if (isset($_POST[ echo $_POST - php

I need help with some coding.
I watched some tutorials from W3Schools and youtube, but I just don't get it.
<!DOCTYPE html>
<?php
if (isset($_POST["Push me"]))
echo $_POST['name']
?>
<html>
<body>
Registration
<form action="/action_page.php" method="get" target="_blank">
Insert name <input type="text" name="fname"><br>
<input type="submit" value="Push me">
</form>
</body>
</html>
When you push the button there should be a name that was typed into the field.
Example:
If you enter the name Simon after pushing the button it should write Hello Simon under the button

if (isset($_POST["fname"]))
// ^^^^^
echo $_POST['fname'];
// ^^^^^ ^
<form action="/action_page.php" method="post" target="_blank">
// ^^^^

Your PHP code is out of the HTML tag, I have place the php code in the DIV under the button, i.e. to display "Hello xxxTheNameYouEnterInTheInputxxx"
The if condition in your PHP code should be like if(isset($_POST["fname"])) instead of if(isset($_POST["Push me"]))
i.e. $_POST["NameOfTheInputElementInTheForm"]
<form action="/action_page.php" method="get" target="_blank"> should be like <form action="/test.php" method="POST"> i.e. Method is POST and action should be the name of the file, remove target="_blank"
Here is the full code, save it as test.php
<!DOCTYPE html>
<html>
<body>
Registration
<form action="/test.php" method="POST">
Insert Name: <input type="text" name="fname"><br>
<input type="submit" value="Push me">
</form>
<hr>
<div>
<?php
if (isset($_POST["fname"])){
echo "Hello " . $_POST['fname'];
}
?>
</div>
</body>
</html>

Related

Input from form to url?

So the goal is to take the input from a form append it to the end of the URL and then return the HTML from that page.
I am not entirely sure how to take the forms value (in this case $2) and attach it to the URL.
<html>
<head>
<title>Metar Test</title>
</head>
<body>
<form action="" method="POST">
<p>IACO Code: <input type="text" name="$2" value=""></p>
<input type="submit" name="submit" value="Submit">
</form>
<?php $html=file_get_contents("http://www.metar.mysite.net/metar?id=$2")?>
<?php echo $_POST ["$html"];?>
</body>
</html>
On submit any input from a form with method="POST" will be stored in the $_POST global. You can access it from there and append it to your URL string.
<html>
<head>
<title>Metar Test</title>
</head>
<body>
<form action="" method="POST">
<p>IACO Code: <input type="text" name="iacoCode" value=""></p>
<input type="submit" name="submit" value="Submit">
</form>
<?php
if (isset($_POST["iacoCode"])) {
$html = file_get_contents("http://www.metar.mysite.net/metar?id=" . $_POST["iacoCode"]);
echo $html;
}
?>
</body>
</html>
Using the IF statement to check if it is set will prevent it from loading the URL with no variable.
The way we extract data via php from a form is like below
<html>
<head>
<title>Metar Test</title>
</head>
<body>
<form action="" method="POST">
<p>IACO Code: <input type="text" name="$2" value=""></p>
<input type="submit" name="submit" value="Submit">
</form>
<?php $html=file_get_contents("http://www.metar.mysite.net/metar?id=$_POST['$2']")?>
<?php echo $_POST ["$html"];?>

multiple form with single submit button to retrieve value of fields within bith form

index.php
<html>
<head>
<script type="text/javascript">
function submitForms()
{
document.forms["form-1"].submit();
document.forms["form-2"].submit();
}
</script>
</head>
<body>
<form method="POST" action="form.php" id='form-1'>
<input type="text" name="txt1" />
</form>
<form method="POST" action="form.php" id='form-2'>
<input type="text" name="txt2" />
</form>
<input type="button" value="Click Me!" onclick="submitForms();" />
</body>
</html>
form.php
<?php
echo $_POST['txt1'];
echo $_POST['txt2'];
?>
Above is my code and when i submit both forms then both text-fields with their value it does not shoe me both text-field values.It only shoe me second text-field value.Please help me quickly.
I think because you try to get the params after sumbit two forms. You have sent the two forms at once and the second has stepped to the first, so the result is the return of the second form.
I think this will be better:
<html>
<head>
</head>
<body>
<form method="POST" action="form.php">
<input type="text" name="txt1" />
<input type="text" name="txt2" />
<input type="submit" value="Click Me!" />
</form>
</body>
</html>
<?php
echo $_POST['txt1'];
echo $_POST['txt2'];
?>
Sorry for my english

