I have some PHP code, which returns all records from my database. I need 10 results on each page. How to paginate the results? Dunno how to write a piece of code responsible for displaying page numbers...
<?php
$query = $link->query("SELECT * FROM news WHERE category='rhythmix' ORDER BY subject DESC");
while($output = $query->fetch_assoc()){
$text = $output['news'];
$text = str_replace('[video]','<div class="video-container">',$text);
$text = str_replace('[/video]','</div>',$text);
$text = str_replace('[media]','<center>',$text);
$text = str_replace('[/media]','</center>',$text);
$embera = new \Embera\Embera();
echo $embera->autoEmbed($text);
}
?>
Add LIMIT to your query in this way:
SELECT *
FROM news
WHERE category='rhythmix'
ORDER BY subject DESC
LIMIT 0, 10;
The first number (0) is the start position on the resulset and the second one (10) is how many results you want to show (the offset).
To show the second page:
...LIMIT 10, 10
If you always want to show 10 results you just need to to add 10 to the first number of the LIMIT.
Change your query to read
$query = $link->query("SELECT * FROM news WHERE category='rhythmix' ORDER BY subject DESC LIMIT 0, 10");
To display the first 10 rows. The next set of 10 rows can be shown using
...LIMIT 10, 10");
and so on. . .
Related
I'm trying to figure out how to only display the 1st 10 records (1-10) or the 2nd 10 records (11-20), or etc...
The code below does a great job of pulling all records, but I can't figure out how to modify it to only show N number of records. Any help is greatly appreciated.
include 'database.php';
$pdo = Database::connect();
$sql = 'SELECT * FROM trail101 ORDER BY id DESC';
foreach ($pdo->query($sql) as $row) {
//my code
}
Use limit to define the offset and number of records you want. To get the first 10 use:
SELECT * FROM trail101 ORDER BY id DESC LIMIT 0, 10
to get the next 10:
LIMIT 10, 10
I have a function in php I use it for paging it is like this :
$query = "SELECT id,
FROM table
ORDER BY id ASC
LIMIT $offset,5";
this work fine but what I want is to get the page that contain id number let say 10 and with it the other 4 rows, I want it to return something like this:
7,8,9,10,11,12 -> if I give it id number 10.
25,26,27,28,29 -> if I give it id number 26 and so on.
like it would return the 5 rows but I want to know how to set the offset that will get me
the page that have the 5 rows with the specified id included.
what should I do like adding where clause or something to get what I want!
Notice that the IDs in your table won't be consecutive if you delete some rows. The code below should work in such conditions:
$result = mysql_query('select count(*) from table where id < ' . $someId);
$offset = mysql_result($result, 0, 0);
$result = mysql_query('select * from table order by id limit ' . max($offset - 2, 0) . ',5');
while ($row = mysql_fetch_assoc($result)) {
print_r($row);
}
Try something like this
//but for pagination to work $page should be $page*$limit, so new rows will come to your page
$limit = 5;
$start = ($page*limit) -2; // for normal pagination
$start = $page -2; // for your case, if you want ids around the $page value - in this case for id = 10 you will get 8 9 10 11 12
if ($start < 0) $start = 0; // for first page not to try and get negative values
$query = "SELECT id,
FROM rowa
ORDER BY id ASC
LIMIT $start,$limit";
I have a page named 'job.php', currently this page is showing all posted job. But now I want to show only 5 latest posts. And if anyone want to check the previous posts, they can click next button thus more 5 posts will be seen. There should be a previous button too.
Following is my code:
$result1 = mysql_query("SELECT * FROM job ORDER BY ID DESC");
$num_row = mysql_num_rows($result1);
while($row1 = mysql_fetch_array($result1)){
$cat=$row1['Category'];
$title=$row1['Title'];
echo "Job field: $cat<br/> Title: $title<br/>";
}
N:B: It's not pagination. I don't want to show page numbers, just want to show next & previous button.
There are 100s of articles available on the Internet
Create Awesome PHP/MYSQL Pagination
PHP / MySQL select data and split on pages
If you want to do on your own:
Use LIMIT keywords in your query.
Pass the page and the multiplier to the LIMIT.
Some code
<?php
$limit = 5;
$start = (int)(($page - 1 ) * $limit);
$page = mysql_real_escape_string($_GET["page"]);
$query = "SELECT * FROM `table` LIMIT $start, {(int)$page + $limit}"
?>
There are two ways to achieve this.
1) In the query itself by using LIMIT
$result1 = mysql_query("SELECT * FROM job ORDER BY ID DESC LIMIT 1, 5");
2 ) By using loop
$i = 0;
while($row1 = mysql_fetch_array($result1)){
if($i < 5) {
$cat=$row1['Category'];
$title=$row1['Title'];
echo "Job field: $cat<br/> Title: $title<br/>";
$i++;
}
}
You can pass the current value to URL and get it back by using $_GET..
