When opening the website, it says it cannot handle the request. Why? - php

Question

I was hoping someone could help me figure why this code is not really working.
When i enter my website (with the GET), it says the server could not handle the request.
Could someone spot any errors?
I'm new to MySQL/MySQLi and PHP as well, so i'm sorry if any part of my code sounds pretty dumb.
Thanks in advance!!!
My table has the following organization:
-------------------
id | value
-------------------
|
|
-------------------
The column 'id' is an INT and the column 'value' is a JSON.
Here's my current code inside a script called "index.php".
<?php
$database = "...";
$username = "...";
$password = "...";
$servername = "localhost";
$mysqli = new mysqli($servername, $username, $password, $database);
if ($mysqli->connect_error) {
die("Connection failed: ".$mysqli->connect_error.".");
}
header("Content-type: application/json");
function get($id) {
if ($id) {
$query = "SELECT value FROM myTable WHERE id = ?";
$statement = $mysqli->prepare($query);
$statement->bind_param("i", $id);
$statement->execute();
$statement->bind_result($result);
$statement->fetch();
$statement->close();
if ($result) {
return $result;
}
else {
return NULL;
}
}
else {
return NULL;
}
}
function set($id, $value) {
if ($id && $value) {
$filled = get($id);
if ($filled) {
$query = "UPDATE myTable SET value = ? WHERE id = ?";
$statement = $mysqli->prepare($query);
$statement->bind_param("si", $value, $id);
$statement->execute();
$statement->bind_result($result);
$statement->fetch();
$statement->close();
if ($result) {
return TRUE;
}
else {
return FALSE;
}
}
else {
$query = "INSERT INTO myTable (id, value) VALUES (?, ?)";
$statement = $mysqli->prepare($query);
$statement->bind_param("is", $id, $value);
$statement->execute();
$statement->bind_result($result);
$statement->fetch();
$statement->close();
if ($result) {
return TRUE;
}
else {
return FALSE;
}
}
}
else {
return NULL;
}
}
$method = $_SERVER["REQUEST_METHOD"];
if ($method == "GET") {
$result = get($_GET["id"]);
echo $result;
}
elseif ($method == "POST") {
$result = set($_POST["id"], $_POST["value"]);
echo $result;
}
$mysqli->close();
?>