Finding sum of values of keys having duplicates values in php - php

Question

I'm not able to find a solution for the given scenario where I have a multidimensional array in which I have to find the sum of the values of the arrays that have same ID.
demo.php
$array = array("1"=>array("id"=>"1", "total"=>"100"),
"2"=>array("id"=>"2", "total"=>"300"),
"3"=>array("id"=>"3", "total"=>"400"),
"4"=>array("id"=>"4", "total"=>"500"),
"5"=>array("id"=>"1", "total"=>"560"));
I want to get the sum of the total of all the duplicates IDs e.g 1 is the ID and the sum of the total would be 100 + 560 = 650.

Answer 1

One option is using array_reduce to summarize the array into an associative array.
$array = //....
$result = array_reduce( $array, function( $c, $v ){
if ( !isset( $c[ $v["id"] ] ) ) $c[ $v["id"] ] = 0;
$c[ $v["id"] ] += $v["total"];
return $c;
}, array() );
$result will be:
Array
(
[1] => 660
[2] => 300
[3] => 400
[4] => 500
)
UPDATE
Add another reduce to group the array first. The second reduce is to only include the array elements with more than one count.
$array = //....
$group = array_reduce( $array, function( $c, $v ){
if ( !isset( $c[ $v["id"] ] ) ) $c[ $v["id"] ] = [ "count" => 0, "total" => 0, "id" => $v["id"] ];
$c[ $v["id"] ]["count"] += 1;
$c[ $v["id"] ]["total"] += $v["total"];
return $c;
}, array() );
$result = array_reduce( $group, function( $c, $v ){
if ( $v["count"] > 1 ) $c[ $v["id"] ] = $v["total"];
return $c;
}, array() );
This will result to:
Array
(
[1] => 660
)

Answer 2

Another take while using a foreach:
$array = array("1"=>array("id"=>"1", "total"=>"100"),
"2"=>array("id"=>"2", "total"=>"300"),
"3"=>array("id"=>"3", "total"=>"400"),
"4"=>array("id"=>"4", "total"=>"500"),
"5"=>array("id"=>"1", "total"=>"560"));
$total = [];
foreach ($array as $sub) {
$total[$sub['id']] = isset($total[$sub['id']]) ? $total[$sub['id']] += $sub['total'] : $total[$sub['id']] = $sub['total'];
}
Output
Array
(
[1] => 660
[2] => 300
[3] => 400
[4] => 500
)
Live Example
Repl
Reading Material
Ternary Operator

Answer 3

You can use simple foreach loop to get the expected result
<?php
// Your code here!
$array = array("1"=>array("id"=>"1", "total"=>"100"),
"2"=>array("id"=>"2", "total"=>"300"),
"3"=>array("id"=>"3", "total"=>"400"),
"4"=>array("id"=>"4", "total"=>"500"),
"5"=>array("id"=>"1", "total"=>"560"));
$issetArray = array();
foreach ($array as $key => $value) {
if(isset($issetArray[$value['id']]))
{
$issetArray[$value['id']]['total'] += $value['total'];
}
else
{
$issetArray[$value['id']] = array();
$issetArray[$value['id']] = $value;
}
}
$result = array();
foreach ($issetArray as $value) {
array_push($result, $value);
}
print_r($result);
?>
Example: https://paiza.io/projects/Fnay-hbk4Cuf_-rMTL5AFA

Answer 4

If you want to use the external class tableArray and you want to preserve the structure of the input array try this:
$array = array("1"=>array("id"=>"1", "total"=>"100"),
"2"=>array("id"=>"2", "total"=>"300"),
"3"=>array("id"=>"3", "total"=>"400"),
"4"=>array("id"=>"4", "total"=>"500"),
"5"=>array("id"=>"1", "total"=>"560"));
$newData = tableArray::create($array)
->filterGroupSum('total',['id'])
->fetchAll()
;
$newData:
array (
0 =>
array (
'id' => "1",
'total' => 660,
),
1 =>
array (
'id' => "2",
'total' => 300,
),
2 =>
array (
'id' => "3",
'total' => 400,
),
3 =>
array (
'id' => "4",
'total' => 500,
),
)