request->all());
Now I have a question. If I have multiple records (multiple rows) in a form and I can add new rows with a button pressed. Then how can I save all records with above code?
Like:
It's easy to do that using Eloquent :
$data = array(
array('field1'=>'value1', 'field2'=> value2),
array('field1'=>'value1', 'field2'=> value1),
//...
);
Model::insert($data);
Assuming your input names look something like name[], since you can add rows on the fly, you can retrieve the input as an array, and insert them using something like this:
$data = [];
$names = request('name');
$product_names = request('product_name');
$product_colour = request('product_colour');
$product_size = request('product_size');
for ($i = 0; $i < count($names); $i++) {
// Add checks to make sure indices actually exist, probably using preprocessing in JS
$data[] = [
'name' => $names[$i],
'product_name' => $product_names[$i],
'product_colour' => $product_colour[$i],
'product_size' => $product_size[$i],
];
}
Model::insert($data);
The best answer for this question is using foreach statement. Like:
$CustomerName= $request -> input('CustomerName');
$ProductId= $request -> input('ProductId');
$ProductName= $request -> input('ProductName');
$ProductColor= $request -> input('ProductColor');
foreach( $ProductId as $key => $n ) {
SaveOrder::insert(
array(
'CustomerName' => $CustomerName[$key],
'ProductId' => $ProductId[$key],
'ProductName' => $ProductPrice[$key],
'ProductColor' => $ProductQuantity[$key],
)
);}
Use upsert
If you use Laravel 8 or above, you can make use of upsert. Such an useful function to insert or update matching records at the same time.
SaveOrder::upsert($request->all(), ['id'], ['CustomerName', 'ProductName', 'ProductColor', 'ProductID']);
The method's first argument consists of the values to insert or update, while the second argument lists the column(s) that uniquely identify records within the associated table. The method's third and final argument is an array of the columns that should be updated if a matching record already exists in the database. The upsert method will automatically set the created_at and updated_at timestamps if timestamps are enabled on the model:
Flight::upsert([
['departure' => 'Oakland', 'destination' => 'San Diego', 'price' => 99],
['departure' => 'Chicago', 'destination' => 'New York', 'price' => 150]
], ['departure', 'destination'], ['price']);
Read the documentation on Laravel Upsert

Why is the `LIKE` operator not working with integer columns?