How do you get user inpup and display it in php

I am trying to get user input from a text box and then echo it using php. Here is my code, and it is not seeming to work.
<html>
<body>
<?php
echo $_POST['value'];
?>
<form method="post" action="">
<input type="text" name="value">
<input type="submit">
</form>
</body>
</html>
<html>
<body>
<?php
if(!empty($_POST['value']))
{
echo filter_var($_POST['value'], FILTER_SANITIZE_STRING);}
?>
<form method="post" action="">
<input type="text" name="value">
<input type="submit">
</form>
</body>
</html>
First check if form posted.

How can i pass values from two html pages to php?

I have 2 html pages :
page1.html
<html>
<body>
<form action="page2.html" method="post">
Enter First name: <input type="text" id="text1">
<input type="submit" value="Next">
</form>
</body>
</html>
page2.html
<html>
<body>
<form action="test.php" method="post">
Enter Last name: <input type="text" id="text2">
<input type="submit" value="Submit">
</form>
</body>
</html>
Now, i would like to retrieve the value of text1 from page1.html and text2 from page2.html. How can i go about it?
Looks like you are looking for forms. See this tutorial http://www.w3schools.com/php/php_forms.asp. Post your form data from page1.php to page2.php. On page2.html you can access them via $_POST.
Please be aware: This is not a secure example, just for showing purposes! When you want to show user generated data in your frontend, please use sanitizing and validation http://www.php.net/manual/en/filter.examples.sanitization.php.
page1.php:
<form action="page2.php" method="post">
Enter first name: <input type="text" name="firstName"><br>
<input type="submit">
</form>
page2.php
<h1>Hey <?php echo $_POST['firstName']; ?></h1>
<form action="lastpage.php" method="post">
Enter last name: <input type="text" name="lastName"><br>
<input type="hidden" name="firstName" value="<?php echo $_POST['firstName']; ?>">
<input type="submit">
</form>
lastpage.php
<h1>Yo, my mate <?php echo $_POST['firstName']; ?> <?php echo $_POST['lastName']; ?>!</h1>

Printing text box value on page in PHP

I am new to PHP (in-fact I am learning it). I am trying to get the value of textbox defined in HTML and print it on HTML page through PHP code. I am able to send the value of textbox to another page using form post and getting it using $_POST['name'] on other page.
I am not able to print the value of textbox on same page.
Here is my code:
<html>
<head>
<?php
function myfunction()
{
printf($_POST['fname']);
}
?>
</head>
<body>
Name: <input type="text" name="fname" />
<input type="button" onClick="myfunction()" value="Click" />
</body>
</html>
First of all it's not required to write php function within <head> tags. Second,
you can't POST data without <form> tags. try this
<?php
if(isset($_POST['submit']) && $_POST['submit']=='Submit'){
$name=$_POST['fname'];
echo $name;
}
else {
?>
<html>
<head>
</head>
<body>
<form method="POST" action="<?=$_SERVER["PHP_SELF"]?>">
Name: <input type="text" name="fname" />
<input type="submit" name="submit" value="Submit"/>
</form>
</body>
</html>
<?php } ?>
you can not call PHP function by button's click event...
if you want to print on same page then you can do by below code..
<html>
<?php
if(count($_POST)>0){
echo $_POST['fname'];
}
?>
<body>
<form method='post'>
Name: <input type="text" name="fname" />
<input type="submit" value="Click" />
</form>
</body>
</html>
hope you will get what you want by my answer..

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