You can use this query:
Select * from table_name ORDER BY ID DESC LIMIT 5;
I feel its better to use pagination. If you want dont want to show page nos, better hide it or just modify the code. If you planning to do it manually its a bit messy
You can use LIMIT in you mysql query:
$result1 = mysql_query("SELECT * FROM job ORDER BY ID DESC LIMIT 0, 5");
I tried to achieve a method in which I create a scoreboard (while loop) and order the fetched results by a certain numeric field (points). But what I need to achieve is like the following
rank----username--point
1st------test-----------3200
2nd-----test2---------1200
etc.. I paginate my results and limit 25 results per page. I tried a while loop in the following way
while($row = mysql_fetch_array($query) || $i<=$totalnumberofrows ){
echo out the results
$i++
}
What this does is number from 1 to 25 perfectly, but on the other hand, on page 2 it numbers again from 1-25.
Is there a trick to achieve what I need to achieve?
I.e. continuous numbering from 1 to (total number of rows) even when paginated.
What you're looking for is the MySQL LIMIT statement. For example, the following query would return entry 0-24 (so, the first 25 entries in your database):
SELECT * FROM entries ORDER BY `points` LIMIT 0, 25
Say that you want to fetch the second page (the next 25 entries), you can do:
SELECT * FROM entries ORDER BY `points` LIMIT 25, 25
Most important thing to note here is that the first argument is the row where it should start, and the second argument is not the last row, but the total amount of rows it should return.
To determine the starting point, simply do (($page_number - 1) * 25), assuming your first page is numbered 1. You could for example do the following:
<?php
$start = (($page_number - 1) * 25);
$query = "SELECT * FROM entries ORDER BY `points` LIMIT {$start}, 25";
// ... rest of your code goes here ...
?>
just add 25 to the number for each page,
for the second page (in my example) - add 25
for the third page - add 50
etc...
$page = 2;
while($row = mysql_fetch_array($query) || $i<=$totalnumberofrows ){
echo out the results
echo (($page-1)*$totalnumberofrows)+$i;
$i++
}
If you know the page number and the offset you should be able to do the following
$rank = $offset * $page_number;
how can i check current number in mysql where....
my query is
$aid = 16;
$get_prev_photo = mysql_query("SELECT * FROM photos WHERE album_id='$aid' AND pic_id<'$picid' ORDER BY pic_id LIMIT 1");
$get_next_photo = mysql_query("SELECT * FROM photos WHERE album_id='$aid' AND pic_id>'$picid' ORDER BY pic_id LIMIT 1");
while i am getting current photo with following query
$photo = mysql_query("SELECT * FROM photos WHERE pic_id='$picid' LIMIT 1");
and getting total photos in album with following query
$photos = mysql_query("SELECT * FROM photos WHERE album_id='$aid'");
$total_photos = mysql_num_rows($photos);
now i want to check where i am and show it as Showing 1 of 20, showing 6 of 20 and so on...
now i want to check where i am actually...
i think you are referring to pagination, which can be achieved using LIMIT and OFFSET sql
decide the number of results you want per page, then select that many
create links like:
View the next 10
and dynamically change those every time
queries look ~like~
$offset=$_GET['view'];
SELECT * FROM table WHERE `condition`=true LIMIT 5 OFFSET $offset
this translates roughly as
select 5 from the table, starting at the 10th record
This is bad:
$photos = mysql_query("SELECT * FROM photos WHERE album_id='$aid'");
Because it grabs all the fields for the entire album of photos when all you really want is the count. Instead, get the total number of photos in the album like this:
$result = mysql_query("SELECT count(1) as total_photos FROM photos
WHERE album_id='$aid'");
if ($result === false) {
print mysql_error();
exit(1);
}
$row = mysql_fetch_object($result);
$total_photos = $row->total_photos;
mysql_free_result($result);
Now you have the count of the total number of photos in the album so that you can set up paging. Let's say as an example that the limit is set to 20 photos per page. So that means that you can list photos 1 - 20, 21 - 40, etc. Create a $page variable (from user input, default 1) that represents the page number you are on and $limit and $offset variables to plug into your query.
$limit = 20;
$page = $_POST['page'] || 1; // <-- or however you get user input
$offset = $limit * ($page - 1);
I'll leave the part where you code the list of pages up to you. Next query for the photos based on the variables you created.
$result = mysql_query("SELECT * FROM photos WHERE album_id='$aid'
ORDER BY pic_id LIMIT $limit OFFSET $offset");
if ($result === false) {
print mysql_error();
exit(1);
}
$photo_num = $offset;
while ($row = mysql_fetch_object($result)) {
$photo_num++;
$pic_id = $row->pic_id;
// get the rest of the variables and do stuff here
// like print the photo number for example
print "Showing photo $photo_num of $total_photos\n";
}
mysql_free_result($result);
I'll leave better error handing, doing something with the data, and the rest of the details up to you. But that is the basics. Also I did not check my code for errors so there might be some syntax problems above. To make a single photo per page just make $limit = 1.