I'm trying to receive some ids from my database for an autocomplete search on my CAKEPHP 3.3 site. But my problem is that its only returning the id if I type in the exact id and not part of it.
Here is my function to search the data. The name variable is what is being passed from input.
public function search()
{
if ($this->request->is('ajax'))
{
$name = $this->request->query['term'];
$resultArr = $this->Invoices->find('all', [
'conditions' => ['Invoices.id LIKE' => ($name . '%')]
]);
$resultsArr = [];
foreach ($resultArr as $result)
{
$resultsArr[] = ($result['id']);
}
$this->set('resultsArr', $resultsArr);
// This line is what handles converting your array into json
// To get this to work you must load the request handler
$this->set('_serialize', ['resultsArr']);
}
}
For example there is a id in the table '5254' and I type in part of the id '52' nothing is returned but when I type in the whole id '5254' the id is returned.
I'm unsure why this is the case because in my sql query i'm using the percent sign to say any characters after what has been typed into the input.
Here is part of my table
SQL debug when 52 is entered.
object(Cake\ORM\Query) {
'(help)' => 'This is a Query object, to get the results execute or iterate it.',
'sql' => 'SELECT Invoices.id AS `Invoices__id`, Invoices.start_date AS `Invoices__start_date`, Invoices.close_date AS `Invoices__close_date`, Invoices.customer_id AS `Invoices__customer_id`, Invoices.invoice_to_address AS `Invoices__invoice_to_address`, Invoices.ship_to_address AS `Invoices__ship_to_address`, Invoices.customer_contact_id AS `Invoices__customer_contact_id`, Invoices.aircraft_registration_id AS `Invoices__aircraft_registration_id`, Invoices.shipping_company_id AS `Invoices__shipping_company_id`, Invoices.notes AS `Invoices__notes`, Invoices.worksheet_notes AS `Invoices__worksheet_notes`, Invoices.closed AS `Invoices__closed`, Invoices.times_printed AS `Invoices__times_printed`, Invoices.payment_due AS `Invoices__payment_due`, Invoices.GST_rate AS `Invoices__GST_rate`, Invoices.opening_notes AS `Invoices__opening_notes`, Invoices.courier_ticket AS `Invoices__courier_ticket`, Invoices.job_description AS `Invoices__job_description`, Invoices.worksheets_printed AS `Invoices__worksheets_printed`, Invoices.supervising_engineer_id AS `Invoices__supervising_engineer_id`, Invoices.job_type_id AS `Invoices__job_type_id`, Invoices.opened_by_id AS `Invoices__opened_by_id`, Invoices.assigned_to_id AS `Invoices__assigned_to_id`, Invoices.certification_required AS `Invoices__certification_required`, Invoices.currency_id AS `Invoices__currency_id`, Invoices.xero_batch_number AS `Invoices__xero_batch_number`, Invoices.xero_amount AS `Invoices__xero_amount`, Invoices.exchange_rate AS `Invoices__exchange_rate`, Invoices.payment_instructions AS `Invoices__payment_instructions`, Invoices.email AS `Invoices__email`, Invoices.inv_email AS `Invoices__inv_email` FROM invoices Invoices WHERE Invoices.id like :c0',
'params' => [
':c0' => [
'value' => '52%',
'type' => 'integer',
'placeholder' => 'c0'
]
The id column is of type INTEGER, and therefore the value is being bound as such, as can be seen in your Query dump, it says 'type' => 'integer'. Being bound as an integer will cause it to be casted, and you'll end up with a comparison against 52 only.
You can workaround that by telling the query builder to treat the column as a string type. This can be done via the second argument ($types) of the query builders *where() methods:
$this->Invoices
->find()
->where(
['Invoices.id LIKE' => ($name . '%')],
['Invoices.id' => 'string']
);
See also
API > \Cake\ORM\Query::where()
In this case You can "inject" plain query - array values with numeric index in conditions are treated as plain query, and it will not be parametrized. Be carefull: Typecast to integer is necessary in this case to prevent SQL Injection:
$result = $this->Invoinces->find('all' , [
'conditions' => [
'id LIKE "'.(int)$input.'%" '
]
])
->toArray();
Try it like this:
'conditions' => ['Invoices.id LIKE' => '"' . $name . '%"']
you can still do it like this in cakephp 3
$results = $clients->find()->select(['id','email','name','accountid','created','status'])
->Where(function (QueryExp $exp, Query $q) use ($requestData) {
$orCond = $exp->or_([
new Comparison('accountid',$requestData['search']['value'],null,'LIKE'),
new Comparison('email',$requestData['search']['value'],null,'LIKE'),
new Comparison('name',$requestData['search']['value'],null,'LIKE'),
new Comparison('created',$requestData['search']['value'],null,'LIKE'),
new Comparison('status',$requestData['search']['value'],null,'LIKE'),
]);
return $exp->add($orCond);
});

how to use insert_batch with unique ids

I am using codeignitor's insert batch function to insert multiple rows to a table.
$this->db->insert_batch('table', $sizes);
my $sizes array looks like this
$sizes = array(
array(
'size' => 'M' ,
'product' => 'Hat'
),
array(
'size' => 'L' ,
'product' => 'Hat'
)
);
I was intending for separate rows to be added to my db table with these values along with unique ids, however when each nested array is added, It adds 0 to the id field, rather than a unique ID
I am receiving the error "Duplicate entry '0' for key 'id'"
What is the best approach to solve this? Thanks for reading!
Make your UNIQUE Column with AUTO_INCREMENT

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