How to exclude specific selection from query - php

Question

I have this function for email checking in registration form which disables submit button if submitted email is currently in use. So I want to modify that function in profile edit section. I also have profile edit form in profile.php. So when user edits his info withouth touching email input it works fine. But once user clicks and to email field and blurs out the mouse without even editing something it shows "Email Already Taken" error. Which is fine cause function works for registeration form. So when user submits different email I want to check if it's already in db otherwise if he doesn't change anything I want to show nothing and proceed.
I've tried to solve this in back end with this query:
SELECT * FROM users WHERE email = ? AND id != ?
.
.
.
mysqli_stmt_bind_param($stmt, "ss", $email, $uid);
but it doesn't work
Then I tried SELECT * FROM users WHERE email = ?
and looped over selection to detect if there is selection with id = uid. If yes, make result variable 0. But it also doesn't work.
function profEmailCheck(){
$('#email').blur(function(){
var email = $(this).val();
var uid = $('#uid').val();
var update_email_check = '';
$.ajax({
url:'update_email_check.php',
method:"POST",
data:{
update_email_check: update_email_check,
email: email,
uid: uid
},
success:function(data)
{
if(data != 0)
{
$('.email-availability').html('<span class="text-danger">Email Already Taken</span>');
$('#update-prof-btn').attr("disabled", true);
}
else
{
if (email == '')
{
$('.email-availability').html('');
$('#update-prof-btn').attr("disabled", true);
}
else
{
$('.email-availability').html('<span class="text-success">Email Available</span>');
$('#update-prof-btn').attr("disabled", false);
}
}
}
})
});
}
<?php
include('db_connect.php');
if (isset($_POST["update_email_check"])) {
$email = mysqli_real_escape_string($conn, $_POST["email"]);
$uid = mysqli_real_escape_string($conn, $_POST["uid"]);
$sql = "SELECT * FROM users WHERE email = ? AND id != ?";
$stmt = mysqli_stmt_init($conn);
$query = mysqli_query($conn, $sql);
if (!mysqli_stmt_prepare($stmt, $sql)) {
echo "Something went wrong :(";
exit();
} else {
mysqli_stmt_bind_param($stmt, "ss", $email, $uid);
mysqli_stmt_execute($stmt);
$result = mysqli_stmt_get_result($stmt);
}
$result = mysqli_sql($conn, $sql);
while ($rows = mysqli_fetch_array($query, MYSQLI_ASSOC)){
if($rows['id'] == $uid){
$result = '0';
}
}
echo mysqli_num_rows($result);
}

Answer 1

As far as I understood you want to check email control.
If (exists){
Do something
}
else {
Do something
}
If this is what you want then you should;
$ControlMailQuery = "SELECT * FROM users WHERE email = ?";
$ControlMailQueryResult = mysqli_query($db, $ControlMailQuery);
if(mysqli_num_rows($ControlMailQueryResult) == 1){
//There is a one user who has this email
}
else{
//this is unique e-mail address
}