How to format an php array to desired result [closed] - php

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I need to display some data in the chart. Basically i have an array from database which looks like this-
[
[0] =>[
[user_type] => 'Manager'
[total_count] => 3
],
[1] =>[
[user_type] => 'Director'
[total_count] => 2
]
]
There is one more user_type which is Trainee . If user Trainee has 0 Total_count it is not coming in above array. So i need to add manually. So first will check which user_type is not exist in above array out of 3 user_types. If not exist then just need to add total_count 0.
And finally my desired array should look like this-
[
['labels'] =>['Manager','Director','Trainee],
['dataset'] => [ 3, 2, 0 ]
]
Please notice here, Proper sequence is very important. So in above array Manager has 3, Director has 2 and Trainee has 0 total count.
Thanks in advance!

Answer 1

Try the below code maybe It will help.
/*
using array column will get the result in
Array ( [Manager] => 3 [Director] => 2 )
*/
$array_column = array_column($array, 'total_count', 'user_type');
//Create new array like below
$add_array = array('Manager'=>'0', 'Director'=>'0', 'Trainee'=>'0',);
//using array_merge merge add_array and array_column
$new_array = array_merge($add_array, $array_column);
//using array_walk_recursive get the requird result
array_walk_recursive($new_array, function($item, $key) use (&$final_array){
$final_array['labels'][]=$key;
$final_array['dataset'][]=$item;
});
echo "<pre>";
print_r($final_array);
?>
Case 1- if Trainee is not there in array
DEMO
Case 2 - If Manager and Director both are not there in array
DEMO
Case 3- if Director is not there - DEMO

Answer 2

Here is the script you can use with array_combine and array_map with splat(...) operator
$arr = array_combine(['labels','dataset'],array_map(null, ...$arr));
if(!in_array('Trainee',$arr['labels'])){
array_push($arr['labels'],'Trainee');
array_push($arr['dataset'],0);
}
print_r($arr);die;
array_combine — Creates an array by using one array for keys and another for its values
Note:- In array_map NULL can be passed as a value to callback to perform a zip
operation on multiple arrays. If only array1 is provided, array_map()
will return the input array. In short to perform transpose of array operation
Working demo
Output:-
Array
(
[labels] => Array
(
[0] => Manager
[1] => Director
[2] => Trainee
)
[dataset] => Array
(
[0] => 3
[1] => 2
[2] => 0
)
)

Answer 3

Try this
$arr = array_combine(['labels','dataset'], array_map(null, $arr));
Make a function for adding non-existing user_type into array
function setUserType($userType, $array) {
if(!in_array($userType, $array['labels'])){
array_push($array['labels'], $userType);
array_push($array['dataset'], 0);
}
return $array;
}
Call function by any user_type like 'Manager', 'Trainee', 'Director'
$arr = setUserType('Trainee', $arr);
Or make an array of all user types and run a loop
foreach(['Manager', 'Trainee', 'Director'] as $type) {
$arr = setData($type, $arr);
}
Print and show the final value
print_r($arr);
die();
Demo https://3v4l.org/UbiXn

Answer 4

Try it
$array = array();
foreach($yourArr as $row)
{
$array['labels'][] = $row['user_type'];
$array['dataset'][] = $row['total_count'];
}
print_r($array);