Where condition based on two database fields - php

Question

I do have two tables which are employee and loan
When I enter loan for particular user I am picking user employee_id and loan amount.
// loan form
https://imgur.com/VH6hflw
these details stores in loan table. As well as I have stored some employees details already in employee table like account number, employee official id, userpic.
When I submitting the loan form I am getting employee unique id. I will store the employee unique id to loan field called loan_employee_id.
My problem is When I retrieve the data from the loan table I will get loan amount but some more field are needs from employee table. So I have joined with two tables which are employee and loan.
my db structure https://imgur.com/XYxGjVH
public function fetchLoan()
{
$this->db->select('*');
$this->db->from('employee');
$this->db->join('loan','employee.emp_id = loan.employee_loan_id');
$this->db->where(array('loan.employee_loan_id' => "employee.emp_id") );
$query= $this->db->get();
return $query->result_array();
}
Here where condition should match with employee_loan_id from the loan table and emp_id from employee table
How Do i join the tables with above condition, where conditions both valion getting from the database.

Answer 1

First of all, the corresponding MySQL query would be:
SELECT * -- Put field names which are required
FROM loan
INNER JOIN employee ON employee.emp_id = loan.employee_loan_id
WHERE loan.employee_loan_id = 12; -- Consider we're fetching records for emp_id = 12
Corresponding code would be:
-- Pass a parameter for employee id for which you want to get loan details.
public function fetchLoan($empId)
{
$this->db->select('*');
$this->db->from('employee');
$this->db->join('loan', 'employee.emp_id = loan.employee_loan_id');
$this->db->where('employee.emp_id', $empId);
$query = $this->db->get();
return $query->result_array();
}

Answer 2

Please pass employe_unique_id on this based data geting
public function fetchLoan($employe_unique_id)
{
$this->db->select('*');
$this->db->from('employee');
$this->db->join('loan','employee.id = loan.employee_id');
$this->db->where('employee.id',$employe_unique_id);
$query= $this->db->get();
return $query->result_array();
}